Interpretation of SAED pattern | estimation of d-spacing & (khl) values - 29

[@ANP-]

Thank you very much Sir. Please do make more videos on Characterization to help people like us. You are a very good teacher.

[@gezahegntadesse7228]

A few people are confused about the conversion of.......1/D nm-1 into 1/r. You need to divide the 1/D values by 2. The formula for the conversion is 1/r = 1/D × (L / λ) / 2. Where: 1/D is the reciprocal space measurement in the SAED pattern. L is the camera length of the TEM. λ is the wavelength of the electron beam. The reason for dividing by 2 is that the diffraction spots in a SAED pattern correspond to the scattering vector, which is defined as: q = 2π / d. Where d is the real-space interplanar spacing. Thank you in advance

[@Hkvlogs1154]

Really Very helpful videos......... Clearly explained all things that we have to do

[@harishchandranishad6041]

Thank you for making this very informative video. I would like to thank you from the bottom of my heart. and one request is to please, kindly make one video on monocrystalline TEM SAED pattern analysis and spacing.

[@nanoworld6122]

Noted

[@hugosantos8444]

Thanks so much!! Very helpful!

[@adelal-salihy9451]

1/r = 2(1/2r) Therefore, when calculating (1/r), you should have multiplied (1/2r) x 2, but I noticed that you are dividing by 2. Can you explain that please?

[@TanvirAhmed-fh7mw]

Yes. I also noticed this.

[@inamali2729]

Why you divide 1/2r values to find 1/r values ?

[@priyankaphalswal482]

It should be multiplied by 2 not divide

[@DrHaffeast]

Can I know why the biggest radius on the small circle or inside circle. Instead of outer circle? Suppose (200) should be place at outer circle. I am new to this can you clarify.

[@mariappankaruppiah177]

How pair hkls, When more than one hkl for a calculated d spacing?

[@anishajoseph2353]

Very Informative video. Sir please put this type of analysis for all characterization methods

[@aakashhossain7993]

I do not have any access to the JCPDS card for my use !! Is there any public domain from where I can access the JCPDS file ?

[@mariappankaruppiah177]

If the d spacing lower than 1A How to identify the hkl?

[@kalpanagarg1301]

How to get the jcpds card can you provide the link of your video in comment box?

[@aryanfathoniamri956]

Thank you very much for the tutorial. Please make a video about the SAED pattern of LRTEM. There is no scale in the SAED pattern

[@juanca17063]

Thanks a lot, very well explained.! Regards from Mexico

[@Vinodpanwar94]

Please make a video on Single-crystal SAED pattern as well!

[@nanoworld6122]

Noted

[@shobhnathgupta2618]

Waiting

[@jinzhou4327]

Could you please also make a video on how to index spot diffraction pattern? Really appreciate it.

[@muhammaddanishiman1951]

hello there, do you know how to index spot diffraction pattern?

[@fayzahtalbi3348]

Many thanks. Please make a video on the Single crystal SAED pattern .

[@kavitayadav8351]

Hello sir, will you plzz make a vedio on the wemple -Didomenico for determining the non- linear refractive index

[@saharjafari2484]

thank you for the useful and complete information.

[@mani2263]

Excellent video, covered every aspect. I have one question kindly respond to clarify concept of the community. Right from the start, obtaining 1/2r, till matching d spacing you video is very coherent. However, to obtain 1/r (2nd column of the table) from 1/2r, instead of dividing it by 2 (which you did), should we not do the multiplication? i.e. 1/2r * 2 = 1/r

[@sanmilankalita9058]

Why did you divide 1/2r to find 1/r?????

[@rcfychemistry3082]

How can we interpret the HRTEM images of nanoparticles and quantum dots..? Can u explain it in hindi..?

[@rajshekhar616]

Going from 1/2r to 1/r, you should have multiplied 2 not divided 2. I do not know how you got the right answer?

[@dongmeimaylin4188]

from C column to D column , it should be 1/2r *2 = 1/r

[@nanoworld6122]

You are right, But his is not the mistake. The actual mistake is, I measured 2R but mistakenly labeled it as 1/2R in the first place and then use R instead of I/R. However, the method and calculation is accurate. But you need just to consider the 1/2R as 2R, 1/R as R.

[@sharafpc786]

@@nanoworld6122 yes.. i was wondering the same thing

[@kausarshah8903]

i need setup of xprethigh schor e may you provide me??

[@Mosesnewtechnology]

Thank you for the tutorial, the math for converting 1/2r into 1/r may not be right. I think you are supposed to multiply not divide by 2. i.e 1/2r is a smaller value than 1/r. please check, thank you for the information

[@dperea]

I think you are right, if 1/2r=n; then 1/r=2n. But then why it seems to be right when compared with the standard values in the card?

[@ashwinichavan7447]

Hi can u pls provide jcpdf of 15-0087.

[@LAURASILVANASALASCHAVEZ]

no tienes el word editable ?

[@seenaselvam3326]

Kindly provide the JCPDS No for MXene..wonderful video

[@research8540]

Sir, 1/r = 2 times of 1/2r . Then How you did the half of 1/2r for 1/r ???

[@harry-ho9ti]

Sir wht ll b d next video. Pls upload next one.

[@tariqmslihsaadalhgre9775]

Great explanation, Can I have JCPDS file for Bi2O3

[@harry-ho9ti]

Sir pls upload more tutorials. Pls upload Vesta software tutorial.

[@ahmedmalik9974]

Plz make more videos.Very less videos on this channel are.

[@КонстантинГорбунов-ы7ц]

Thank you for the informative video. Why didn't you use the formula L•lambda=R•d to find d - spacing?

[@pinakmiku4999]

Is this that you are mentioning the bragg equation?

