Excellent explanation, simple and made easy. Thank you
@ganeshgalaxygg25494 жыл бұрын
Good explanation , for easy watch here:-)kzbin.info/www/bejne/ambdZ6qth7KIqcU Like,share and subscribe my channel
@Muck-qy2oo3 жыл бұрын
What I always wonder is whether a series of different springs acts similar to a conical spring, in a nonlinear shape?
@mnotil11 ай бұрын
Hey, nice video! What about a mass that is being suspended by two parallel, vertical springs with different spring constants?
@yeonhojung71856 жыл бұрын
I guess you are a new yoututor but I really have high reputation on this channel!
@ganeshgalaxygg25494 жыл бұрын
Good explanation , for easy watch here:-)kzbin.info/www/bejne/ambdZ6qth7KIqcU Like,share and subscribe my channel
@ketanschannel3 жыл бұрын
cause teacher there are better things that i don't wanna learn and the last one i had made me cry
@BirnieMac19 ай бұрын
For a series spring, how does a block in series between the two springs change things? Is it just a matter of subtracting friction from the spring force in the equation of motion?
@fourier61194 жыл бұрын
Hi Physics Ninja. I really like to watch the next video that explains a spring constant when mass is 0 but I cannot find it. Would you give me the link, please? Thank you.
@PhysicsNinja4 жыл бұрын
Simple harmonic motion including the mass of the spring
@JADEXPLORER5 ай бұрын
Easy and understandable DANK UE
@JB91967 жыл бұрын
Good video - helped me a lot when doing coursework :)
@PhysicsNinja7 жыл бұрын
Thanks, i'm glad you found it useful. Happy learning!
@diyatakhar6613 жыл бұрын
thank you so much!🙇♀️
@sumedh71304 жыл бұрын
Is there a way to determine the spring constant of a parallel system without the use of simple harmonic motion. I am asking this because this showed up on the AP exam and I was surprised as I thought harmonics would not be tested.
@PhysicsNinja4 жыл бұрын
You could hang the springs and see how much they stretch.
@ganeshgalaxygg25494 жыл бұрын
Good explanation , for easy watch here:-)kzbin.info/www/bejne/ambdZ6qth7KIqcU Like,share and subscribe my channel
@deavl106 жыл бұрын
Could someone tell me what would happen if you have two in parallel on one side and ONE (alone/in series) on the other side of the mass. How and why would you simplify it.
@PhysicsNinja6 жыл бұрын
imagine pushing the mass a little on the side where there are 2 in parallel. All 3 springs would now try to return the mass back to the equilibrium position so the equation of motion would be ma=-k1*x-k2*x-k3*x. All 3 spring forces are in the same direction. The effective spring constant is simple the sum keff=k1+k2+k3.
@ganeshgalaxygg25494 жыл бұрын
Good explanation , for easy watch here:-)kzbin.info/www/bejne/ambdZ6qth7KIqcU Like,share and subscribe my channel
@evstath6 жыл бұрын
Can you saw and proove with maths that the force F in the spring system in series is the same in both springs? e.g. Why k1x1=k2x2=F ? Is it because the displacement of two springs are not equal as it is in the parallel system? And depends on the constant K of its spring? It results that if the system is at rest ΣFx=0 -> F=k1x1-k2x2 . this means that the k2 spring must be conpressed and not elongated. Is that correct ?
@PhysicsNinja6 жыл бұрын
Blanqui imagine if it was a massless rope. In this case we say the the tension is the same everywhere. In our case we neglect the mass of the spring therefore the force must be the same or else you'd get a small piece of spring with infinite accelaration
@evstath6 жыл бұрын
If you sketch the F.B.D with the force vectors on springs it is difficult to understand how can 2 equal spring forces with vectors pointed to the left can be equal with 1 force pointed to the right, so that the sytem be at rest. -k1x1-k2x2 = F ???? So, can you please write the ΣFx for the system in series ? It is difficult to understand it if you write the ΣFx without the equivalent spring, but with the 2 individual springs K1 and K2
@swapnayak43486 жыл бұрын
@@evstath Take the point exactly between both the springs, As both the springs are massless, net force has to be zero. F1x1=F2x2
@ganeshgalaxygg25494 жыл бұрын
Good explanation , for easy watch here:-)kzbin.info/www/bejne/ambdZ6qth7KIqcU Like,share and subscribe my channel
@JoshMurphy4249 жыл бұрын
what is the frequency of two springs in series, in term of the frequenies of the two individual springs?
@PhysicsNinja9 жыл бұрын
+Josh Murphy Starting from expression for at 16:13 of the video. Write down the frequency of the individual cases as w1^2=k1/M and w2^2=k2/M. For each of these cases write the spring constants as the angular frequency squared multiplied with the mass. k1=w1^2*M, k2=w2^2*M. All you need to do is eliminate the spring constants in the general equation. With a little algebra you should get to the solution w=sqrt[ (w1^2*w2^2)/(w1^2+w2^2) ]. If you're still having trouble should me an email onlinephysicsninja@gmail.com and i'll forward you a PDF.
@ganeshgalaxygg25494 жыл бұрын
Good explanation , for easy watch here:-)kzbin.info/www/bejne/ambdZ6qth7KIqcU Like,share and subscribe my channel
@antoniomantovani31473 жыл бұрын
so not many likes its a shame, please use the button
@uasserkamal20022 жыл бұрын
thx alot
@phoenixelectronics26316 жыл бұрын
Bro, can you solve for a block placed between two springs??
@PhysicsNinja6 жыл бұрын
Phoenix Electronics the block between 2 springs will be the same as the 2 springs in parallel. For 2 springs in parallel like in the video both springs push and pull at the same time whereas for the block in between one spring will push and one will pull but both forces will be in the same direction.
@phoenixelectronics26316 жыл бұрын
@@PhysicsNinja yeah you are right I got the same result as in parallel springs. Thanks a lot.❤
@zzzweasel2 жыл бұрын
thank you!
@dangisjakutis37548 жыл бұрын
Very nice video,thanks bro
@ganeshgalaxygg25494 жыл бұрын
Good explanation , for easy watch here:-)kzbin.info/www/bejne/ambdZ6qth7KIqcU Like,share and subscribe my channel
@king-hm7gs4 жыл бұрын
Thank you
@ganeshgalaxygg25494 жыл бұрын
Good explanation , for easy watch here:-)kzbin.info/www/bejne/ambdZ6qth7KIqcU Like,share and subscribe my channel