Math Olympiad | A Beautiful Exponential Problem | VIJAY Maths

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VIJAY Maths

VIJAY Maths

Күн бұрын

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Пікірлер: 14
@walterwen2975
@walterwen2975 3 ай бұрын
Math Olympiad: √[(5⁸ + 7⁸ + 74⁴)/2] = ? Let: a = 25, b = 49; 5⁸ + 7⁸ + 74⁴ = 25⁴ + 49⁴ + (25 + 49)⁴ = a⁴ + b⁴ + (a + b)⁴ a⁴ + b⁴ + (a + b)⁴ = a⁴ + b⁴ + (a⁴ + 4a³b + 6a²b² + 4ab³ + b⁴) = 2(a⁴ + 2a³b + 3a²b² + 2ab³ + b⁴) = 2[(a⁴ + 2a²b² + b⁴) + (2a³b + 2ab³) + a²b²] = 2[(a² + b²)² + 2ab(a² + b²) + a²b²] = 2(a² + ab + b²)² √[(5⁸ + 7⁸ + 74⁴)/2] = [√2(a² + ab + b²)²/2] = a² + ab + b² = 25² + (25)(49) + 49² = 625 + 25(50 - 1) + (50 - 1)² = 625 + 1250 - 25 + 2500 - 100 + 1 = 4251
@daakudaddy5453
@daakudaddy5453 3 ай бұрын
In the end you got a^2 + b^2 + ab You could have written it as (a + b)^2 - ab = 74^2 - (25 x 49) This is much easier to calculate.
@Danieswors
@Danieswors 3 ай бұрын
4251
@ManojkantSamal
@ManojkantSamal Ай бұрын
Respected Sir, Good afternoon. I prefer the way, you make reach the problem to the end....
@vijaymaths5483
@vijaymaths5483 Ай бұрын
So nice of you ,Thanks for watching!
@lyricsssulders43
@lyricsssulders43 3 ай бұрын
👏👏👏
@pratapjadhao388
@pratapjadhao388 3 ай бұрын
Thanks sir, For the memory booster example.... . .
@ManojkantSamal
@ManojkantSamal Ай бұрын
(25)^2+(25×49)+(49)^2 625+1225+2401=4251(may be)
@crazyindianvines1472
@crazyindianvines1472 3 ай бұрын
great explanation
@ezzatabdo5027
@ezzatabdo5027 3 ай бұрын
High concentration and high flexibility by best explanation, thanks too much sir.
@prabhushettysangame6601
@prabhushettysangame6601 3 ай бұрын
One of the best example I liked 👍
@naveenkhare1979
@naveenkhare1979 3 ай бұрын
Very nice but typical problem
@vijaymaths5483
@vijaymaths5483 3 ай бұрын
Thank you ⚘️
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