Derivative of ln (x) using the definition of derivative

  Рет қаралды 16,247

Prime Newtons

Prime Newtons

Күн бұрын

Пікірлер: 39
@WolfgangFeist
@WolfgangFeist 11 ай бұрын
Second last step: you need to use "continuity" of ln(x). (Because:with still finite x/h the term in the ln is not yet 'e'). BTW: I love the way you are presenting this explaining every step (in a calm and friendly way). Most teachers try to do it in a hurry. That is the main reason, why some students get annoyed with math.
@AvneeshKumar-x4o
@AvneeshKumar-x4o 3 күн бұрын
And in the limit the variable should approach infinity
@temporarychannel9759
@temporarychannel9759 Жыл бұрын
the enthusiasm made this really enjoyable to watch, great job
@averagestudent5222
@averagestudent5222 11 ай бұрын
This guy turns math into magic
@SpiroGirah
@SpiroGirah 4 жыл бұрын
I never thought of this! Good job!
@barthennin6088
@barthennin6088 Жыл бұрын
Beautiful! 1st time seeing this truly from first principles!
@boguslawszostak1784
@boguslawszostak1784 6 ай бұрын
If you define ln(x) as the integral from 1 to x of 1/u du, you have no problems computing its derivative. It is equal to 1/x by definition of the function.
@Th3OneWhoWaits
@Th3OneWhoWaits 9 ай бұрын
8:58 as h goes to 0, "n" or x/h goes to infinity. Thus, lim as h goes to 0 = lim n goes to infinity.
@manoharkanade7383
@manoharkanade7383 Жыл бұрын
Very good explanation ❤
@ecSruthipriyaMahesh
@ecSruthipriyaMahesh 7 ай бұрын
I really like your classes, thank you for your hard work! 😃
@sldw3221
@sldw3221 Жыл бұрын
Hello sir, i'm seeing that we always using definition of e with limit while proving all of these formulas but is it actually possible for you to explain or prove how or why limit n->infinity (1+1/n)^n is equal to euler's number? Did you record a video about this or would you talk about that in another video if it's possible? Thanks
@wira2562
@wira2562 10 ай бұрын
It's very useful to understand the inderivatived integral of dx/x sir!
@robertveith6383
@robertveith6383 4 ай бұрын
Use grouping symbols: (dx)/x
@Harrykesh630
@Harrykesh630 6 ай бұрын
just a suggestion 😁 It might be too late to point out but, you could have started by first proving that ln(x) is indeed differentiable by Left and Right hand derivative then go on to find it.
@nellwackwitz
@nellwackwitz 3 жыл бұрын
You are AWESOME!!
@AvneeshKumar-x4o
@AvneeshKumar-x4o 3 күн бұрын
But the variable should approach infinity
@nichodimuszishiritinashe8329
@nichodimuszishiritinashe8329 2 жыл бұрын
You are the best
@surendrakverma555
@surendrakverma555 8 ай бұрын
Very good. Thanks 👍
@alexdcruz3682
@alexdcruz3682 7 ай бұрын
Love your videos
@EternalScienceAndTech
@EternalScienceAndTech 11 ай бұрын
You are a great man
@samwelkariuki3114
@samwelkariuki3114 2 жыл бұрын
Always the best teacher.....what about 1/x
@PrimeNewtons
@PrimeNewtons 2 жыл бұрын
Thanks
@elai3147
@elai3147 2 жыл бұрын
5:31, as h goes to zero wouldn't x/h go to either positive infinity or negative infinity?
@xavierwainwright8799
@xavierwainwright8799 2 жыл бұрын
This works because lim x-> -inf (1+1/x)^x is also equal to e, but I don't know any proofs without using the derivative of ln(x) (this would be circular reasoning).
@cblpu5575
@cblpu5575 Жыл бұрын
Recall that the domain of ln (x) is **positive real numbers only** hence x/h is a positive real number x divided by a quantity h tending to zero
@wilsonhicke5598
@wilsonhicke5598 5 ай бұрын
Love this
@EliiiAkotha
@EliiiAkotha 6 ай бұрын
Great job
@salamalmudarris5032
@salamalmudarris5032 2 жыл бұрын
But n is integer while x/h is real number?
@sandraboateng5435
@sandraboateng5435 Жыл бұрын
😍😍👌👌✊✊👍👍
@januszek1760
@januszek1760 10 ай бұрын
(1 + 1/(x/h))^(x/h) is not equal e
@Artemis1855-k4w
@Artemis1855-k4w 2 ай бұрын
as h approaches 0, x over h approaches infinity, if you replace x/h with a variable it's more legible
@festusemmanuel2111
@festusemmanuel2111 Ай бұрын
Wow ❤
@hassanejturay2994
@hassanejturay2994 Жыл бұрын
Awesome
@katiatzo
@katiatzo Жыл бұрын
BRAVO
@holyshit922
@holyshit922 Жыл бұрын
He missed step when he used fact that ln is continuous
@joelmwape4239
@joelmwape4239 2 жыл бұрын
You are the best
@PrimeNewtons
@PrimeNewtons 2 жыл бұрын
Thank you for your kind words.
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