L19.3 Differential and total cross section

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MIT OpenCourseWare

MIT OpenCourseWare

Күн бұрын

Пікірлер: 21
@gibbs-13
@gibbs-13 3 жыл бұрын
If there are 100 people explaining differential cross section, they do in 100 different ways from each other. This is one of the best explanations to me!
@jacobvandijk6525
@jacobvandijk6525 Жыл бұрын
This only means you didn't understand the other explanations. Nothing else. You (and these likers of yours) have a very subjective mind. Wake up! Teaching is about giving EVERYONE the right example to understand.
@TheCrunchyGum
@TheCrunchyGum Жыл бұрын
3:39 Finally the differential cross section is explained clearly... I have no idea why textbooks and instructors are obtuse about something so simple.
@jacobvandijk6525
@jacobvandijk6525 Жыл бұрын
@ 16:37 A STRANGE EQUATION physically. As if a change in solid angle (determined by the experimenter) would change something about the cross-section of the material in target?
@not_amanullah
@not_amanullah 4 ай бұрын
Thanks ❤️🤍
@cikif
@cikif 5 жыл бұрын
2:02 I'm finding as you -should- *shoot* in particles 3:58 an -iv- *idea* 5:39 -floods- *flux* 19:03 approximate solution -for a wave- *far away*
@not_amanullah
@not_amanullah 4 ай бұрын
This is helpful ❤️🤍
@JimmyGray
@JimmyGray 4 жыл бұрын
Great lecture. Thank you.
@abhinovenagarajan.s7237
@abhinovenagarajan.s7237 3 жыл бұрын
Given that the wave function psi is a 'leading term' solution, how do we know that the remaining terms may not contain functions that depend on (theta,phi) and hence, affect our differential cross section as well?
@scienceandstudy6431
@scienceandstudy6431 4 жыл бұрын
please explain why u took incident wave imaginary part
@onderozenc4470
@onderozenc4470 3 жыл бұрын
It is plane wave representation. Though the outgoing wave is spherical in terms of both phase and amplitude, its argument becomes suppressed in the intensity expression (complex conjugate).
@jacobvandijk6525
@jacobvandijk6525 Жыл бұрын
@@onderozenc4470 Now try to answer his question. Only the first sentence has anything to do with it.
@onderozenc4470
@onderozenc4470 3 жыл бұрын
In turkish universities, even the emeretus professors😄don't know about these representations 😝
@Shaziakhan75557
@Shaziakhan75557 4 жыл бұрын
A cmplt knowledge of the topic could be found here
@MANOJKUMAR-ev7pl
@MANOJKUMAR-ev7pl 5 жыл бұрын
At 9.12 min why he used imaginary
@parasharchatterjee3223
@parasharchatterjee3223 5 жыл бұрын
The probability current density has the formula of the type he wrote. There's another one where its (psi*)del psi - psi del (psi*), which is generally what is derived in textbooks.
@onderozenc4470
@onderozenc4470 3 жыл бұрын
Wave function multiplied by its imaginary part gives the probability density.
@zakirreshi6737
@zakirreshi6737 4 жыл бұрын
Playlist link kzbin.info/aero/PLUl4u3cNGP60Zcz8LnCDFI8RPqRhJbb4L
@scienceandstudy6431
@scienceandstudy6431 4 жыл бұрын
please explain why u took incident wave imaginary part
@Tom-iv5pw
@Tom-iv5pw 4 жыл бұрын
It is the definition of 'Probability Current'. Since the sum (or integral) over all possible states will always conserve to 1 - before and after the scattering process - what we assume is that the probability redistributes itself, like how the intermediate state between two different charge distributions would require an electric current to redistribute the conserved overall charge. A quick way to obtain this quantity is to take the time-dependent Schrdöedinger equation (Let's call this Eq.1) and its complex conjugate (Eq.2). If we multiply Eq.1 by the complex conjugate of the wave function and Eq. 2 by the wave function and subtract these expressions, we will get an expression which we can be manipulated into something very similar to a continuity equation (divergence of a vector + partial time derivative of a scalar = 0). This vector (the one that is acted upon with a divergence in the paragraph above) is the 'Incident Flux' the professor defined in this video.
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