Quotient Rule Proof

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Dr Peyam

Dr Peyam

Күн бұрын

Пікірлер: 43
@zhixiantaivieve
@zhixiantaivieve 5 жыл бұрын
How can u be so serious and funny at the same time while proving maths😂 hats off doctor Peyam
@blackpenredpen
@blackpenredpen 5 жыл бұрын
TAI ZHI XIAN hahaha totally agree!! I want to grow up to be like Dr. P!
@zhixiantaivieve
@zhixiantaivieve 5 жыл бұрын
@@blackpenredpen hahaha hey sir , i watched ur videos too , it's great , both of u are funny and genius 👍👍
@qubix27
@qubix27 5 жыл бұрын
There is a whole Chinese derivative family of Chen Lu, his Italian wife Prada Lu and their son Quo Lu
@ViktorKronvall
@ViktorKronvall 5 жыл бұрын
Qubix The kid is surely named Quo Xian Lu, isn’t he?
@jonasmb7
@jonasmb7 5 жыл бұрын
More basic videos like that! Thanks Dr. Peyam :)
@aracalbuto
@aracalbuto 5 жыл бұрын
I'm not a mathematician but I like maths and your videos are awesome :) thank you Dr. Peyam!
@LarryRiedel
@LarryRiedel 5 жыл бұрын
I like the horror movie camera angle. I was on the edge of my seat anticipating the jump scare.
@frozenmoon998
@frozenmoon998 5 жыл бұрын
The Quo-Chen-Lu is amazing! When I first happened to come by it in my math studies, as they are not exponentially high or anything :)), I actually remembered a nice pattern, which states: Low, D-High - High, D-Low/ Square the Bottom, and away we go. Great video!
@vtvtify
@vtvtify 5 жыл бұрын
A trivial proof that I thought of a few months ago: let f(x), g(x) (f(x)/(g(x))' = ? define h(x) = f(x)/(g(x) h(x) * g(x) = f(x) after taking the derivative of both sides: h(x)g'(x) + h'(x)g(x) = f'(x) substituting the definition of h(x) (f(x)/g(x))g'(x) + (f(x)/g(x))'g(x) = f'(x) after multiplying both sides by g(x): f(x)g'(x) + (f(x)/g(x))'g (x)^2 = f'(x)g(x) after subtracting f(x)g'(x): (f(x)/g(x))'g(x)^2 = f'(x)g(x) - f(x)g'(x) la finale, after dividing by g(x)^2: (f(x)/g(x))' = (f'(x)g(x) - f(x)g'(x))/g(x)^2 yay! xD
@foreachepsilon
@foreachepsilon 5 жыл бұрын
I very much prefer the form (f/g)'/(f/g)=f'/f - g'/g so that I can say, "the relative rate of change of a quotient is the difference of the relative rates of change."
@przemysawkwiatkowski2674
@przemysawkwiatkowski2674 5 жыл бұрын
K H Wow! I never noticed it! :-) Are there any applications of f’/f ?
@foreachepsilon
@foreachepsilon 5 жыл бұрын
Przemyslaw Kwiatkowski I just think it’s more of a meaningful statement. It has logarithmic meanings too.
@saatee100
@saatee100 5 жыл бұрын
I am the sixth person enjoying your exposé!
@High_Priest_Jonko
@High_Priest_Jonko 5 жыл бұрын
I like to see more Analysis videos cause it's my favorite subject
@otakarzdebski9497
@otakarzdebski9497 5 жыл бұрын
Why you are so much cheerful?
@kobros-tech
@kobros-tech Жыл бұрын
fantastic 🎉
@yrcmurthy8323
@yrcmurthy8323 5 жыл бұрын
Sir, one thing. Derivative of (f/g) is derivative of (f • (1/g)). So we can just use product rule. Hence proved
@drpeyam
@drpeyam 5 жыл бұрын
And the chain rule, so you need to prove the chain rule too
@yrcmurthy8323
@yrcmurthy8323 5 жыл бұрын
@@drpeyam oh I see. Thank you sir. I didn't see that
@michaelempeigne3519
@michaelempeigne3519 5 жыл бұрын
Would it be okay to do it by using product rule ? H(x) = f(x) / g(x) So g(x) * h( x ) = f ( x) And use product rule from there
@drpeyam
@drpeyam 5 жыл бұрын
Yeah! That’s also a cool way of doing it
@beatoriche7301
@beatoriche7301 5 жыл бұрын
To be honest, I don’t understand why many calculus teachers introduce the quotient rule when it’s really just as convenient to use the product rule. Is it your personal experience that introducing the quotient rule helps students? Personally, I am happy with just the product rule.
@virajagr
@virajagr 5 жыл бұрын
Can u please prove Chen lu as well:) I searched online and got only one proof that is dy/dx=(dy*du)/(dx*du) which gives us the proof. But can it be proved just by using the definition of derivatives(the limit of h tends to 0) without introducing dy/dx? Thanks
@drpeyam
@drpeyam 5 жыл бұрын
Already done!
@virajagr
@virajagr 5 жыл бұрын
@@drpeyam oh I didn't notice it, just watched it thanks it was awesome:)
@VibingMath
@VibingMath 5 жыл бұрын
A very solid proof from first principles, compared to your other videos, this is only on kindergarden level 😁
@RalphDratman
@RalphDratman 5 жыл бұрын
Exactly. And, way back in calculus (at Berkeley!) I always had trouble remembering the stupid quotient rule! So it is very pleasing to me to see it demonstrated so gently. Dr. Peyam, you are a good man.
@turbopotato4575
@turbopotato4575 5 жыл бұрын
There is another proof that is easier far more intuitive in my opinion: First apply the product rule to f and 1/g the use the chain rule on 1/g
@Silver-xf7it
@Silver-xf7it 5 жыл бұрын
You have a new subscriber
@drpeyam
@drpeyam 5 жыл бұрын
Yay!!!
@phronessys
@phronessys 5 жыл бұрын
It's exactly what i'm seeing in college, thx
@rigorless6330
@rigorless6330 5 жыл бұрын
based on the camera angle i kept expecting everything to slide to the left the whole time
@mikedavis8973
@mikedavis8973 5 жыл бұрын
Quotee Lu!!
@Flanlaina
@Flanlaina 4 жыл бұрын
Use the Quo Chen Lu!!!
@jayamitra4656
@jayamitra4656 5 жыл бұрын
Next paw-duck rule.
@tusix6
@tusix6 5 жыл бұрын
My gf is like the sqrt of -100 A solid 10
@shashwat4920
@shashwat4920 5 жыл бұрын
Copied
@GRosa
@GRosa 5 жыл бұрын
Or an imaginary 10 😂😎
@Flanlaina
@Flanlaina 4 жыл бұрын
Shashwat 10*i, where i is the imaginary unit
@benjaminbrady2385
@benjaminbrady2385 5 жыл бұрын
Quo Chen Lu
@RalphDratman
@RalphDratman 5 жыл бұрын
I had some difficult studying the board each time before you erased it. I kept having to pause whenever you moved out of the way. Could you please write higher up on the board so your body will not be in the way of what you have written? Or in some other way provide more time to read what is on the board. Thank you. (PS I love this very much)
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