Geometry - Ch. 5: Triangle (23 of TBD) Find Angle BCD=?

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Michel van Biezen

Michel van Biezen

Күн бұрын

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Given an interesting “shape” and 2 angles in the “shape.” We will find angle BDC=?
Previous video in this series on KZbin: • Geometry - Ch. 5: Tria...
Or title seach on other platforms: Geometry - Ch. 5: Triangle (21 of TBD) Show Triangle PTS = Triangle RTQ
Next video in this series on KZbin: • Geometry - Ch. 5: Tria...
Or title search on other platforms: Geometry - Ch. 5: Triangle (24 of TBD) Find x=? y=?

Пікірлер: 8
@nielsheirbaut
@nielsheirbaut 4 ай бұрын
Why not just consider triangle BDC and since you know angle B and C do D = 180 - 30 - 45 = 105?
@MichelvanBiezen
@MichelvanBiezen 4 ай бұрын
There are often multiple ways to solve a problem.
@Znxjsjnsdn
@Znxjsjnsdn 4 ай бұрын
Professor does the sidereal year have to do with the earth crossing the equator?
@Znxjsjnsdn
@Znxjsjnsdn 4 ай бұрын
Professor how do you know the sidereal year accounts for precession and tropical doesn’t? What’s does that mean?
@Znxjsjnsdn
@Znxjsjnsdn 4 ай бұрын
Professor what is precession of the equinoxes?
@danlake7970
@danlake7970 4 ай бұрын
Typo in video title asks about BCD but it's a given (30°) so I clicked to see what I missed.
@simpleman283
@simpleman283 4 ай бұрын
Yes, these are fun. lil brain teasers I call them.
@MichelvanBiezen
@MichelvanBiezen 4 ай бұрын
Learning is fun and good for your brain!
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