You are just awesome. I am reviewing for the FE and your videos are making my life a lot easier. Your students are lucky to have you as a professor.
@diaaesmail34576 жыл бұрын
you are right
@InfinityLRDL2 жыл бұрын
As a chemical engineering major, idk why we have to know this 🤷🏻♂️🤷🏻♂️🤷🏻♂️
@engineerated56279 жыл бұрын
My mind easily grasps your words!!! Appreciate your help.
@jyo33379 жыл бұрын
Hi I am student of mechanical engineering from Korea, and I really appreciate at your clear lecture!! Thank you very much.
@aimanaiman99355 жыл бұрын
THANK YOU SO MUCH. really, my lecturer isn't all that great as he likes to just skim through the material without giving explanation for why we do the way we do it. he especially skips explanation for the advanced cases like the submerged planar surface after explaining the normal vertical scenario. i have a test today so i'm sure this will help me infinitely more. so thank you randall from 4 years ago.
@BETAG05 жыл бұрын
The best freakin video ever. I was about to give up on Fluid statics but this professor saved my ass. Love u professor
@Chibuzo30008 жыл бұрын
I wish I had you as a Professor at Prairie View A&M... I've taken Fluids twice and still don't understand it at most but with your lectures so far, you've explained it very well including why we do certain process in a given example. I bet all your students exceled in your class. You are a God sent HYBRID instructor. With you and your lectures, I will succeed. Thank Remain Blessed
@randallmanteufel64118 жыл бұрын
+Datguy obi thanks for positive feedback. Can you please edit your comment and delete name of University. I hope one day you will be a successful alumni of that University. We have all had a few difficult professors, as well as some excellent ones.
@carfree1239 жыл бұрын
True.
@lampa2984 жыл бұрын
True.
@essafr38233 жыл бұрын
@@lampa298 True.
@r.a.58749 жыл бұрын
thank you for clarifying concepts that can be hard to remember so clearly. Awesome video!
@markmumiriki29796 жыл бұрын
Professor Randall ,daddy u re a legend! !!!..may God bless you abundantly I understood something that bothered me for a year!..billion thanks
@joshsimpson4228 жыл бұрын
thank you for saving me from the past several hours of misery! impressive teaching.
@mehekghosh31108 ай бұрын
You explained it so well!! Thank you!!!
@Darkarium9 жыл бұрын
Thanks. Neither google nor hours of lecture notes and past papers could explain to me center of pressure as well as you did.
@karabomohlala72573 жыл бұрын
Very thankful, u put clarity to most concepts I had trouble with
@milenelatorre17334 жыл бұрын
your lecture was clear and straight to the point. thank you. I am studying for my PE in Texas.
@ahamadromen8 жыл бұрын
It is Very helpful. Thank you very much Professor Randall.
@riasatmorshedkhan73276 жыл бұрын
Professor Randall, I really don't how to tell you that you're awesome. Way Too Awesome! Just Loved the lecture!
@randallmanteufel64116 жыл бұрын
I'm glad you find the video helpful. Best wishes in all your studies.
@Animals-Kingdom20242 жыл бұрын
Very informative. Thank you
@musakazem29982 жыл бұрын
Gordon Ramsey if he taught Fluid Mechanics.
@astafzciba9 жыл бұрын
thank you very much i have a test tomorrow in aerodynamics and this really helped
@muhittinselcukgoksu13278 жыл бұрын
Thank you soo much, also your video lessons are wonderful for PHD students like me.
@christyjiang6124 жыл бұрын
Hi, lecturer,do you know how to solve the question?thank you 60 cubic metres of oil (RD=0.93) is poured into the tank. Calculate (e) The depth of oil in the tank (2 marks) 60m³ of oil RD=0.93 (f) The pressure at the oil-water interface. (2 marks) (g) The pressure on the bottom of the tank. (2 marks) (h) The total force in magnitude and position acting on the 6.0 m side. (10 marks) (i) Draw and label a diagram to show the variation in pressure on the 6.0 m side of the tank after the addition of the oil. (2 marks)
@RizkyYozia8 жыл бұрын
Hello Prof. Randall. At the 7:13, why you use (1/3).h from the bottom on the calculation? Why not at the centre of the red square?
@KLCII886 жыл бұрын
There is a distributed force acting on the wall. You can represent this as a single force acting (1/3)h from the bottom.
