✅ Mental Math For Pilots | Easy Math Hacks Every Pilot Must Know

[@toddcianciulli921]

The crosswind math is genius as is the crab angle. Thank you very much for that.

[@ATPLStudent]

You're welcome I am glad you've found it helpful

[@jacmwo9865]

I come your channel and it's very educative and easy to understand as i will be joining PPL classes in 5 months time from now,i thumb you up mate👍🏼!.Great work.

[@ATPLStudent]

Thanks and welcome

[@Lecichipsinc]

Do it

[@FA18Training]

At time 4min55, for me, TOD = ((Current Altitude -Target Altitude)/100)/desired angle of descent = ((Current Altitude -Target Altitude)/100)/3. In example time 5m42, my calcul is: TOD= ((5500-1500)/100)/3 = (4000/100)/3 = 40/3 = 13Na If we choice an angle of descent 5° TOD= ((5500-1500)/100)/5 = (4000/100)/5 = 40/5 = 8Na

[@fitrafi7645]

Please do a similar version of admission test for emirates cadeT pilot training. Syllabus to cover, what maths and physics topic should we practice, what type of physics and maths can we expect during the training etc.

[@yuvrajsharma1149]

Hey , do u know what to prepare for emirates pilot cadet assessment, as I am abt to go for it , pls

[@cherrysoulmate6690]

@@yuvrajsharma1149 have you taken the assessment yet?

[@IzlaNiya_]

​@@yuvrajsharma1149did you join?

[@Cosme422]

My suggestion is to please use a microphone so that the audio can have good quality. It’s a lot of noise.

[@ATPLStudent]

Thank you for your suggestion

[@nikolamalakov8721]

Captain I have a question regarding the XWC. What if I encounter the situation of a tail wind. And it is above 90 degrees diference. Example: HDG 290 Wind from 170/20 290-170= 120 degrees difference 180-120= 60 degrees With the graph you provided 60 deg is WIND -1 so: XWC = 20-1 = 19 WCA = 8 degrees to the left HDG CORRECTED 288 degrees Is this simplification correct?

[@alejordann2fly411]

Gran Tip de video , me ayudo bastante en ejercicios de GNAV

[@danielndala4598]

I'm new but already fall in love with my first video on channel really thank you💞💞

[@ATPLStudent]

You’re welcome 😊

[@1Mr.Legend1]

3:50 290-220=70 70*15=1050 1050/tas(100)= 10.5 degrees to wind.

[@FitXhub]

Can you do another video on mental math on Hold/fuel calculations ? As well as more examples from this video please

[@ATPLStudent]

Sounds like a good idea, thank you for your suggestion will consider it.

[@FitXhub]

@@ATPLStudent thank you. Please soon!!

[@Mashaorasethaba]

I learned so much

[@VinceCartierBeats]

Why did you mulipl GS*5 for rate of descent. Just trying to get an understanding of where you got the 5 from and not any other number?

[@ATPLStudent]

It's a rule of thumbs for easy mental math. it comes from the glide path in percent 3 degree glide path = 5.2% so it is actually GS x 5.2 but we drop the 0.2. If you want to go deeper of where it comes, you will find out that it comes a result of basic trigonometry

[@VinceCartierBeats]

@@ATPLStudent thank you man!

[@Zfx13]

The DME ARC rule can be used for NBD arcs as well?

[@ATPLStudent]

Of course it can, provided you know the radius of the arc (how far away the arc from the NDB) if it’s about 13/14/15/16 miles then you may use the rule of thumb as explained in the above video.

[@dusitthehto1946]

This is helpful thanks!

[@ATPLStudent]

You're very welcome mate

[@dsd-downshiftdave8056]

Did I miss something how did you get FL260- FL110= 15000ft- isn't cruise altitude 5500 minus target altitude 1500 would be 4000 Which would make rate of decent 4000/10= 400

[@ATPLStudent]

I think you are confusing two examples with each other. FL260 is 26000 and FL110 is 11000. So, 26000 - 11000 = 15000 Got it ?

[@dsd-downshiftdave8056]

​@@ATPLStudent I must have missed that somewhere- at what part of the video is that

[@jhonatan64184]

Excelente video!!!! Muchas gracias 🙏

[@ATPLStudent]

De nada amigo

[@bruno84]

How can you assume the WCA is half of the crosswind component without taking into account your airspeed? Your example would only apply if your were flying at 120kts. Any other speed and you'd have to apply a different w.c.a..

