Springs in Series and Parallel

Discusses the physics of two springs hooked together in either a series combination or a parallel combination. This is at the AP Physics level.

[@vijaysubramanian2037]

I love the fact that you started by diving straight into the topic!...

[@amineelarif7001]

i love the fact that you have Gon picture in your pfp!...

[@bappadityasaha3579]

@@ganeshgalaxygg2549 no you are shit.

[@aideeshahmi4772]

you make me understood two topics in a row,spring and circuit topics,thanks!!

[@YaegarEren94]

The video cleared all my concepts. The derivation of the equations in the beginning really helped me alot. Thanks and great video

[@astyutechick7980]

Thanks for being clear and straight to the point. I understood everything! Actually good content

[@worldmonitor5132]

Brilliant teacher with brilliant concepts.Best explanation!! Thanks buddy.Still watching in 2020.

[@boop5716]

Thank you for the clear and precise information. Also for the comparison you did with resistors.

[@PopaDom212]

what a fantastic video. Your explanation is so clear and simple so thank you!

[@s.n.victory3408]

"We are just gonna assume" 4:08 This was such happy moment. I was literally so confused like everyone was saying that the extension of both springs is same and ........ Now i got it

[@Kiyodio]

I'm currently doing A levels in the UK and I havent seen a video that explained it in a way that I could derive it myself. Thanks a lot for showing me that it would be easy enough to derive if I forgot it!

[@asifzawad5158]

That was pretty straightforward and simply explained.. Thanks ❤

[@kristenwensel3769]

Thank you so much for making this content! Helped me with my homework when I was getting pretty confused!

[@joshual3758]

Great video! I learned a lot!! So ready for my test tomorrow : )

[@Joel-yr2cu]

howd the test go buddy?

[@ydk2284]

Hope you did well!

[@AmanTiwari-bv6zu]

How was the test? LMAO

[@jaciane3798]

Still in school?

[@dillipnanda5118]

U failed I know

[@HaiTran-Tyler]

Thank you so much! I'll use these spring rules during my FE exam this coming week.

[@stevesgle4025]

Man you expalined it so clearly. Thank u!

[@dawgthenasty5429]

Thank you man appreciate this video

[@mayasinha7188]

It was crystal clear explanation.. thanks sir !

[@kkkk-qs6rn]

great video man, my test is in an hour and this save me

[@casperqurze8233]

Great explaination thank you!

[@lala-vh6fg]

Thank you! Very clear explanation

[@simranjoharle4220]

Thank you Sir..... this really helped!

[@oliviali7976]

Very clear! Thanks so much

[@marioleon4128]

At first, I was blind, but now I see. Thank you good sir.

[@ColonelScotch]

Thank you so much! I'm doing dynamics hw and we're now on the chapter about Work and energy!

[@manishsinghrajput1802]

Very very much helpful.thank you

[@areebahmad1484]

wow great video prof

[@umeshkashyap6070]

JEE Aspirants assemble

[@KiritoPanda]

Yuss surr!!

[@fadsmfawopefaw]

Thank you so much! I've never had a proper physics mechanics class before and I was clueless but it makes sense now. You are an amazing teacher!

[@sysk6773]

Loved it sir...

[@DrTusharSharma]

The video is too old but still up to date! Gonna help me always!

[@venkataramanamurtychepurip8102]

Learnt a lot Thank you

[@Ahmadabdal_]

this is so helpful unlike our p.o.s book which doesn't even mention this topic yet they are in the papers

[@shaffroncity]

saved my life for my lab report!! thank you :)

[@anjana5887]

I really need a great help in covering all General Organic Chemistry Principles concepts! :/ would you please help! :-} Please suggest some thing, how do I remember the Name Reactions?

[@shaffroncity]

@@anjana5887 Sure! What worked for me was making reaction maps and filling them in over and over!! For example, you can make a reaction map for say addition reactions ( or google one!!) by starting with an organic reactant, then draw an arrow to the product and fill in the blank reagents. You should also write the name the reaction while you do this, try to visualize or say out loud the mechanism/arrow-pushing, and other important info like "syn" or "anti" etc. You can also list reactants, then fill in the blanks with predicted products or vice versa. The key is to do this a bunch of times and to really force yourself not to look things up in your book/notes too much! The repetition + having to recall the info from memory is what helped me most. Another thing I did to remember reaction names or reagents was to make silly rhymes or numonics. Like for OSO4 I remembered "oh so syn-ister" to remember it was syn addition of OH lol I hope this helps!! You got this :D

[@sihfgzd7061]

thanks for your beatiful explication

[@faisal1934]

Great video, out professor teach us from it. He doesn’t do shit

[@alanraj9731]

Good work 🙏sir

[@OSMADO]

After years being in University, I am back to review and re watch your videos for my upper division course. Thank you !

