Practice Problem: Initial Rates and Rate Laws

[@savannahadams2821]

Some days, I just want to give up and change my major. But then I remember Professor Dave's channel exists and that I'm not stupid, it is possible to learn the material. Thanks so much! :)

[@ivoryas1696]

Savannah Adams Nice! Which major are you?

[@savannahadams2821]

@@ivoryas1696 I'm a biomedical sciences major at my uni :)

[@opufy]

i can relate to this!

[@IvyElizabeth918]

Thank you, this was great. I did the problem on my own and then watched the remainder of the video.. I had almost everything correct except for the units in the answer for k!

[@shardofkingdoms9816]

Professor Dave explains it in such a way that makes it easy to learn

[@taylorreese6215]

Thanks Professor Dave! THIS HELPED!

[@ameilly]

Just did this in CHM ll Thank you

[@brianzar1943]

I believe that there is an error in the final calculation of K. In the data we are given the rate of NO loss which is d[NO]/dt. However, The rate of reaction = -1.2 d[NO]/dt and when you calculated K you assumed that the Rate of NO loss (d[NO]/dt) is equal to the rate of the reaction which is not true. Can you please confirm?

[@michaeltaumoepenu2875]

Appreciate ur hardworking, thanks

[@adethyamuralidharan1721]

thank you professor dave ,you are really awesome. I had this doubt for a long time and I got it clarified.

[@Yatukih_001]

Fun explanation by Professor Davs, or Professor William Williams...

[@Nobodyknows95123]

thankyou

[@janchristianbailo970]

hello professor dave! can i use trial3/trial2 instead of trial3/trial1 when getting the x order?

[@cocogabrielle2005]

Got a chem 1820 test...I'm rushing..if ykyk lol

[@Noone-rm9hu]

But why we put concentration of trial 2 in numerator and of trial 1 in denomenator? When i do it oppositely the answer is still the same I've got same order but is it necessary to put trial 2 concentrations in numerator??

[@cactichris9829]

How do I do one with 3 M Collins’s?

[@shubhneet8082]

Won't the order for NO be 1 because as NO is multiplied by 1.5,rate is also multiplied by 1.5..but u wrote that it's multiplied by 2.25..i think there's an error here.

[@ProfessorDaveExplains]

those are exponents

[@shubhneet8082]

@@ProfessorDaveExplains yeah so if the rate increases in the same way as the concentration of NO. Wouldn't the exponent be 1 instead of 2?

[@ProfessorDaveExplains]

sorry i misread at first, for NO the increase of rate is equal to the square of the increase of concentration, it's not by 1.5, it's by 2.25

[@shubhneet8082]

@@ProfessorDaveExplains okay Thankss!

[@gajjiyadav7271]

Sir , I can know evolution I first

[@ayushshukla1042]

First