Probability & Statistics (18 of 62) The "At Least One or Once" Rule - Example

[@marcschmiedel9110]

I love this guy, he helped me through a difficult night of maths despair. Props to this guy

[@md.arifulislam447]

Thanks a lot for this probability playlist Sir. These videos are gems....

[@MichelvanBiezen]

Thank you. Glad you found our videos. 🙂

[@XxXRapidoSxXx]

2:42 To make profits LOL !! Awesome teacher, keep it on !

[@nguyenthithuhien1374]

fuck

[@Sklenny99]

At 2:03 he says that the probability of this happening to any one number (not just 6) is 0.518, however this is technically incorrect. It is true if you are looking one SPECIFIC number between 1 and 6, but not true if you are looking for ANY single number between 1 and 6. This is true because if you are looking for ANY non specific single number, the first roll would not have a probability of (1/6) but a probability of (1) because any number would do.

[@MichelvanBiezen]

The statement is correct. The probability for any ONE number.

[@Sklenny99]

Michel van Biezen My mistake, I was confusing it with something else that wouldn’t be applicable in this problem. Thanks for the videos!

[@MrWinter2]

You’re an amazing teacher! Thank you again!

[@FavioQuenaya]

Hahaha the better than 50-50 part truly amuses me! Thanks

[@MichelvanBiezen]

Glad you enjoyed it.

[@eolvra]

I'm about to start hustling kids on campus now

[@jahiem-j1sv]

Marry me! Lol, I have an exam in little over 1 day and watching your videos are helping me so much!

[@MichelvanBiezen]

You got this! All the best on your exam. 🙂

[@javeda]

Awesome teacher indeed

[@wirito]

Well, I rolled a die 10 times and the times it took to roll a six were: 6,12,5,3,5,2,4,10,3,17. Avrg: 6.7 tries.

[@russelomondi8063]

Biased dice

[@wirito]

@@russelomondi8063just a regular die. It just shows that out of those 10 tries, I was able to get a 6 in 4 tries or less. Not too bad but I wouldn’t bet money on it Lol

[@chakradharsimhadri2132]

Hello sir I got a doubt in probability that is 2 die are rolled 2 times find the probability that for getting a sum 7 i) atleast once ii) only once iii) twice

[@Clifffffffffford]

Thanks!

[@Leelaraidu]

Hi Sir can you help with this sum - A sales executive has generated 20 leads. He estimates that there is a 10% chance that each lead will result in a sale and that the leads are independent of each other. What is the chance that he will make at least one sale?

[@MichelvanBiezen]

Calculate the probability that they will NOT make a sale (0.9 each) and then multiply them together P(not for 20) = 0.9^20 = 0.12. Then the probability of making at least one sale = 1 - 0.12 = 0.88 (= 88% chance).

[@Leelaraidu]

@@MichelvanBiezen Thanks so much for the quick response , appreciate your help :)

[@Leelaraidu]

@@MichelvanBiezenbtw how you got the 0.9 ?

[@georgetzathas9002]

@@Leelaraidu 10% chance of sale for each, so 90% chance of no sale for each. 90%=0.9

[@yichengtoh4405]

To find the # of ways that "6" would not appear in 4 dice throw, why cant I say (6C5)^4? Can someone kindly explain to me? Thank you so much!

[@MichelvanBiezen]

Work it out both ways and compare. But from a logical point of view, find the probability that you will throw a six and then subtract that from 100%

[@AssyrianKing4ever]

Thanks for all your videos. Going over all of them here to prepare for the naval officer test. How would you go about solving this problem and calculating the solution? If a pair of dice is rolled and a playing card is selected, what are the odds of rolling a value that adds to 8, and the odds of you selecting a heart? I have 5/36 for dice and 1/13 for selecting a heart. I really don't know what the solution is. Thanks :)

[@MichelvanBiezen]

Are they asking for the "odds" or for the "probability". They are different. Look at the videos that explain how to calculate the "odds".

[@AssyrianKing4ever]

@@MichelvanBiezen I think odds. Will do! Thanks for your quick reply. Do you have videos to prepare me for math aptitude questions specifically geometry? Thanks

[@zainrezaei4860]

Thank you!

[@MichelvanBiezen]

You're welcome!

[@abdullahsaleem8525]

Nice and v informative

[@kishinasura1504]

Yep. Gacha is a mad mistress. _MAD_