The definition of equivalence classes is given and several properties of equivalence classes are introduced.
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@alexturk63894 жыл бұрын
this was so useful. 11 minutes saved me hours trying to decipher my textbook
@lightnightsky2 жыл бұрын
Bro you have no idea how these videos have saved me. Thank you so much! You make everything make so much sense!
@yondabigman46687 ай бұрын
fr, I thought this stuff was impossible
@ferociouswaves10 жыл бұрын
Thank you so much for this video! I now understand equivalence relations and equivalence classes! May God bless you and shower you with joy and happiness!
@learnifyable10 жыл бұрын
Thank you for the kind words!
@itjustmemyselfandi2 жыл бұрын
No matter how they know the topic, some teachers are really bad at teaching. They can't speak in the level of the students. Some of them speak like we're babies, and some of them speak like we're geniuses. However, some people can explain the things well. This person is one of them, thank you sir.
@jongallagher4719 Жыл бұрын
Legend has it someday learnifyable will return.... !
@danielstone58105 жыл бұрын
Nice! I am trying to learn Abstract Algebra on my own. I know it is ambitious, but wish me luck and keep making these vids!!!
@ibraheemkhan97737 жыл бұрын
The first example was the exact problem I had. This helped a lot, thanks!
@mathsical5 жыл бұрын
Thank you so much! I've been searching for abstract algebra videos all over youtube and your videos are literally the only ones I understand! For the last example, would you also have to look at the case where [x]=/=[y] and show they have to be disjoint?
@pramila18033 жыл бұрын
Thank you!! These are very clear step by step videos ❤️🙏
@aryankumarprasad15743 жыл бұрын
Thanks. I am into the second week into a Group theory class, and now I understood what its all about.
@geogaddi845 жыл бұрын
Great explanations. Thanks
@andreaLA2223 жыл бұрын
Thank you so much for this video! It helped me a lot!!
@utility006 жыл бұрын
Great video
@Rohitgupta09085 жыл бұрын
Awesome explanation
@ajay428226 жыл бұрын
Thanks...that helped a lot... keep posting....
@shawnkoo30995 жыл бұрын
Excellent!
@ashmitasingh70296 жыл бұрын
Thanq u so much the way u had explained by giving the example was really nice.
@gulligagardinen7 жыл бұрын
Perfect! Thank you! :)
@leilajabari59613 жыл бұрын
very useful thanks.
@Bemath_kh4 жыл бұрын
More videos please. I love your teaching ♥️♥️♥️🙏
@arnabchowhan34887 жыл бұрын
shabbash gooooood yaar
@Francesabc10 жыл бұрын
this helped a lot. thank you!
@learnifyable10 жыл бұрын
No problem! I'm glad I could help.
@kwame70032 жыл бұрын
I really appreciate it
@AkhileshKaur3 жыл бұрын
Thank you a lot for making this.
@adi-sngh4 жыл бұрын
After watching a lot of videos on this topic, I stumbled upon this video and this is the only video that was able to explain me this topic. (My textbook just confused me)
@navjotsingh22514 жыл бұрын
There’s two ways of doing math, the intuitive way ( like this video) or the textbook way, I hate textbooks and don’t really use them in my studies because the ones we get are so boring and unintuitive.
@unknown-pe1oq3 жыл бұрын
Thaks for efforts
@ianz.07 жыл бұрын
Thanks a lot. you are a life saver. found your videos at the right time. do you also have a problem set for this topic?
@pranesh0617 жыл бұрын
Nice video. What device did you use to make this great explanation?
@Ghost_of_Morisset3 ай бұрын
Thanks for this
@alisondunning24464 жыл бұрын
Thank you! At 9:17, wouldn't it have been more straightforward to start with y being an element of [x], since [x] := {y | x ~ y}, and from [x] = [y] we can just imply that y is an element [y]?
@subhashmehta78097 жыл бұрын
well done
@parkermilligan75036 жыл бұрын
You should consider private tutoring. I would pay you. I'm in my university's proofs class right now. Fun stuff! Btw, great videos.
@athira.k42914 жыл бұрын
Thank you
@sfhan9 жыл бұрын
great video, thanks!
@learnifyable9 жыл бұрын
Shufang Han I'm glad I could help.
@tmendoza65 жыл бұрын
holy hell this was great!
@DanielMak12349 жыл бұрын
is the disjunction in the very last proof an exclusive or inclusive disjunction? ([x]=[y] or [x]intersects[y]=null set) if it's an exlusive disjunction (which seems more likely), then assuming one false and proving another seems a bit counterintuitive because that seems to apply only to inclusive disjunction
@aydiology9 жыл бұрын
Man Bear Pig The phrase "either … or" generally implies an exclusive disjunction.
@edwizecorner76523 жыл бұрын
well explianed and i am curious about which software you are using to explain, can you plz name it
@theunknown42093 жыл бұрын
great hand writing. looks like you trained as an architect
@amsainju8 жыл бұрын
Thank you very much
@learnifyable8 жыл бұрын
+Arpan Man Sainju You're welcome.
@ssbsnb12008 жыл бұрын
In the iff proof could we start with x exists in [x]... therefore x~y? this would make the symmetry step unnecessary
@learnifyable8 жыл бұрын
+ssbsnb1 Yes, that would work too. A short proof made even shorter!
@danibhutta98038 жыл бұрын
Thanks Brother...
@learnifyable8 жыл бұрын
+Dani Bhutta I'm glad I could help.
@mohmd2528 жыл бұрын
equivalence classes are sets???? am I right??
@excorpse6 жыл бұрын
yes
@HaniYahya99 жыл бұрын
Why -1 is not divisible by3 but -6 is? Thanks
@latishacooper119 жыл бұрын
Because -1 divided by 3 would give you -1/3 but -3 divided by 3 would give you -3/3 = -1 same for -6/3 = -2. For a number to be divisible by another number it should not leave and remainders or result as a fraction.
@x87-646 жыл бұрын
-1 = 3*-1 + 2 Hence when -1 is divided by 3, it leaves a remainder of 2. But, -6 = 3*-2 + 0 Which means -6 / 3 doesn't leave a remainder or we can say -6 is divisible by 3.