[@ATPLStudent]

You are right, that is why I mentioned that that method is applicable mostly for General Aviation and single engine low performance aircraft where the TAS is about 100 to 130 kts

[@bruno84]

I didn't see you mentioning it. That's why I commented so that people wouldn't think it would be always half the crosswind coponent. Anyway one easy rule to calculate your w.c.a. with any aircraft and speed is to divide the crosswind component by your speed in Nautical Miles per Minute. E.g. 120kt = 2nm/min. Given a 20kt crosswind: 20/2 = 10 degree w.c.a. 300kt (5nm/min) 20/5 = 4 degree w.c.a. Easy to apply to any speed. Still, thanks for the video!

[@ATPLStudent]

@@bruno84 Thank you for your comment as well as for the trick, I learned something today. Much appreciated

[@koller8930]

I can do fourier and laplace tranform with pen and paper But I can't do 84*24 in my head in under 30sec .... :/

[@AaronWbirdman]

Great!

[@louditalian1962]

Once you get the hang of it is easy.

[@isaiah732]

For real, once you write main takeaways, and breakdown the formulas(which he’s already done) it’s very easy

[@FitXhub]

Why do you divide by 4 on the DME arc ?

[@ATPLStudent]

Because of the 1 in 60 rule. For a 60 NM DME Arc each degree is1 min 30 NM DME Arc each degree is 30 sec 15 NM DME Arc each degree is 15 sec and since this calculation is merely a rule of thumb we consider 12/13/14 all as 15NM DME Arc. because of 15 seconds is 1/4 of a minute we multiply by 1/4 or simply divide by 4 the difference in radials. Hope this has clarified your doubt

[@vaishnavraj5205]

superb sir thank you sir

[@ATPLStudent]

All the best

[@mrsumeetsaxena]

Good One !

[@ATPLStudent]

Thank you

[@ihorkohut7290]

Cool tips, thanks!

[@ATPLStudent]

No problem!

[@donolsen6141]

Are calculators allowed when factors like sinus come in play? And are basic calculators there in the interviews, or is it purely mental! Thanks for the vid btw!

[@ATPLStudent]

You hardly ever get to use sin and cos in flight, there are many rules if thumb for most of the calculations needed in flight, so don’t worry about that. As for ground school especially in Gnav and Mass and balance you are allowed to use a calculator. In interviews they only expect you to know rules of thumb and 1 in 60 rule and other very basic mental calculations just like the ones demonstrated in the video above.

[@donolsen6141]

@@ATPLStudent Thank you very Much!

[@USA2041]

My dear are there another formula for arc distance anyway 🙋‍♂️🙏

[@ATPLStudent]

Thanks for watching buddy, I'm afraid the 1 in 60 rule is the best Rule of Thumb to find ARC distances

[@tsunghanlee9044]

GIVEN: True course : 105 degree , True heading : 085 degree , True airspeed : 95 kts , Groundspeed : 87 kts. Determine the wind direction and speed. (A)020 degree and 32 knots. (B)030 degree and 38 knots. (C)200 degree and 32 knots. According to u video the answer should be (B) but the answer is A why?

[@richievaldez3607]

105-085= 20 degrees 95-87= 8kts crosswind According to table, 20 degrees is closer to 15 degrees off track = 1/4 of wind speed so: 8x4= 32kts wind speed So answer (A) is correct.

[@1Mr.Legend1]

5:33 Your calculation does not match exactly. This is correct; 5500-1500=4000ft GS120KTS 120kts/60h=2nm path per munite 4000ft/600fpm=6,66 minute (descends in 6.66 minutes with 600fpm) 6,66*2= 13,32nm. (it make progress 13.32 nm in 6,66 minutes at 120 kts.)

[@ATPLStudent]

You are using two different methods at the same time. you wont get the correct answer that way. I see the point you're trying to make here but that method of your corresponds to high altitude/high performance aircraft where during the descent the GS changes. if you are looking for Propeller/Low Altitude operations stick to the method in the video it's pretty accurate to manage your VNAV profile/TOD. thanks for your comment

[@1Mr.Legend1]

No, I just calculated it on 120 kts. The process changes if we take wind into calculate. You shared a method without taking the wind into calculate, but it was not exactly correct.@@ATPLStudent

[@hermitamrat143]

Easyyy

[@barryfitzgerald3839]

Not exactly a mathematician

[@ATPLStudent]

thanks for watching