IP Subnetting tutorial | How to subnet IPv4 addresses

[@jim7smith]

This is by far the best explanation of IPv4 subnetting I have seen. Well Done!

[@RichTechGuy]

Thank you!

[@n19ence]

RichTechGuy - Thank You / Master level explanation of the IPv4 Construct and how it is practically implemented. I struggled with this concept until you brought clarity. I knew that I could manage my way through Subnetting however I did not consider myself good enough to Finesse the working details as well as explain, as you did this with little effort - Kudos. I am so glad that I found and subscribed to your channel I will pick through your playlist with computer and popcorn and a drink to enjoy the learning. 🤓 Again thanks for making this topic less than a headache for all who care to watch the video.

[@sajith2702]

Your explanation was too good. Thank you so much for this video. You made subnetting so easy to understand. 🎉

[@DP-pf7ps]

Amazing video starting to get it a lot better. I'm going to watch it three more times. Thanks for this amazing content.

[@superman1234567826]

Thank you so much, you've helped me understand so much better.

[@letung932]

Wow this is a great video. Thank you so much

[@guyarp3767]

You're the best thank you so much❤

[@DominicChukwuma-ww6ow]

Please do video on 5 basic network command

[@weslynmann9702]

Awesome tool ❤

[@RichTechGuy]

Thank you!

[@DominicChukwuma-ww6ow]

Nice video

[@JasonNelson-e4u]

Thanks for this great video! I do have one question I'm struggling with: I'm using your tool and and have an ip of 115.163.109.207 and a subnet mask of 255.255.248.0. I get everything right but the broadcast IP address. The solution per all the calculators I've used including yours give 115.163.111.255 as the broadcast address. In the example in your video, you have 172.16.15.25 and subnet 255.255.240.0; The broadcast address works out as follows: Broadcast: 10101100.00010000.00001111.11111111 Broadcast Address: 172.16.15.255 Well that makes sense, the 1111 = 15. But, in the tool when the problem is an ip of 115.163.109.207 and a subnet mask of 255.255.248.0, the broadcast address portion of the third octet is 00000111. I would think 111 =7, as in the your video example, 00001111 is 15, but apparently it's 111 and I have no idea why. Can you give me any clarity? Thank you!

[@RichTechGuy]

With the following IP: 115.163.109.207 and subnet mask: 255.255.248.0 (Or 115.163.109.207/21) IP Address: 01110011.10100011.01101101.11001111 Subnet mask: 11111111.11111111.11111000.00000000 Network IP: 01110011.10100011.01101000.00000000 115.163.104.0 Broadcast IP: 01110011.10100011.01101111.11111111 115.163.111.255 The third octet is the relevant octet and the subnet mask splits it at 5 bits and 3 bits: Network 01101 | 101 Host The octet's network IP is as follows: Network 01101 | 000 Host --> (104) The octet's broadcast IP is as follows: Network 01101 | 111 Host --> (111)

[@alexunixaxwell3952]

The entire 127 range is reserved for Lookpack... A 0.0.0.0 - 126.255.255.255 / B 128.0.0.0 - 191.255.255.255

[@RichTechGuy]

I do specifically call out the 127.0.0.0/8 address space as the local loopback address later in the video (timestamp: 37:32), but that does not take it out of the Class A IP address space. The 127.0.0.0/8 range is a classful subnet based on the rules of Class A IP addresses.

[@alexunixaxwell3952]

@@RichTechGuy Yeah sorry for making you reply, I saw it later in the video. But both me and my teacher agree that it should be classless... like making A 0-126 and B 128-191, but it is what it is :))