4 HEAT AND WORK CALCULATION | THERMODYNAMICS | IIT ADVANCED | JEE MAIN | CHEMISTRY CLASS 11

[@phi4387]

If someone frm class 11 or didnt study themodynamics(physics kaa) before....u can remember cp cv value easily.. Cv=f/2*R Cp=f+2/2*R Here f is .....For Mono;Di;Tri 3;5;6 respectively

[@Vivi00875]

Thanks!

[@surajgavariya6137]

Ya

[@arpitverma6745]

thanks easily yaad hogyi values

[@11thWasteHogyaYaar]

bhai pls brackets daalde to avoid confusion

[@dipanshugarg4483]

diatomic -> 5 (linear) diatomic-> 6 (non linear)

[@asishbauri7433]

At 17:28 it will be "for n moles" not one mole sir wrote by mistake

[@kamalsharma9283]

yes

[@funforever6642]

Rytt

[@krishnaharsha2654]

was thinking the same

[@pranavpendyala5632]

@@krishnaharsha2654 Yeah

[@hitsehpatel5071]

Are this videos good for Jee Advanced? Which book should o do for physical chem..? Plzz tell

[@ItsgojoLa]

Video 4 completed Summary: Modes of transfer of energy: Work: Pv work- due to volume change Non pv work-electrical work Very very imp:work done on system compression= +ve Work done by the system=-ve Heat given to the system=+ve Heat taken from system=-ve You can directly use formula work done=p × delta v(if the pressure is constant) If the pressure is not constant then integrate it --->if it's isochoric process work done is 0 because volume is constant and obviously the formula is p×delta v so entire thing will go 0. Qp=CpV(delta)T Qv=CvV(delta)T Formulas: Degree of freedom for monoatomic--> 3 Diatomic--->5 Polyatomic-->6 Cv=f/2R Cp=f/2+1R Cp-Cv=R Y=Cp/Cv

[@trashbarbarian5231]

Thank you for your service bro

[@ArRt1719]

2:26 4:44 6:53 9:14 11:02 13:09 14:45 16:35 18:15 18:51 22:49 24:41 27:05 22:13 to 22:52 24:50 to 25:13 28:57 30:56 31:55

[@Thesufferguy]

Abe tu pagal he khya

[@D7XTE7]

I love sir along with his methodology of teaching . Though some may feel pressurized by his emphasis on intensive note making , I believe that this method helps in better retention .

[@ebinsunnyvarghese5165]

Super lecture sir!!!!

[@sohamjavheri3715]

Competishun zindabad...!!!

[@dhruvtripathi5972]

aur fir sir iss lecture ke baad garma garam chawal daal khane chle gye 😂. but the lecture was splendid ek dum to the point mza aagya🙏

[@ShivamKumar-hq3gm]

Itna kami mat nikalo yaro Aage padhlo pahle phir batana !!

[@RyoYamada07]

"To infinity even beyond it I'm the comet, no destination"

[@beastfamilyfanclub5558]

Great content sirrr

[@shashwatagarwal7067]

Sir Cp and Cv ki values calculations and degree of freedom nahi karwaye hai kya aapne

[@ShivamAnandSpeaker]

Degree of freedom u can watch in abj sir ktg Lecture,I gues in last 1-2 Lecture or either in thermodynamics also...in physics

[@samatasingh5087]

Sir after carefull obs i notced physics work is. (Pressure of gas ×dv) Thats why its opposite in sign

[@Sudhish2026]

wah ,someone noticed it btw samata i also noticed the same thing in chem, it is ext pressure * dv

[@mominabdulahad4069]

At 16:49 sir has written q/dT while sir has written in definition that heat required to raise the temperature by 1 degree.why sir hasn't taken 1 at place of dT.pls explain.

[@devkaransingh9242]

as you don't know how much temperature is changed ... if we replace it with 1 the c = q and thus makes no sense whatever heat is transfered c will take the same value but q = cdt makes sense; as it fixes the value of c your question was nonsense

[@AyushRaj-ez2cw]

Here q is heat we’ve given to 1 mole and dT is the temperature change it has caused, therefore for finding temp for unit change we take q/dT

[@birojit1]

@@devkaransingh9242iit ban Gaya?

