Finite square well scattering states

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Brant Carlson

Brant Carlson

Күн бұрын

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@fr0styy202
@fr0styy202 4 жыл бұрын
its 2 am and my final at 11am. As a frequent college all-nighter, I thank you for the clarity, good sir.
@sasasatatata602
@sasasatatata602 3 жыл бұрын
solving for T=1 we require sin ( 2a/h * sqrt(2m(E + V0))) = 0 so 2a/h * sqrt(2m(E+V0)) = pi * n so E + V0 = (pi * n * h / 2a)^2 / 2m this looks like E = p^2 / 2m and de brolie says p = h/lambda so lambda = 2a / (pi*n) so we have solutions 1,2,3,4.... so when the half wavelength is an integer multiple of the well width we have a momentum ~ energy which will transmit fully so a standing wave in the well lets a scatter wave "coast by"
@lancehenning4187
@lancehenning4187 5 жыл бұрын
For anyone struggling with the algebra of resolving the boundary conditions, heres a useful read. quantummechanics.ucsd.edu/ph130a/130_notes/node160.html
@vorsankoy3548
@vorsankoy3548 9 жыл бұрын
thank you very much..I have used a lot from Brant Carlson, from first video till this, its great
@MiguelGarcia-zx1qj
@MiguelGarcia-zx1qj 3 жыл бұрын
15:25 onwards: Say it is an intuition; I think that those dips in transmission are the result of interference when the QWF has a wavelength related to the well width. As Brant points out, akin to the reflective coating in optic systems. If my intuition is right, I'm missing an explicit statement about the issue; more over, considering we are studying wave functions (and phenomena).
@howwedoMichaelmath
@howwedoMichaelmath 11 жыл бұрын
You're the man! Thanks for making these videos.
@besidehimself9813
@besidehimself9813 10 жыл бұрын
Very informative, thank you.
@meeranagarajarao6887
@meeranagarajarao6887 3 жыл бұрын
Most treatment of this physics problem becomes so mathematical and one loses the physical perspective. But this is a very neat approach. Thanks.
@meeranagarajarao6887
@meeranagarajarao6887 3 жыл бұрын
A very neat approach.
@Maymz-uf6bc
@Maymz-uf6bc 9 жыл бұрын
GREAT VIDEO, UNFORTUNATELY MY ASSIGNMENT IS TO UNDERTAKE ALL THAT MESSY ALGEBRA AND END UP WITH the expressions for F and T :( sorry, only realised my caps lock was on half way through writing this...
@andrewstallard6927
@andrewstallard6927 6 жыл бұрын
We have to go through the algebra hell on our own for this one.
@OM-el6oy
@OM-el6oy 4 жыл бұрын
Should have used .lower() method
@TiagoBatista-uc8nm
@TiagoBatista-uc8nm 4 жыл бұрын
Same :(
@captainhd9741
@captainhd9741 4 жыл бұрын
@@TiagoBatista-uc8nm Actually you can just go through all that mess for T or R and then use a sneaky trick to get the other one without repeating all that hard work. The trick is to remember that T+R=1 so if you have the formula for T then just do 1-T and all of that will be the formula for R
@TiagoBatista-uc8nm
@TiagoBatista-uc8nm 4 жыл бұрын
@@captainhd9741 oh thank you! I found some PDF on google with the algebric manipulation to get T, I was struggling with that part. But thanks for the response, I appreciate it!!
@arupbiswas8288
@arupbiswas8288 7 жыл бұрын
extremely helpful videos!
@valeriaitzelarteagamuniz5286
@valeriaitzelarteagamuniz5286 6 жыл бұрын
good video! where did you make the transmission coefficient graph?
@enchis1269
@enchis1269 4 жыл бұрын
Why you use trigonometrical function as the general solution for region 2 instead of exponential funtion?
@ljrahn5619
@ljrahn5619 4 жыл бұрын
Yes wondering the same
@captainhd9741
@captainhd9741 4 жыл бұрын
@@ljrahn5619 As long as it is the same then it doesn’t matter. Trigonometric functions are related to the exponential function e^ix = cosx + isinx
@goddess_ofchaos
@goddess_ofchaos 29 күн бұрын
Trig fcns are nice bc we can exploit their even and odd qualities. The boundaries are centered symmetrically around x=0, thus it is nice to use these. But there is nothing wrong with using the exp form
@cafe-tomate
@cafe-tomate 2 жыл бұрын
For about two hours now Ive tried to resolve the BC, the two results Ive found are either one nor the other good
@SampleroftheMultiverse
@SampleroftheMultiverse 10 жыл бұрын
Very well done!
@goddess_ofchaos
@goddess_ofchaos 29 күн бұрын
Why doesnt the the term with exp(-ikx) not go to infinity for x
@xXxBladeStormxXx
@xXxBladeStormxXx 10 жыл бұрын
Why did you skip the formalism chapter? Also, thanks for the videos.
@Mathletelady
@Mathletelady 2 жыл бұрын
Thank you for explaining :)
@kartikeypandey499
@kartikeypandey499 3 жыл бұрын
why we didn't apply that G=0 approximation on surface x=-a too???
@davidhand9721
@davidhand9721 2 жыл бұрын
Here's how to calculate things with the wavefunction: Don't calculate things with the wavefunction.
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