Percentage Yield and Limiting Reagent

[@chrisjohn8409]

for limiting reagents, if the reactants aren't in a 1:1 ratio, then would the limiting reactant still be the one with the lower number of moles?

[@heleniroanya]

Sorry, i didn't get the last question...where is the 24 coming from?and why volume divided by 24?

[@yousifz.08]

its been 6 years do u know it now unc

[@sabahussain758]

Thanks for this helpful video. I just wanted to ask at around 12:05 you said you divide by 24 but why do you do that?

[@MaChemGuy]

Saba Hussain Hi there. I’m using the vol = mol x 24 equation to find the volume of gas that the moles of ethyne gas would have at RTP. I’m then comparing this volume with the actual volume produced. Maybe you’re not familiar with the molar gas volume equation? I have a video on that too. Can send link if you would like?

[@sabahussain758]

MaChemGuy Yes please

[@MaChemGuy]

Saba Hussain Here you go kzbin.info/www/bejne/oGGZeXVpbrtkj68

[@flowerpower487]

@machemguy Sir is it moles that you divide by or mass?

[@MaChemGuy]

You can calculate yield by comparing the actual mass or moles to the expected mass or moles

[@flowerpower487]

Thank you sir, and thank you for your videos. I have recommended them to fellow chemistry students, they are an invaluable resource.

[@philip4691]

You sound like Chuck Norris... Or just a random guy... How did i get to this video?

[@walidkhan616]

you're rounding your answers wrong

[@charlotte1974]

The 2nd % yield should be 53.9%

[@meganjohnson1688]

I agree, @machemguy, I got this answer calculation the theoretical mass of methanol to be 9.632 then 5.2/9.632 x 100 = 53.9, would this still be correct?

[@sharan5857]

@@meganjohnson1688 i did the same