@flyingfoxes14 жыл бұрын
Thanks for helping. Just a Question please. So what area dimensions do I use for calculating the Force on the vertical side? This is at about 11 minutes from start. Is it the width x 2/3h (Cp), width x 1/3h, width x h/2 or width x h?
@kellycooley21443 жыл бұрын
Whos hibler for the book ?! sorry I just want to know how to spell the name so I can find it
@randallmanteufel64113 жыл бұрын
Hibbeler
@Dianabanda9022 жыл бұрын
Thanks me too I was looking for the same book
@coolbombe2 жыл бұрын
In the first problem, why is it assumed the circular surface sinks to a depth of h1? Could it not float?
@glukeglacier Жыл бұрын
Wow, this is good
@afandimohamad6769 жыл бұрын
can you solve this to me? You are a team of design group, involve in designing a flood prevention system of a river. Your assignment is to propose the best position of the water gate hinge so that during heavy raining, when water level reaches 10 m from river bottom the water gate will open automatically. The water gate size is 3 m wide and 9 m high.
@franck-paulinpehnmayo71488 жыл бұрын
such a saviour! 👍. Thank you
@jackhooper28399 жыл бұрын
cheers for the video, very clear explanations
@lopalapz43602 жыл бұрын
Thankyouverymuch
@jzwillows8 жыл бұрын
So regardless of the weight of water above the surface (for instance it could be in a container 1 square foot at bottom but narrowing from the bottom) if a waterproof weighing scale were placed on the surface it would register the computed pressure rather than actual weight of water in the container. For instance, a container with 10 feet depth of water, 1 square feet of area at the bottom, but holds only 5 pounds of water would register on the weighing scale 624 (62.4 x 10) pounds of water rather than 5 pounds. Right?
@randallmanteufel64118 жыл бұрын
+john zimmerman pressure of water at bottom of container is not the same as "pressure" or "Force/Area" between container and scale. Force between container and scale must equal weight of container and weight of fluid in container. Sorry if this doesn't help. But that is all the time I have to try and answer your question.
@jzwillows8 жыл бұрын
+Randall Manteufel Thank you for responding. However, you misunderstand because I was not real clear. I try again. It will be simpler to reword my question using containers. Consider a container in the shape of a cylinder 10 feet depth of water, 1 square foot horizontal area. A weigh scale is placed inside the container at the bottom. One would think it would register the weight of the liquid, 624 pounds,. because that is the weight of water. But actually what the scale registers is not a function of the weight of water but the force from the water which is a function of pressure not weight, though in this example the resultant force is the same. Now take a container, 1 square foot at the bottom but that narrows and it holds 10 feet of water. Lets say it holds only 5 pounds of water. What would a scale inside the container resting on the bottom, supporting the entire liquid register 5 pounds (the weight of the water) or 624 pounds according to the formula F = 62.4lb/cu ft x 10ft x 1 sq ft? (answer is 624 pounds - right?)
@davidkapuku48717 жыл бұрын
Quick question. On the problem (38min-45min), Shouldn't that free body diagram have a normal force where the stop is? I know that since the only equation you used here was the moment equation, vertical forces do not contribute for this case, but then if we had to solve for Ay we would have to use the 'sum of vertical forces equal zero' equation and the numbers will be different if we put the normal force.
@randallmanteufel64117 жыл бұрын
at 40:00 horizontal force Fs is shown. the gate is assumed to "hang" from hinge at A. So don't need vertical force acting on bottom of gate. Could the gate rest on the ground? Yes. If it did rest on the ground, would there be vertical force at bottom? Yes.
@coolbombe2 жыл бұрын
What???? height of equilateral triangle with side b is Sqrt.3/2xb, that makes the area bsquared/4xsquare root 3. "base is equal to the height" how so??????
@KingOvSparta9 жыл бұрын
Clear explaination! Thank you sir
@ncgallagher6 жыл бұрын
your formula for the area of an equilateral triangle is wrong
@ConceptualCalculus3 жыл бұрын
He calls it equilateral, but labels it as if the "height" (measured at right angles to the vertical side) is equal to the length of the vertical side. If that's the case, then the triangle is not equilateral. His area formula is wrong for equilateral, but correct for the way he labeled the triangle.
@Verifierabfi5 жыл бұрын
Thanks to you I will pass the exam I have today !
@chamikaonyt3 жыл бұрын
Thank you sir
@TopAhmed17 жыл бұрын
THANKS A LOT.