[@aideeshahmi4772]

thank youuu ,you help me so much

[@Vanessa-zi4og]

Amazing, you have cleared all of my doubts... thank you so much!

[@damnyes5667]

Thank you sooo much Sir.

[@ThejanaMunasinghe]

Thank You!

[@srihariromeo2725]

Keep up the good work.

[@hihams6993]

Great video man! You really helped me in understanding the why in this!

[@testchannel7747]

Thank you so much! Not all heroes wear capes ;)

[@AnuarsTV]

You are right. But if you stretch it farther to get it back to the same length as when it was longer and stretched, then the new "x" will not be equal, neither the half of the original "x" (when it was longer and stretched).

[@Shootskas]

For compression do you just use a negative force?

[@amazesoundtrack3421]

Thank you,thank you ,thank you

[@ClydeMorrisMusic]

Thank you sir!

[@shevplayz1860]

Great vid.

[@Rima-wd1ne]

Awww that's so cool ! Thank u !

[@bird100yearsago2]

Thank you

[@Mr_2chef]

Thank you ❤

[@MisterBinx]

I'm doing this problem where I am calculating the spring constant of a vertical rod with a mass at the center. But I'm thinking the springs are in parallel instead of series. The total deflection at the center will be the same on both sides of the mass. In the problem both ends are fixes so both deflections have to be the same. I guess we only count them in series if the deflections of the springs are different.

[@SHONSL]

Thank you!

[@daivahfiona4479]

how do you do the formula for springs in opposing series of 2 different sizes and rates. etc I have a .50kg/mm x 450mm long spring in a opposing series set up with a .60kg/mm x 70mm. lets say that the 450mm spring compresses to 400mm and that would put the 70mm spring at 20mm n length. as the longer spring compresses the shorter spring extends till springs seperate completely. What would the rate be of the springs before they separate? I used the k1 x k2 / k1+ k2 = rate I know this formula works stacking them on top of each other but when doing the opposing series, do I use the inverse and subtract from the longer spring rate?? thanks Daivha

[@user-zh6qu7dn3i]

THANK YOU SO MUCH!!!!!!

[@aurum3404]

great vid, thanks

[@bewhoyouare5556]

What happen to the no of coils in parallel series would they be equal to Spring Stiffness ?

[@surendrakverma555]

Thanks Sir 👍

[@mahmudaliza4079]

really helpful :)

[@DMeloMan]

How would you find the period if there is a mass in between two springs? What would the period be if there were two parallel springs acting on a mass?

[@geethachandrasekar3245]

DMeloMan u slove the reaction by constraints equation bro

[@ganeshgalaxygg2549]

Good explanation , for easy watch here:-)kzbin.info/www/bejne/ambdZ6qth7KIqcU Like,share and subscribe my channel😊

[@_ShubhamTiwari1312]

Brilliant👍👍👍

[@Beastagmaio]

Great 👍..tq

[@solarsynapse]

More related to capacitors than resistors? Is it a fair guess that this applies to compression springs as well?

[@AnuarsTV]

I really don't know if what you are saying is true, but are you agree with me that the "x" is not the length of the spring? x is the displacement from the equilibrium position.

[@user-us8xs7ud9n]

THANK YOU

[@99waterblade]

Thank you very much :3

[@hellblazer9261]

thank you!

[@karthik-rd5vx]

thanks a lot. Made my day 😅😌😊☺😉😉😊😄

[@archismanchakraborty8228]

Nice work

[@cath1594]

DUDE you are good.

[@amalbiju2046]

Nice one 👌👌

[@MuhammadAhmed8]

if the spring is cut into two equal halfs,how is the time period affected

[@varunshah3290]

Muhammad Ahmed I think you have to multiply by √2. If we take the spring with stiffness k and split it in two parts, we get two springs each with stiffness k. Thus effective stiffness is half of k. Substitute into the formula for period we get 2π√(m/0.5k) which is 2π√(2m/k) which is just multiplying by √2

[@lduh9446]

Can i use the method if one spring is torsional spring and the other is translational spring and i need to find the k eq of the tow springs.

