Math Olympiad | A Beautiful Exponential Problem | EasyMaths

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[@walterwen2975]

2^a + 2^b + 2^c = 28 = 4(7) = 4(1 + 2 + 4) = 4 + 8 + 16 = 2^2 + 2^3 + 2^4 a = 2 < b = 3 < c = 4

[@NhaNguyen-cx1ri]

a+b+c=2+3+4=9

[@snarkybuttcrack]

16+8+4 pretty obvious

[@adityakhanna8822]

Binary me convert krna jyada asaan rahega (28)₁₀ = (11100)₂ = 2⁴+2³+2²

[@dubdub6638]

it's a simple, but GENIAL solution.

[@niranjanchakraborty1139]

Ans=a=2. b=3. & c= 4. (proof "2^2=4. ,2^3=8 &. 2^4=16. Now. 16+8+4=28.

[@dubdub6638]

a not equal 0 because 28 is pair if a = 1 then 2^a+2^b =26 26 = 2 x 13 no good then a =2 24 = 2 x 2 x 2 x 3 = 2^3 +16 then b = 3 16 = 2⁴ then c = 4 then

[@BhuvanRao-gj1dj]

Not equal to 0 because 0 is not +ve no,