Lesson 11 - Mesh Current Problems, Part 1 (Engineering Circuits)

[@kazimafzal]

I would love to buy your dvds but considering I am already 60K in student loans.... :/

[@azizmizrobov4058]

P=-600W

[@kabelokb902]

How did you get it?

[@roodyg5352]

@@kabelokb902 You should get 6A for iA then you multiply that by 100V to get 600W.

[@pemifo260]

You are going to write all equations for ia, ib and ic. After that, use Ax=B, then A^-1 * A * x = A^-1 * B You are going to find that, ia = 2A, ib = 2A, ic = 4A. Hope this helps!

[@Jack-gx2sx]

-600W