[@rupaljain5449]

Sir aapne bola except monoatomic gas Cp ,Cv for every substance depend upon temperature but phir uss table me toh aapne diatomic aur polyatomic ke liye constant values likhi hain wo kahan depend kr rai temp par Sir pls answer It's request

[@devikantjha2159]

You are right that monoatomic gases do not have vibrational and rotational DOF this is because they do not have bonds which gives them a single spherical structure which is directionless and makes them independent of rotation and vibration.Moreover they still have 3 translational DOF which gives them a constant value of 3/2R,translational DOF means that they have 3 axis to move. For more clarification you can checkout 6 lecture of Thermo. On unacademy jee by ashwini tyagi

[@sohail1221_]

Sir didn't taught degree of freedom and their values for atomicity..

[@d.9097]

Nope, because sir said that monatomic doesnot have vibrational degree of freedom but diatomic and polyatomic have vibrational degree of freedom.Vibrational degree are those which are taken under consideration at higher temperatures so when temp will be high we will take vibrational degree of freedom in di and polyatomic so cp and cv will change...in that table we didn't take any vibrational so these are constant

[@namansingh5276]

Iss ka answer pta chala?

[@Chamanpandit99992]

#askcompetishun sir at 9:32 we are calculating work done by gas but you calculated work done by gravity which is equal to chage in potential energy . And if this work is also equal to the work done by gas so the kinetic energy change should be zero i.e vf is zero so sir please explain that are you assuming at dh displacement its velocity is zero. Please sir i have doubt

[@Yogesh.kumar9759]

Acha🤨 gravity mass ko uper leke ja ri hai 🤨, are uper to pressure of the gas is pushing mass M

[@fascination3472]

Sir, teaches you very well. There is no doubt, but Sir, after writing please brief explain, please do Please Sir!

[@bosniangamer5509]

bhai jab revise kar rhe hoge apne aap samajh aa jayega. basic english toh aati hi hogi

[@asim3351]

@@bosniangamer5509 yes but atleast a small explanation is needed what I think

[@Sreejesh1803]

Thank you sir 💙

[@Abcd-bz2gp]

0.02 vicks ki goli khaalo sir...😂😂...btw lecture was awesome🙏🙏

[@jeramiahnolan5787]

21:30 how does the piston type vessel indicate constant pressure

[@sense_storiess]

temp increase hone pr piston se P control kr lenge as vo V increase kr degi expand hoker

[@preritsharma329]

because the mass kept above it is exerting the same pressure on gas

[@namanarora2005]

25:00 sir I think rotational degree of freedom doesn't depend on temperature but vibrational does 🌞

[@surajgavariya6137]

Kis chiz ki preprn kr rhe ho

[@ss-wx6pl]

rotational degree of freedom require atleast room temperature

[@mujhe_kya_mai_toh_tamatar_hu]

Thanks 😊

[@cyanide.c]

bro tera syllabus complete hua kya

[@Ravi_Raj.]

17:27 #askcompetishun here q=ncdt is for n mole ??

[@VandanaThakur-uq6jc]

Yes its right!!

[@tussulegend2641]

Sirji mst video

[@princemaurya4959]

sir in lectures k notes kha milenge? please reply.

[@ranaraunitrazsingh1755]

sir there were many adds in between moreover videos of ALK sir are not working on the competishun aap pls take this into consideration

[@asim3351]

Bro download the videos

[@alok.thakur]

Bro offline kar le

[@ManasJaipuria]

bro adblocker use kr

[@bruh8057]

#4-HEAT AND WORK CALCULATION|THERMODYNAMICS|IIT ADVANCED|JEE MAIN|CHEMISTRY CLASS 11|OLYMPIAD|KVPY

[@shirshgyan6778]

Title repeat kyu kiya😅

[@shivaswapna1975]

Thank you sooo much sir fr these wonderful sessions...I am very much thankful....

