Orthogonal Signals (Solved Problems 2)

[@harshitkumarc0289]

1.3^(0.5) is 1.14 not 1.41 check at time 05 : 09

[@siddeshavhad]

you're wrong. It's 1.41

[@shreyjani5114]

@@siddeshavhad bhosdike 1.14 hai

[@vidvathamar4181]

NO he is right it is 1.141709245 @@siddeshavhad

[@N1tTROxUMP45]

@@siddeshavhad no, youre a retard

[@AjayKumar-ob3vm]

sir its really confusing because in previous videos you calculated power of composite signals by adding avg powers of them but here why you used this formula for A○

[@mohammedadel363]

because the phase is difference in this example

[@anubhavkumargond3264]

basically this method apply on orthogonal signal only.

[@0506saikiran]

wats wrong with the below approach?? please let me know. 2sin3t+3cos(3t+60) 2sin3t+3[cos(3t)cos(60)-sin(3t)sin(60)] on simplyfing 0.597sin3t+1.5cos3t power of Asint or A cost is (A^2)/2 so total power =(0.597^2+1.5^2)/2=1.48

[@makingmycareer2608]

This method is right

[@rationalthinker9612]

Way better method, that other shit was ridiculous

[@farook7410]

Equating L.H.s and R.H.s with plus symbol is applicable?

[@kesavkumar1434]

why cos (5*pi/6) is calculated in radian @nesoacademy

[@tulyagosetti6827]

Its a bit confusing...it would be better if u tell us where to use a particular method to solve...why cant we simply add the individual powers ?

[@ushashreemurali4793]

Hello, Sir. Could you please mention the value of phi in A0sin(wt+phi0) = A1sin(wt+phi1) + A2sin(wt+phi2) Awaiting for an answer. Thanks in advance.

[@muralisai7782]

Phi1=0 , phi2 = 5π/6 (π/3 +π/2 =5π/6) ..the phi values are taken from the given data.

[@hashirwaqar8228]

This is not a orthogonal signal at all and that's why it is solved differently .I have checked for the conditon of orthogonal to confirm this

[@BSFMSTU-EEE]

sir its really confusing because in previous videos you calculated power of composite signals by adding avg powers of them but here why you used this formula for Ao

[@k_EC_ANURAGPAL]

i used cos(a+b) and it became orthogonal...and i did using A^2/2

[@shaillybhai007]

but the answer is not the same right?

[@shaillybhai007]

now it is coming 1.3

[@prakashchandrajat9752]

nice video

[@akhilchiluveru5834]

sqrt of 1.303 is not correct @neso academy

[@coolmanqabaha3820]

1.1414

[@rovibb2128]

probably he didn't notice he didn't write 1 before 414 after dot

[@abc1936]

wonder how he missed as 1.414 is famous sqrt(2)

[@anandamar6775]

1.141490254010081

[@Svenkatesh429]

here you are saying that freq and phase should be same for orthogonal but before you have solved power by adding..very confusing..please reply for comment

[@refreshment567]

in previous video also if u do by same method u will get the same result.

[@ishaanbaru8984]

In that question if u change the consine to sine by using π/2, they will become two same harmonics with different frequencies and phases i.e orthgonal

[@mohammedmahrozuddin]

In the previous video, the signals x1(t) and x2(t) where orthogonal. Because they were cosine and sine signals with same frequency (omega not) and same harmonic(2) and with same phase (45°). The formula P = P1+P2 is applied only on orthogonal signals. But in this video the sine and cosine functions have same frequency and harmonic but different phases so they are not orthogonal signals to each other. Hence the formula P=P1+P2 cannot be applied. And we have to convert them into a resultant signal using the method shown in the video and Ao²/2 will be the resultant power.

[@Jashu_jaswanthX]

RMS value is 1.141

[@mosannajalal1502]

The value of cos(5pi÷6) is confusing me

[@makingmycareer2608]

It's taken wrong here. cos(pi/2+x)= -sinx not sinx

[@AyushMo]

@@makingmycareer2608 It isn't wrong. cos(5pi/6) is cos(pi - pi/6) which is -cos(pi/6) About your 'cos(pi/2+x)= -sinx' thing, that isn't what we're using here. What was used here was sin(x + pi/2) = cos(x)

[@makingmycareer2608]

sir but cos(x+pi/2)= -sin(X), so how did you take positive value by converting?

[@AyushMo]

What he did is correct. We had cos(3t + pi/3), let 3t + pi/3 be y. So we have cos(y) and we want to convert it to sin, and that is easily achievable by writing cos(y) as sin(y + pi/2)

[@Jashu_jaswanthX]

RMS value is 1.141