@pubudunuwan17513 жыл бұрын
Thanks a lot ❤️sir
@RaunySilva5 жыл бұрын
Thanks, it might be useful for me
@jffoz110 жыл бұрын
You said in the explanation that the triangle was EQUILATERAL, yet from the way of explanation and drawing, I think you mean Isosceles.
@randallmanteufel641110 жыл бұрын
jffoz1 you are correct. thanks
@okeponglkr45486 жыл бұрын
Good job sir. Very helpful!!
@SageBaka9 жыл бұрын
why is it that when calculating the weight of cylinder, the depth used is 5ft? And area of cylinder isn't pi*r^2 but 2ft*5ft?
@randallmanteufel64119 жыл бұрын
+SageAdam length of cylinder in third dimension (not shown) is 5 ft. Hope that helps with second question as well..
@astafzciba9 жыл бұрын
+Randall Manteufel isn't it eg(h^2/2)
@Skull12o129 жыл бұрын
So helpful! Thanks!
@ossama32498 жыл бұрын
great explaine thank pro
@hasnaouimohamed57726 жыл бұрын
thank you
@dimitridobroskok23549 жыл бұрын
Does the method used during the last part of the vidoe work for plane surfaces instead on curved surfaces?
@randallmanteufel64119 жыл бұрын
+Dimitri Dobroskok yes, I see no reason it wouldn't work.
@dimitridobroskok23549 жыл бұрын
Thank You!
@mohamedelhadi99536 жыл бұрын
thank you so much sir
@nurfazlinbintijahipin45688 жыл бұрын
thank you sir for the explanation ! :D
@prakharmishra37267 жыл бұрын
please please reply sir at 4:22 resultant force cant be applied a little bit to the left because resultant force acts through the centroid of pressure prism and it is exactly at ( b/2 ) .
@randallmanteufel64117 жыл бұрын
discussion is confusing at this point, sorry. An equilateral triangle is drawn and incorrectly I say it is isosceles (or at least imply it is isosceles). If length of each side of equilateral is "b" then distance from middle of edge to opposite corner is "b*sin(60)" (not b as I think I say). Centroid is at (1/3) of this distance, measured from each side toward the opposite corner. To help see this, draw equilateral triangle, then 3 lines from middle of each edge to opposite corner. All 3 lines will intersect at centroid. With ruler you can verify this is (1/3) from middle of "base" to "peak"
@prakharmishra37267 жыл бұрын
Sir irrespective of isosceles or equilateral triangle the centre of pressure must lie on the centre of pressure prism and in this case it will be exactly at ( b /2 ) because we have a horizontal surface.
@prakharmishra37267 жыл бұрын
And it shouldnt be at centroid of cross section as you have mentioned..please correct me if i am wrong sir
@cebanihlabisa92157 жыл бұрын
There is a genius busy answering all these question that i dont know
@Fahad15_4 жыл бұрын
Guys pressure prisms are important for the fe exam.
@muhammadnsubuga4 жыл бұрын
It helped
@devonm3015 жыл бұрын
2:09 pi*d/4 or pi(d/2)^2
@sulemanarshad22226 жыл бұрын
legend
@johne55166 жыл бұрын
STRAIGHT LEGENNNNNDDDDDDDDDDDDDD
@BODYBUILDERS_AGAINST_FEMINISM3 жыл бұрын
at 11:00 "no it dont! thats why im here watching this video!!!" says my study group
@ezrapotter46314 жыл бұрын
1:06:43 somehow I got sqrt(9092^2+8736^2)=12,608.8 lb
@THEmanINtheVAN214 жыл бұрын
I'm trying to think of something I wouldn't do for you to be my professor. So far no luck.
@brentlackey831623 күн бұрын
H not equal b remember pythagoris
@parkedavendiaz26714 жыл бұрын
The answer of your letter a. is wrong professor you equate the wrong value of the FRH
@sunisshiningiceisslippery5 жыл бұрын
17:48 What was that? A yawn?
@puckbucky.55455 жыл бұрын
İ was confused 🙋♂️
@lampa2984 жыл бұрын
And now?
@yilmazucar5 жыл бұрын
hay bin kunduz
5 жыл бұрын
Keşke Türkçe olsaydı.
@xxSheldonBazingaxx5 жыл бұрын
Keske degil mi? Sanirim ders kaydi bu..
@puckbucky.55455 жыл бұрын
"Not too innovative"...
@engineerated56279 жыл бұрын
My mind easily grasps your words!!! Appreciate your help.