Method to Calculate Continuous Convolution

[@TutorialsPoint_]

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[@cameronfagan3656]

Your awesome. You have no idea how long I stressed about this convolution material. Thanks for this.

[@thenewjew]

The Best ever Method. God Bless you and thank you.

[@trippdavis7538]

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[@abramnehemiah782]

@Tripp Davis definitely, I've been using InstaFlixxer for years myself :D

[@beasthunt]

You are utterly amazing.

[@sharonsharon5453]

Thanks a lot mam. This is very much beneficial and God bless you

[@g.krithikavarshini8412]

Another method to calculate convolution is t^2. 2t. 1 t^2. 3t. 4 Multiply first row with each element by 2nd row each element just like 3t(t^2+2t+1) and lastly add them you'll get same

[@c.danielpremkumar8495]

Is this not simple algebraic multiplication of the two signals ? What is the difference bet multplication and convolution?

[@MathsJoseFuentes]

I never done convolution that way, it interesting that I used the foil method and got the same thing.

[@p.gaurav.n.m2417]

What is the difference mam .... U have just multiplied those two functions.... Result is coming same only....

[@suryakumararun5761]

Brother it's one year now do you have the answer...if you have please provide the answer it would be helpful 🙏

[@sushantaadhikari5929]

@@suryakumararun5761 brother its one year now , do you get answer about this????

[@suryakumararun5761]

@@sushantaadhikari5929 naah I changed my field of study 😂😂 But I believe convolution of two signals does not leads to signal loss where as multiplication does..... I mean there are some questions where convolution of two signal is not equal to multiplication of two signals. But you are only going to deal with polynomial kind of questions and there multiplication of two signals just works fine Hope it's sufficient! I believe you are in second year electronics student?

[@sushantaadhikari5929]

@@suryakumararun5761 haha , no brother , 4th year engineering student from nepal🇳🇵🇳🇵🚩🚩 , its my back paper

[@lakshminathyt2843]

@@sushantaadhikari5929 brother its about a year now do you get the answer about this???

[@krishnakumar1714]

Best method to cal convolution.... Thanks mam😊😊

[@muhammadibrahimsadiq207]

bestem best method. love from pakistan

[@rob651]

Thank you. Isn't it just the multiplication of two polynomials? x(t).y(t) also gives the same result.

[@priyanshiyadav1411]

you are bestttttt mam

[@suryakumararun5761]

Ma'am can you please explain the difference, I mean you just multiplied those 2 signals...then what's convultion?

[@AkEntertainment47]

👍👌this method is good

[@rishabhtiwari3545]

thank you so much...

[@RituSingh-vb3rs]

Very nice

[@tarpanbhattacharya4434]

Why aren't we multiplying this? It is same as multiplication...

[@syukrimusa]

thx

[@balajibaheti8577]

is this multiplication or convolution????????? please reply on the doubt of your students!

[@sudhanshyelishetty3094]

Does this work for transcendental continuous functions?

[@sachintiwari1959]

Great

[@Crusader2]

madam, please make a video on integral method

[@mayankpal9729]

Ha mem

[@darmasta]

this is very good i wish you were my teacher wink wink lol

[@siddsuhel1231]

no need to draw these boxes, directkly mulitply every term with every term simple mulitplicatin

[@mayankpal9729]

Mem. t^2-2t-1 Hoga to

[@shubhamsemwal2225]

sign leke chlenge

[@nikoszervo]

I'm pretty shocked that no one on the internet knows how to calculate convolution algebraically by just doing the integration. You just need to express your signals in terms of the unit step function do some algebra and bring the whole thing in a special form where you can break the integral into 2 parts (almost like integration by parts).

[@alexdiallo304]

Hello, Do you have a video for me where I can watch that ?

[@ifazahamed2212]

this method is wrong