Numerical Based on Psychrometry Chart to calculate Total cooling load and Room heat gain

  Рет қаралды 1,425

Keshav Jadhav

Keshav Jadhav

Күн бұрын

Пікірлер: 9
@BRPJ
@BRPJ 25 күн бұрын
Awesome 👌
@tisha-e1y
@tisha-e1y 24 күн бұрын
A conference room for sitting 100 persons is to be maintained at 22 oC DBT and 60% relative humidity. The outdoor conditions are 40 oC DBT and 27 oC WBT. The various loads in the auditorium are as follows: Sensible and latent heat loads per person 80 W and 50 W respectively; lights and fans, 15000 W; sensible heat gain through glass ceiling etc. 15000 W. The air infiltration is 20 m³/min and fresh air supply is 100 m³/min. Two-third of recirculated room air and one-third of fresh air are mixed before entering the cooling coil. The bypass factor of the coil is 0.1. Determine i) Apparatus dew point, ii) Grand total heat load and iii) Effective room sensible heat factor
@KeshavJadhav
@KeshavJadhav 24 күн бұрын
@@tisha-e1y kzbin.info/www/bejne/i6rWnoudmJ6Xb9Usi=MDW1t8utmdqnsa2e
@tisha-e1y
@tisha-e1y 24 күн бұрын
@@KeshavJadhav Thank you so much!!
@TeamRecreation2003
@TeamRecreation2003 23 күн бұрын
A commercial shop has following loads: Room sensible heat: 58.15 kW Room latent heat: 14.54 kW The summer outside and inside design conditions are: Outside: 40oC DBT, 27oC WBT Inside 25oC DBT, 50%RH 70 m3 /min of ventilation air is used. Determine the following if the by-pass factor of the cooling coil is 0.15. (i) Ventilation load (ii) Grand total heat (iii) Grand sensible heat factor (iv) Effective room sensible heat factor (v) Apparatus dew point
@KeshavJadhav
@KeshavJadhav 23 күн бұрын
@@TeamRecreation2003 kzbin.info/www/bejne/p6e7pp6Xh5qMfMUsi=Iv4w1Aya-fAZlEg3
@रविंद्रशिंदे-ज2ढ
@रविंद्रशिंदे-ज2ढ 25 күн бұрын
Great!!
@malharchikhale
@malharchikhale 24 күн бұрын
Can you please make a video on this numerical as soon as possible? "Atmospheric air at 30°C dew point temperature and 75% relative humidity, enters a cooling coil at a rate of 200 m³/min. The coil dew point temperature is 14°C and the by-pass factor of the coil is 0.1. Determine:[10] i) The temperature of air leaving the cooling coil; ii) The capacity of the cooling coil in TR and in KW. iii) The amount of water vapor removed per minute; iv) The sensible heat factor for the process"
@KeshavJadhav
@KeshavJadhav 24 күн бұрын
@@malharchikhale kzbin.info/www/bejne/a4SxiIF3hNWEn5Ysi=yiC4JAMGJ9tdJ8-d
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