[@roopasharma32]

16:27 it should be "c" but sir wrote 'q' while defining right?

[@introvert.mmmutian]

Sir aap degree of freedom to btaye hi nhi

[@aruntejachamalla7465]

🔥 🔥 🔥 🔥 🔥

[@pndt01]

Nice sir

[@gigastein3151]

8:18 sir external pressure mai apne mechanical stops ka bhi pressure liya h kya.

[@shreyanshgupta5892]

no bro stoppers is just balancing out it isme stoppers ki bina hai ki initially pint>pext stoppers is just preventing the piston from expanding so as to measure initial condition

[@gigastein3151]

@@shreyanshgupta5892 oh thanks bruh

[@shivamsaurabh5627]

Sir Mg/A external pressure kaise hua?? atmospheric pressure ko consider nhi krna h kya??

[@VandanaThakur-uq6jc]

Video me bola toh hai... Neglecting atm pressure..

[@VandanaThakur-uq6jc]

Well Kaha Hai App?

[@eforeverything6482]

Obviously, are you slow😂

[@rameshshah5788]

Force upon area he na wo isiliye

[@eliteblenderuser]

Like if youve noticed the Windows ping @ 19:25

[@Japleen009]

#ask competishun what is degree of freedom

[@jeeaspirant7210]

Long back😂

[@premsagar4363]

Sir aapne bataya ki ki only monoatomic ko chhod kar sabhi ki temperature dependent heat capacity hoti hai par aapne table likhwayi usme wo constant values hain how ?😢😢

[@aryantrippin]

at stp.

[@Dhruv45124]

14:30

[@Ayush-hx9qn]

Sir notes ban gye lekin samjh nhi aaya 😟

[@Ayush_JEE24]

first time padhna par hota hain kaam kaam smjh aata hain but tum ussa socho aur dubara padho tab aayaga main bhin class 11 main padha than (10month pehla) bahut doubt than but aab crystal clear ho raha hain :))

[@deadpool20065]

@@Future_iitian_ bro then kaha se thermodynamics kare ?? Please suggest

[@harshvardhantiwari9]

@@Future_iitian_brother ye chapter he esa hai Pehli baar padhne may nhi samajh aata ek do baar revision karoge tab aayega isliye don’t worry sir ne saare topics cover kiye hai

[@JEE-qd9rt]

😂😂😂😂

[@piyu2003]

@@deadpool20065 bro try chemistry untold. The teacher there had explained it very well, otherwise, you can also study from abj sir. Most concepts of thermodynamics of chemistry is similar to that of physics

[@alphaiitd1]

Thanks sir

[@bosniangamer5509]

at 19:22 I thought my windows had a notification :DDDD

[@JEEAdvanced2023-ix8ij]

🔥🔥🔥🔥🔥🔥

[@anupamchaudhary547]

sir free expansion irrervesibe work also 0?

[@piyu2003]

Yes

[@gamersarena6279]

16:33

[@jacobblack2544]

When only two weeks are left for JEE and I have done only 60% of the syllabus till now I be like:- 0:03

[@amitsingh2782]

😂😂

[@arsenicalpha202]

Master that 60% and it'll be sufficient to crack the exam.

[@amitsingh2782]

❤️❤️❤️

[@TohruSan-l7w]

Sir, total work done meh why did we integrate it from 1 to 2???

[@lazycork1]

Are sir has explain karne ke liye laga rahe hai Uska asli matlab hai 1 matlab initial limit and 2 matlab final limit

[@shobhitaagrawal]

@@lazycork1I guess the limits indicate states. From state 1 to state2

[@Ict_editss]

Sir ne ye lecture mai kuch bhi acche se nahi samjhaye 😢

[@abhaysahani8090]

Team competitshun should be given Bharat Ratna someday ❤

[@csdoit]

Sir IIT Bombay se hain

[@SSEpsilon]

Thank you sir

[@vikram_singh005]

❤❤