Armstrong Number - தமிழில் Programming - Payilagam

[@ArunKumar-zz4tg]

Awesome Teaching sir,God bless you Always

[@angeldaniel9954]

Hereafter There is no need go for any programming course bcoz i can able to understand ur teaching

[@eaganathanshamraj5124]

Super sir keep posting video's we Will support you

[@ArunKumar-zz4tg]

Program Explanation is Superb sir

[@abinayaabi7271]

Super sir very easy to understand

[@ummesalma8566]

Understood.... Sir too good😮

[@ajaykumar_tamilan]

For any number given as input how to find Armstrong number

[@m.hcraftworks770]

Sir awesome 👌🏻👏 Sir I like it very much 👍🏻

[@lokeshm6119]

Ultimate sir Good teaching..

[@malavan2766]

Thank you sir ... Its helpful for me

[@pkkp6286]

Sir extraordinary explanation sir 👌tq

[@veeramanip8495]

Sir enga number 10 la mattum than divided pannanuma apti 10 la mattum than divided pannanuna 1634 Armstrong number sollunga

[@sanjayprabhum907]

if (No == arm) then There is no need of no2

[@sudhar8579]

Super explanation sir

[@divyac7626]

Super level explanation Sir

[@devstackz5187]

i was interesting for your class sir...

[@karthigakarthiga9209]

I can understand easily.....tq sir.... upload more videos

[@iam-irfan]

np=str(input("enter your num")) bp=int(np) new=0 for i in np: b=int(i) c=b*b*b new+=c if new==bp: print("armstrong") else: print("no") try this

[@jayashree990]

Thank u sir... Nice explanation

[@hemalakshmi7168]

Thank you so much sir

[@nanthiniboopalan2465]

simple and clear

[@024naveenms4]

Ur great

[@kayalvizhin4622]

Sooper 👍👌👌👍

[@ArifKhan-rd5nc]

for loop work aagala

[@vennilasenthil6432]

C++ Dettol venum sir

[@san8122]

Sir after checking "while" it will "do"sir or do killa irruka statements laam pannathuku aparam while condition check pannuma

[@prabhu1517]

'do' ku kila iruka statements laam panathuku aproma while condition check pannum

[@hemalathaharibabu803]

Nice bro ...

[@-_-FIRE-_-]

Thanks sir

[@padhmanabanrethinakumar195]

Number 4 digit ah erunthalo illa 5 digit ah erunthalo yenna pannuvinga

[@subhashinishini952]

Multiply by its digits count. If 4 digit means Multiply itself 4 times.

[@Ganesh-005]

Vera level

[@kiddiesarea8388]

for i in range(150, 400): fst=i%10 res1=fst*fst*fst sec=fst%10 res2=sec*sec*sec thrd=sec%10 res3=thrd*thrd*thrd arm=res1+res2+res3 if(arm==i): print(arm,"is armstrong number") Can anyone say what is the error in it? I have to print all the Armstrong number within the range 150-400 but during output it gives only one value

[@kirubhavignesh6199]

You have written fst = i % 10, if we take i as 153, 3 will be stored in fst , so in sec = fst % 10, 3 is passed.

[@naveenkumarselvarasu7433]

Thanks sir for ur work..

[@lifeisshortnanba7205]

Super sir

[@unknown_VK]

thalaivare...lenth base pani thane multiply pannanum🙂atha solava ilaire

[@rajiraji0214]

370 epdi sir calculate panradhu??

[@PayilagamChennai]

Try the same way we did.

[@51nishanthi.s71]

great100%

[@ECENAVEENKUMARM]

Go on regularly sir plssss

[@tech-learner4555]

Super sit

[@vennilasenthil6432]

Yanaku Java paython Dettol venum

[@ravichandranr2020]

Rmba tnx sir😊

[@shafeeqix4096]

Program Mattum system la pottu kaamiga

[@hariviswa5621]

d=input("enter value:") s=int(d) l=list(d) result=0 for i in l: result=result+(int(i)**len(l)) if result==s: print("it is an armstrong number") else: print("non armstrong number")

[@sivakumarm2592]

In this program,only suitable for three digit number .......for four digit number ,this program not suitable....

[@joelantony3420]

Kindly cmt the cod for 4 dight num

[@joelantony3420]

He is correct.. 4 digit no vantha remainder ah 4 times multiple pannunga bro.

[@sugunamanickam8942]

User ketta irruthu values vaguna epdi print pannuvinga

[@PayilagamChennai]

Check Scanner videos

[@baguleyanb4219]

4 digit num ku intha coding work agathu.

[@joelantony3420]

So kindly cmd the cod fr 4 digit value

[@joelantony3420]

He is correct.. 4 digit no vantha remainder ah 4 times multiple pannunga bro.

[@sksabari9431]

Thank you sir

[@indiantourism975]

Super sir

[@3thrisha869]

Thanks sir

[@ECENAVEENKUMARM]

Super sir