In this video, I showed how to set up the problem in order to use the Squeeze Theorem.
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@sharirhariparsad5777 Жыл бұрын
If more professorstaught like you, the world would be a better place...love from south africa
@PrimeNewtons Жыл бұрын
Thank you
@asokk.mukherjee34227 ай бұрын
At the of 75 in a retired life I am enjoying your brilliant way of teaching mathematics; best wishes for your great work (from a senior citizen of India)
@PrimeNewtons7 ай бұрын
Many thanks!
@user-fh3dp4nx4p Жыл бұрын
The way you offer your classes is just fun, simple and fast.
@RethabileMokgari-yq6ju3 ай бұрын
"Those who stopped learning, stopped living."💯❤That's powerful sir. You are doing incredible work.
@desiresiabuwasupersounds Жыл бұрын
My brother you have explained the concept of squeeze theorem so simple thank so much pliz continue to make more videos you are a great tutor I have ever watched.
@acerovalderas4 ай бұрын
Apart from the clear way of your explanations you have a soothing voice which is just perfect. I am very glad I have found your videos. I taught math for many years.
@teamgaius Жыл бұрын
Wow! Just exciting. Thank you sir.
@raphmackey3063 Жыл бұрын
You are a great help, thank you
@ardaaktis5002 ай бұрын
This solution was so understandable and clear. Thanks 🎉
@AsandaMahlaela3 ай бұрын
Thank you so much for making this easier to solve and understandable
@user-yw8lx2ic9e Жыл бұрын
Great explanation.
@user-je7yx7mr1s8 ай бұрын
Nice explanation. Easy to follow.
@spaceshipastro7 ай бұрын
like.. thank u sm and i would be lost without u!! big love from Iraq
@user-re3oo8ue7b9 ай бұрын
You're just awesome my brother
@heritierirakiza8075 Жыл бұрын
THANK YOU FOR YOUR SUPPORT
@MahirRashid-ih1nz Жыл бұрын
Salute bro💯💯 i gained more in your tutorial
@biswambarpanda44684 ай бұрын
Great my brilliant sir.
@pujachakraborty5244 Жыл бұрын
thank u very much 👍🙏
@rssl55005 ай бұрын
We could use the sinu=u formula as you said to get 0 But I really like this method I learned it today from you ! Keep up the great work man ❤️🔥
@mariannakot737 Жыл бұрын
please do more!
@Dheeraj53737 ай бұрын
Tomorrow will be my exam and i thaught squeeze theorem is easy enough but when i try to do questions i stuck up and then this video 😊 . Thanks a lot
@simonkibera47229 ай бұрын
Thanks for your lessons, why didn't you divide all sides by × from 5/× at the middle?
@violethill4454 Жыл бұрын
you have a beautiful hand writing
@Cyrenalux Жыл бұрын
Hey brother i have one question, what would happen if i replaced x^6 with an odd power? Thx for all your videos they really help me out a lot 🙏🙏
@PrimeNewtons Жыл бұрын
It doesn't matter because if negative x^5 will be negative and so will change the inequality signs on both sides but that would then retain the original inequality just written from right to left and you can rewrite it. So, the short answer is that nothing will happen.
@BenjaSichali9 ай бұрын
Good one💥
@nothingbutmathproofs71506 ай бұрын
Since you made a few videos using the squeeze theorem, can you please make up a video that proofs this theorem? That would be cool.
@joelmacinnes23918 ай бұрын
If it were not for the mandatory use of squeeze theorem, could you have said that sin(5/x) would go to an undetermined value between -1 and 1, which, when multiplied by x⁶ which would go to 0, would also become 0
@AbrehamDegu-xx1vc2 ай бұрын
that`s great🎉🎉🎉
@user-xm4yd5jv2x4 ай бұрын
What happen if x has an odd exponent ? do we assume negative or ? depend on what value x is approaching
@o.om.m5632 Жыл бұрын
Thank you so helpful if it was x inplace of x^6 and the second question if x approaches 0 from the right or from the left could you please reply
@PrimeNewtons Жыл бұрын
All 3 answers are 0
@o.om.m5632 Жыл бұрын
@@PrimeNewtons so if the exponent of the x is odd it don't matter as all the inequalities will stay the same all all of them will flip right?
@user-dm7oj2kz2p7 ай бұрын
you are brilliant 10q
@danilojonic79245 ай бұрын
I dont understand only one part though: How did you multiply the entire inequality with x^6 because thats basically 0? Or its not? Maybe its allowed because its very close to 0 from the right (positive) side? Please clarify on this.
@themathsguy-7606 Жыл бұрын
GOOD SIR WHERE CAN WE FIND YOU MAYBE TO ADRESS SOME KIND OF QUESTIONS.
@PrimeNewtons Жыл бұрын
Message me on Twitter or email primenewtons @gmail.com
@sisaa.g Жыл бұрын
Hello Sir, I wanna if ever what if the power was odd , were we gonna change the sign since we didn't change because it was to the power of 6
@PrimeNewtons Жыл бұрын
It will adjust in the end even if it's odd. Watch the other squeeze Theorem video. I explained it there.
@user-rz8lv7pl3x7 ай бұрын
lovely lol i wish i was your student
@FenetAbilu Жыл бұрын
Wow you are smart
@YsabellaCastillo Жыл бұрын
What if we have a fraction for example the limit of sin(8x)/x as x approaches 0 or the limit of sin(t)/square root of t as t approaches 0
@PrimeNewtons Жыл бұрын
The first example is quite common. Multiply x by 8 then multiply sin(8x) by 8. So the limit is 8. For the second, do the same think using sqrt t instead of 8. You should get 0 answer.
@KingGisInDaHouse11 ай бұрын
That first one requires a whole ‘nother one or two videos to explain. That second may require some dlc we learned in calc two…or you would at least have to come back to it after you learn derivatives and interpret it as one.
@KingGisInDaHouse11 ай бұрын
Ok for that second one you can do it with raw limits my argument is you can say sin x0+ sin x/sqrt(x) 0 x/sqrt x because your dividing more cookies by the same number of people Now we need a lower bound argument for the squeeze theorem. The limit is positive because positive/positive is positive for my lower bound I can just use the opposite lim x->0+ -x/sqrt(x) < L < lim x->0 x/sqrt(x). Since x/sqrt(x)=sqrt(x) -sqrt(0)0- sin(x)/sqrt(x) lim u->0+ sin(-u)/sqrt(-u) lim u->0+ -sin(u)/(i*sqrt(x)) Lim u->0+ (-1/i)*[sin(u)/sqrt(u)] Lim u-> 0+ (-1/i)*[0]= 0
@itsmemario12987 ай бұрын
Sir can you pleasee make video on proving squeeze theorem and please make a video on Weisteress Thereom with proofs