Does it make any difference if the equilibrium is stable or unstable? Thanks.
@sesangse3 жыл бұрын
Simple & good~!!
@MichelvanBiezen3 жыл бұрын
Thanks.
@stephencolumbus85667 ай бұрын
Very well said,i finally understood it but sir i have a question. Cant we just use Kinetic energy-Work theorem? I think that its the same with the virtual work and easier to apply. Am i correct? Thank you,keep up the good work
@mathiasb77705 ай бұрын
Hamilton’s principle may also be used and in my opinion/taste is more elegant than the principle of virtual work, besides it yields both equations of motions and natural boundary conditions However, Hamilton’s principle needs a conservative system (you need potentials and self-adjoint operators). Virtual work (and d’Alambert) principle does not need that. It needs however a knowledge of the equations of motions in order to be derived, whereas Hamilton’s principle yields them. The weak form of the equations of motion often is the same, and it is for conservative systems, but it needs not to be.