Ship Stability _ Trim Introduction Part 2_ Formula for MCTC

Explains the derivation of MCTC= W x GML / 100 LBP

[@eduardodaquiljr9637]

So what is stability? That is triangulization or plane geometry subject in high school.

[@setyoufree2726]

I am not working related to mother vessel but love to see how mathematics applied to the real life. Excellent for your explanation.

[@Catdaddy8989]

If we use (Trim/LBP)=(GG1/GML) then could we write GML=GG1/(Trim/LBP) = GG1*LBP/Trim? With this relation and if we know GG1 provided a center of mass equation, could you write Moment needed to change Trim by 1 unit (MCTC) = W * (GG1 * LBP/Trim) / * LBP This is assuming the trim is 1/100th of LBP

[@captalfred]

Great explanation 👍

[@MarinaMatic]

If B shifts from B to B1 how come when we move cargo from forward to aft the AP to B distance before shift from h. tables and then again AP to B1 are exactly the same since LCB distance is same for same displacement? In your image distance from AP to G1 is larger then AP to B1, that makes trim lever forward not aft? How do you calculate BB1 longitudinal shift? You have seen the problem your self when you drag the green arow to B1, if you placed it correctly it would be left from G1 and that would make ship trim forward. ???

[@ncekdockerfile7219]

Tentang intensif yang berhubungan dengan pernyataan intuisi. (PEMILIK)

[@prabu0bala07]

Instead of shifting if i load a cargo w, in the formula for MCTC should use initial displacement i.e W or final displacement i.e W+w??

[@georgen9755]

What make no sense ?..

[@inandoutthere3963]

Good Day. Need help regarding calculating or obtaining the value of GML?

[@faragmasaoud8902]

Verey good indeed

[@tanchanokphanit361]

Cof What is

[@rinklesebastian4991]

How did GG1 = (m*d) /∆? Can someone explain the proof of it?

[@magellanseaman]

Many thanks!

[@aymanhamad9262]

I understood that, if we load above G , then G will not move longitudinally, and therefore no trimming moments will take place, and trim will remain the same. and if we load above C.F, which is not vertically above G will do the same, i.e the trim will not change. now the question is, Is loading above G will not affect the trim as the same effect as loading above C.F? thanks.

[@sailorstube3259]

If the ship is box shaped where COF and COG will lie in the same line , it will not make any difference .However for normal ship shape COG and COF are different, hence loading at COF will not result in trim but loading at COG will result in some trim. FYI COF is the geometrical center of water plane area where ship trims and COG is the point where total weight of ship is assumed to be acting vertically downward.

[@sanketgthesailorman3985]

Make a video on change in trim due to change in density

[@AmitKumar-jt5qy]

How you got trim (t) not fully clear.Please make me understand.

[@jairabelleventurillo9998]

after the vessel has heeled, the AP and FW has a difference, and that is ur trim.

[@softwaretraining-naval]

Thanks for upload video.

[@srinivas_gullipalli]

very nice explation sir,anyone can understand easily

[@thapa3]

Thank you. Great videos.

[@alvincarreon9886]

MCNTC WEW..

[@rubecortneysalesjangad1057]

Thank you sir

[@waelsh6403]

You are great , thank you😃

[@lukasvanderveken8093]

Is MCTC constant? because GM(l) is also constant

[@sailorstube3259]

MCTC is not constant. It changes with the draft or dispalcement. For small changes in draft, it may be considered constant.

[@sajibmiah9301]

It will be depend to the displacement of ship.

[@abdelrahman458]

thanks

[@hosseinazizi1426]

Excellent lecture

[@crazymofoshit]

Gratitude

[@mmashrurhussain1042]

Great video sir. Thanks a Lot