5. Charge Separation, Part I: Diode

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MIT OpenCourseWare

MIT OpenCourseWare

Күн бұрын

Пікірлер: 23
@DDDelgado
@DDDelgado 5 жыл бұрын
51:43 I think prof Gang Chen at MIT 2.57 playlist calls it electrochemical potential. But probably it could be used interchangeablly.
@DDDelgado
@DDDelgado 5 жыл бұрын
57:14 how doping affects the voltage of the PV, this is important for electrolysis applications where one needs to match the voltage so that a reaction can happen.
@yahdi
@yahdi 6 жыл бұрын
Thanks MIT, thanks professor
@DDDelgado
@DDDelgado 5 жыл бұрын
28:00 shouldnt the electric field sign be related to charge, so you would have negative and positive electric fields?, or you were referring to magnitude of the electric field?.
@DDDelgado
@DDDelgado 5 жыл бұрын
never mind, he later mentions that these diagrams are for electrons only
@steveq34
@steveq34 10 жыл бұрын
Why doesn't closing the circuit in the unbiased case essentially create a "second" p-n junction? It seems symmetrical to me, just as if it were a toroidal structure with two junctions for charges to move across... (???)
@AnonYmous-hg7cm
@AnonYmous-hg7cm 9 жыл бұрын
+steveq34 I think (not sure) that the rest of the circuit doesn't contain p-n materials (instead, you have a conductor) and that breaks the symmetry.
@michaelmcneil4168
@michaelmcneil4168 6 жыл бұрын
What is happening at : kzbin.info/www/bejne/q33Fopt_pZiUnsU is that the criticality point reached allows slipstreaming to take over from turbulent flow. It can this be guided. Because it is not generally fine tuned, it will appear to be random. Regard Tesla's words as the key: frequency frequency frequency. en.wikipedia.org/wiki/Frequency
@neurosync_x
@neurosync_x 6 жыл бұрын
In forward bias, what happens if the voltage applied (Va) is greater than the voltage of depletion region (psi)?
@mallakbasheersyed1859
@mallakbasheersyed1859 4 жыл бұрын
Same doubt??? Did u come to know the answer now? Explain
@kyungryulha8478
@kyungryulha8478 3 жыл бұрын
In that case, current will increase more exponentially.
@seeker8028
@seeker8028 8 жыл бұрын
Why can we not able to measure the cut-in voltage of diode by a voltmeter.?
@vipulsharma4945
@vipulsharma4945 8 жыл бұрын
Because that voltage is due to immobile charges.
@bismark5809
@bismark5809 7 жыл бұрын
you can not just throw in any definition without knowing the rudimentary of anything
@shubhamx64
@shubhamx64 8 жыл бұрын
can someone help me with finding the "chess board example"?
@govorilegko
@govorilegko 7 жыл бұрын
the same question Joe is really a nice guy
@michaelmcneil4168
@michaelmcneil4168 6 жыл бұрын
I am not sure I understand the question.
@kabandajamir9844
@kabandajamir9844 2 жыл бұрын
So nice
@clashofclanslovers4598
@clashofclanslovers4598 6 жыл бұрын
Sir at 21min u said boron has 1 less proton than silicon in its nucleus But boron has 5 proton and silicon has 14 proton in its nucleus So how boron has 1 proton less than silicon Plsease help me out
@pranshunigam5991
@pranshunigam5991 6 жыл бұрын
He is talking about the outermost shell.
@zolandia5262
@zolandia5262 Жыл бұрын
It's not one less proton with Boron just fewer protons. B is in the same group as Al which has one less proton than Si. B and Al both have one electron in their highest p orbital (2p for B and 3p for Al), so both can be used as p-dopants for Si which has a 3p2 configuration.
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