[@mickyweird8644]

thank you so much

[@erikjohansson4275]

Thanks!

[@nuwankalanamith3039]

Thank you...

[@somnathbanerjee4993]

In case if the force isn't applied in the middle of the bar (in case of parallel springs),say its applied at a point P which divides the line into a ratio a:b then how will we obtain the equation for K effective.? thnx btw i know the equation but i am unable to understand how they derived it..Help would really be appreciated thnx... (y)

[@ramanjotsingh2172]

If there are to springs of spring constant K1 and K2 and if same force is applied to both they have time period T1 and T2 respectively. What would be the time period if they both are connected in parallel. any relationship between Teffec and T1 and T2.

[@godriksvids9281]

ramanjot singh ramanjot, The T1 and T2 you are calculating are from T= 2*pi*sqrt(m/k). If you substitute keff in for k, then you know that Teff = 2*pi*sqrt (m /(K1 +K2)) for parallel springs.

[@hoseinqadam]

can someone help me, I am doing mathematical models in engineering and I want to know if a rotary damper would have both spring scenarios (both series and parallel) but opposing.

[@AnuarsTV]

So, you're saying that the spring's constant depends on the length of the spring? Where that came from?

[@gayantha_gk]

thanks alot mann !! , appreciate the video big time :)

[@forithall2417]

Sir, amazing video! But I have a question, if the difference between K's on springs in series is quite big (I mean if we have a very soft spring and a very hard spring) when you pull with a relatively small force one will be deformed and in that case how is -k1*x1=-k2*x2 ? Maybe my intuition is wrong..

[@lasseviren1]

The very soft spring will have a small k and large x and the hard spring will have a large k and a small x.

[@forithall2417]

Thank you!!

[@somethingdifferent7713]

if we cut it in 4 parts so K will be four times original K ? is it righy

[@rnumashankar2857]

Thanks sir

[@hardikkardam6116]

thanks a lot

[@thereishope651]

thank you.Can you send me if the period of motion of amass connected to two springs connected to each other in series and parallel

[@lasseviren1]

That's T=2(pi)sqrt(m/k) where k is the effective k of both springs that is derived in this video.

[@sreepriya2133]

If springs are in series and parallel connection which parameter remain constant for all the springs???

[@nazilpm45]

Good sir.. But one doubt.. how the extension of the spring became half of the original extension when it cut into two equal half..

[@MunkyChunk]

When you only have half of the spring, for the same force, it’s only going to stretch half as much, because there’s only half as much of it to stretch.

[@MiXtApEMesSiAh22]

THANK YOU!!

[@abhijitsinha5316]

So are you there??

[@khalidabdelhamid6027]

Im in university and still watch your videos !

[@Dev-bq3mm]

Thankyou

[@manlawmixes]

wow nice one

[@outdomkhen9336]

Very good

[@mastan7846]

Short and simple

[@brycemontgomery3164]

Just divide both sides of the equation by F. It turns all of the F's up top into 1's.

[@yvesluyens5427]

Great video, I used it in my Physics class. Question: Is your name really Lasse Viren or are you just a fan of the famous runner? 😄

[@user-ni3sp5mz4u]

I'm building a prototype, can any one here give me some insight, please. I need a 2" - 3" diameter compression spring to expand horizontally as far as possible ( in the air, no friction). Ideally 24" - 30" solid height into 8' - 10' free length. Is there any tricks or methods to assisting in greatest free length? Hope I explained my point well enough, know very little about springs, thanks in advance.

[@bayanzabihiyan7465]

sounds more like a job for a hydraulic shock (like those found to hold hatchback trucks in cars), they have a huge "free length" and can be compressed a lot.

[@saravananb2980]

Good One!

[@basharhz]

thnx alot :)

[@naumanrasheed3635]

sir practically it is not possible to have x1=x2=x in case of parallel spring arrangement as if they have different stiffness How will you justify???

[@neilpetroff6758]

As long as the plate, or whatever it is, connecting the two parallel springs does not rotate, both springs have to deflect the same amount. That is, the plate, the end of spring 1, and the end of spring 2 all deflect the same amount. In general, since k_1 is not equal to k_2, different forces will be developed in each spring.