4^(b) * 4^(b) = 80 [4^(b)]² = 80 4^(b) = ± √80 4^(b) = ± 4√5 → we keep only the positive value 4^(b) = 4√5 Ln[4^(b)] = Ln(4√5) b.Ln(4) = Ln(4√5) b = Ln(4√5) / Ln(4) b = [Ln(4) + Ln(√5)] / Ln(4) b = 1 + [Ln(√5) / Ln(4)]
@AsadInternationalAcademy14 күн бұрын
thank you so much dear
@AsadInternationalAcademy14 күн бұрын
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@juanjoalbertez10313 күн бұрын
Absolutely amazing. 10/10.
@AsadInternationalAcademy13 күн бұрын
Wow, thanks!
@AsadInternationalAcademy13 күн бұрын
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@veijolalli32612 күн бұрын
WRONG!!! - - - ln80/2*ln4 +++ ln80/2/ln4
@AlexanderSemashkevich8 күн бұрын
b=log80/2log4=(2log4+log5)/2log4=1+log5/4log2 b≈1+0.699/(4×0.301)≈1903/1204≈1.5805 Deviation is about 0.0001 4^(2×1.5805)≈4^3.161≈80.004
@AsadInternationalAcademy7 күн бұрын
beautiful solution
@elektrotubbie14 күн бұрын
Gracias. Muy entretenido.
@AsadInternationalAcademy14 күн бұрын
welcome dear
@AsadInternationalAcademy14 күн бұрын
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@angi357412 күн бұрын
MAL,PORQUE FALTA ROAVIA ...QUEDA LOG BASE 16 DE 80
@AsadInternationalAcademy11 күн бұрын
ok dear
@AsadInternationalAcademy11 күн бұрын
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@hansgeorgschrey516811 күн бұрын
the solution shown is overly complicated - if you start writing the numbers in form of exponent of 2 you will be finished in seconds ... my personal view: not good for beginners !
@AsadInternationalAcademy10 күн бұрын
easy dear
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@joaosilverio809910 күн бұрын
Why 16*5 ?
@AsadInternationalAcademy10 күн бұрын
check out the lesson
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@joaosilverio809910 күн бұрын
@@AsadInternationalAcademy thanks
@robertoneves540615 күн бұрын
Não existe nenhum
@AsadInternationalAcademy14 күн бұрын
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@AsadInternationalAcademy14 күн бұрын
here b
@panini_checker9 күн бұрын
Whoww...😮 Well..Using a calculator: * log(80) ≈ 1,9030899869919 * log(4) ≈ 0,6020599913279 * b ≈ (1.903... / 0.602...) / 2 * b ≈ 1,5804820237218
@AsadInternationalAcademy9 күн бұрын
ok dear
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