Math Olympiad Exponential Problem| How to solve without a calculator??🤔🤔

How To Solve Without calculator? Exponential Problem | Math Olympiad | #olympiad #matholympiad #exponents #exponential
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[@rabotaakk-nw9nm]

2^19-2^5=2(2^18-2^4)= =2(2^9+2^2)(2^9-2^2)= =2(512+4)(512-4)= =2(500+16)(500+8)= =2(500^2+500(16+8)+16•8)= =2(250000+12000+128)= =2•262128=524256 😁

[@Jefftw2]

It's easy. 2^20=1048576 (from memory) 2^19=524288 2^19-32=524256

[@denisrenaldo3506]

Interesting, but that’s a long development. Why giving 2^7 = 128 and not giving 2^10=1024 (kilo in binary computing) or 2^20=1048576 (mega) and then 2^19= 2^20/2= 524288. Solution is easy : 524288-32=524256

[@Jefftw2]

the same with me.

[@abdulroushan0129]

You better teach cl-vii students.

[@ChaudharyFahim22]

Just did it normally only took me 3 mins

[@teerayutmaingam3770]

I think , normal solve 2^19 is faster.

[@LaunTehTakTergantung]

2^19- 2^5

[@user-xs8dj5jl2i]

2^19 - 32 = 2^20/2 - 32 = (1000+24)^2/2 - 32 (1000+24)^2 = 1 000 000 + 48 000 + (25 - 1)^2 (25 - 1)^2 = 625 - 50 + 1 = 576 (1000+24)^2 = 1 000 000 + 48 000 + 576 (1000+24)^2/2 = 500 000 + 24 000 + 288 2^19 - 32 = 2^20/2 - 32 = 500 000 + 24 000 + 288 - 32

[@walterwen2975]

Math Olympiad Exponential Problem: 2¹⁹ - 32 =? 2¹⁰ = (2⁵)² = 32² = (30 + 2)² = 900 + 120 + 4 = 1024 2²⁰ = (2¹⁰)² = (1024)² = (10³ + 24)² = 10⁶ + 48(10³) + (25 - 1)² = 1048576 2¹⁹ - 32 = 2²⁰/2 - 32 = 1048576/2 - 32 = 524288 - 32 = 524256

[@mg.mathematicalsolutions5671]

Great job 👍

[@osmanmuneer2226]

You're writing a lot of useless filler!

[@b213videoz]

Ok, so Injust know that 2²⁰ = 1 Megabyte 😁 so 2¹⁹ must be 512 KBs so 2¹⁹ - 32 = 512*1024 - 32 = 512*1000 + 512*24 - 32 = 512000 + 512*10 + 512*10 + 512*4 - 32 = 512000 + 10240 ----------------- 522240 + 2048 ------------------ 524288 - 32 ------------------- 524256 I'm a programmer not a mathematician 😋