Mechanics of Materials: Lesson 18 - Axial Elongation Example Problem, Displacement

[@bradvincent2586]

Thank you for the great video! I believe the last calculation adds the displacement at E and the stretch of EB. It should be .0016858+.03161=.0332858, slightly different from video

[@j2393T]

0.0332958* (;

[@michell9328]

So practically the displacement of B its the same of E??

[@SS-pn7ss]

This is presented so beautifully, thank you so much! God bless you.

[@Darius-us4tw]

The displacement for B is 0.03161+0.0016858=0.0332958, not 0.033468.

[@michell9328]

Now im wondering it the displacement of B and E are equal

[@user-fl8un5iy2g]

Thank you for this excellent explanation. You're better than my college teacher.

[@ardajakuzi2081]

dude every online lecturer is better than your college teacher, c'mon you study in an arabic country.

[@arturboras6615]

the nek is professionally perfect

[@drew3494]

Would the weight of the members be relevant in a real-world application or are they small enough that they are negligible?

[@manuboker1]

Wonderful Lectures ! Thanks.

[@momomona7833]

Love you, 😍💜

[@ashar1122]

Isn't y the change in height of eb? so isnt it the same as δeb? why are the values for δeb and y different?

[@dagsilryancristianp.bsee-3879]

To find the Y which is the displacement of E. I think you forgot sir to convert the 8 ft and 2 ft to inches. Because the results of delta's EB and CF are in inches. But you've use 10' and 2' for the similar triangle.

[@kennyyetter5718]

It wouldn't matter because he's only doing a ratio; 10 feet is to .008429 inches (change in position of c) as 2 feet is to y inches (change in position of e.) The equation is y=(1/5)*.008429 whether or not he converts those lengths to inches before evaluating for y.

[@amolsandbhor]

for calculation 12.5 mm radius should converted into inches 0.4921 inch= 12.5mm

[@a_cool_raccoon]

Shouldn't the members FC & BE be in compression? Just a little confused on why they are stretching.

[@zimcarbone]

If you remove link FC beam DC would move down so FC must be holding it up, i.e. tension. Same with link BE.

[@mwenge6355]

Why are we adding displacement of e and the stretch of the member to find displacement of b? And what's the difference between the stretching of a member and a point? Someone please respond quick. My exam is tomorrow😭😭

[@christymatta]

did you find out? i have that same question

[@Shoom-wt]

Might be a tad late but pretty sure it’s because the displacement of E is not accounted for in the elongation of tension EB, basically you have a bar which is tilted down prior and on top of that is a stretch of the tension, look at it in a sequence, CF elongates and points C and E go down, after they’re down, the tension in BE elongates from the 2.5 kips on the bottom causing point B to go even further on top of what E was displaced. lmk if this helps I yapped a lil

[@matthewpeura9949]

why did you add together the A and B at the end for the last displacement