[@solankianitaba9399]

please gave information that my XRD data match with which number JCPDS FILE NUMBER

[@RohitSharma-yp5mg]

Respected sir can you please provide me this standard values card ..???

[@lakshmikantasain5667]

Could you please provide jcpds file of reduced graphene oxide and graphitic carbon nitride

[@souravpan3068]

You are doing really nice work.

[@nanoworld6122]

Thank you! Cheers!

[@skylerxing7548]

Very brilliant video. But I am wondering if I am wrong about the 1/2r and 1/r in relative values, if anyone can tell.

[@trithien3t]

I am also think that, 1/2r=a => r= 1/2a, but in this case r is calculated reversely

[@SP-qv9ui]

1/2r is not a 1÷ (2r) its 2r in reciprocal plane

[@harry-ho9ti]

Please do a vdo on ac conductivity fitting and how to calculate the atomic positions of a sample for rietveld refinement. Pls. suggest the site.

[@nanoworld6122]

Noted

[@suranjanapatowary9524]

While indexing Miller indices in Microsoft paint, you have indexed the plane corresponding to the least r-value to the outermost circle. I am confused at this point.

[@meemalli3328]

Hi, could you please share me the terbium JCPDS data?

[@anjalisuryavanshi6971]

Hello sir can you provide jcpds card

[@MrShkolololo]

Thank for your tutorial, it was very helpfull!

[@nanoworld6122]

You are welcome!

[@vedant2136]

Nicely explained work . Thanks 🎉🎉

[@nanoworld6122]

Thanks and welcome

[@subinkc3539]

JCPDS 44-0141 ?? can u pls share the jcpds file of alpha- MnO2

[@ranjitkate8396]

Please upload the videos on d spacing calculation from HRTEM image and XPS convolution and deconvolution

[@sanchiakharphanbuh251]

Thank you for this video. Can I have JCPDS file for Mn2o3 and MnO

[@dhanyanp666]

Very useful videos, go ahead.

[@nanoworld6122]

Many many thanks

[@ahmedmalik9974]

Nano world plz make such more videos

[@uzmasubhan877]

Very helpful session

[@pratikshatanwade3781]

When saed scale is 10 1/nm then what will be the calculations and to decide that?

[@mehdikhadem2576]

just in the Image-J, Analysis>set Scale change 2 to 10. the rest of the process remains the same

[@debashissarmah6390]

Required JCPDS Card.

[@priyankadogra3258]

Thankyou sir your vdieo help me alot❤

[@fionajoylinemascarenhas5266]

Thank you very much for the video sir

[@alexandrerodriguessimoes8020]

Thank you!! God bless you!

[@dr.poojashandilya6885]

Thank you so much your video is wonderful.

[@clauberdalmas]

Excellent! Thank you

[@nanoworld6122]

You are welcome!

[@Ayu-rx3dz]

Thank u so much for your guide sir. Sir, do you have JCPDS card no. 52-0875 for Ti3AlC2?

[@nanoworld6122]

email respomded

[@Ayu-rx3dz]

@@nanoworld6122 Thank u so much sir, This really helped my research

[@gunntea9545]

Why d=1/R ?? I only know that d.R=L.landa Could you tell my why L.landa=1 ?

[@HongNguyen-mb3io]

Thank very much for your usefull video

[@anjalibaburajan2963]

Thank you soo muchh sir...can you please provide jCPDS card of Ceo2

[@dipint4913]

no

[@zahirmuhammad9133]

Great job sir

[@nanoworld6122]

Thanks

[@bharathimeti7753]

Thank you for this tutorial. Kindly give me all values for PCMO , jcpds no. is 89-795. Also for BCMO Jcpds no. is 57- 767.

[@goyenkaneelam]

How to index saed of crystalline materials

[@nanoworld6122]

This video was for polycrystalline SAED pattern. However, I will upload soon a video on the interpretation of single crystalline SAED pattern.

[@andreachan8944]

@@nanoworld6122 Thanks a lot! I am looking forward to watching your new video.

[@shobhnathgupta2618]

Thank you sir. We are eagerly waiting for this.

[@ahmadaziz5263]

Thank you. awesome!

[@nanoworld6122]

Glad you liked it!

[@simransapra823]

Awesome..Really helpful...

[@nanoworld6122]

Glad to hear that

[@nanoworld6122]

Glad to hear that

[@simransapra823]

Please make video for how to index spot pattern for HRTEM

[@rupalimurade7372]

Thank a lot sir

[@gaanak6595]

Thank you for this video

[@richasharma5993]

Thanku sir very informative video. Sir please send me the JCPDS File for ZnO

[@chetanawasthi5610]

Please provide data for JCPDS file No. 290914

[@Vinodpanwar94]

Thank you!!

[@nanoworld6122]

Welcome!

[@TheAbhi23456]

Thanks for the tutorial, it was helpful. Can you please help me in my SAED pattern through mail, I have some specific questions about it.

[@majidraza346]

Thank you sir

[@mohammedsalah1673]

Plz prof, could you send me a JCPD card of graphene oxide?

[@sanjeevip6701]

Analyse single crystal SAED pattern!!

[@nanoworld6122]

I will upload soon

[@ritikacharak9650]

Thank you.

[@asmasiddiqa8098]

thats great

[@BreakThroughBB]

Sir.. please help me to analyse .. I calculated the d spacing but due to lack of jcpds card, I couldn't do it.. will you please provide your email address?

[@nanoworld6122]

email address is available at the end of video.

[@BreakThroughBB]

@@nanoworld6122 got it sir❤️🔥

[@nirmalkundu164]

jcpds card no- 411445 for sno2

[@sukanyaguharoy2739]

What is your email ID?