Statistical Estimation | Lecture 1 | Biostatistics

[@TheStatisticsTeacher]

Note the error at 34:34 the value for error is 1416.71.The answer is (4456.29, 7289.71)

[@deadkachu7678]

The question u gave after this my answer is coming (746.299,765.701)

[@deadkachu7678]

And the 99 percent questions which u give to solve my answer is coming (76.32,92.28)

[@deadkachu7678]

And sir for the 90% the answer is (14.99,19.41)

[@deadkachu7678]

Sir the last question of proportion i didn't understand. p^=0.18 ,n=1220 so q^=0.82. 0.18± 1.96√0.000120 0.18± 0.21 (-0.03,0.021) This is my Answer but it's coming negetive one side.

[@MISHECKNGOSA-jw7yx]

He has made me understand better than my university lecturer thank you ❤

[@carlolinechidakwani138]

Am saying

[@nainarkumar]

In an automotive safety test conducted by the North Carolina Highway Safety Research Center, the average tire pressure in a sample of 62 tires was found to be 24 pounds per square inch, and the standard deviation was 2.1 pounds per square inch. What is the estimated population standard deviation for this population? (There are about a million cars registered in North Carolina.) Calculate the estimated standard error of the mean Construct a 95 percent confi dence interval for the population mean

[@TheStatisticsTeacher]

Thank you for the interesting problem. It would serve as a good practice question for engineering statistics.

[@adogafavour583]

Sir but what if you are given 96% as your confidence interval

[@TheStatisticsTeacher]

Most commonly 96% are not used. If you would like to calculate them you can use the normal distribution table to calculate the z-value at 0.96 and use that value in the confidence interval formula instead of 1.96 if it is a one tailed test. If it is two tailed test you can find the z value at 0.98 and use that value instead of 1.96. I hope that answers your question.

[@Jo_kings]

Hii, pls on 27.24 how did you get q?

[@StaneMakayi]

Makes sense

[@StudyAccount-c5y]

Thank you

[@TheStatisticsTeacher]

You're most welcome! Please like, share and subscribe!

[@Reminiscer0]

Very helpful

[@TheStatisticsTeacher]

You're most welcome! Please like, share and subscribe!

[@WII567]

Good 👍

[@TheStatisticsTeacher]

Thank you. Please like, share and subscribe!

[@mekutube6565]

best lecture but you have make error in calculating margin of error it is 1416.77

[@TheStatisticsTeacher]

Hi thank you for the feedback. Please let me know the exact time point so I can review and put corrections in comments.

[@mekutube6565]

@@TheStatisticsTeacher ok my dear

[@RudyGiuccini1973]

@@TheStatisticsTeacher Great presentation -- the error is at ~34:34 time

[@TheStatisticsTeacher]

Thank you. I will add the correction in the description

[@RudyGiuccini1973]

Looks like you multiplied by 1.6 instead of 1.96

[@Alex-Yema4wz4cw7h]

good

[@maxamadsharif5827]

how do iget this lesson i need i hve a presentation next weak

[@TheStatisticsTeacher]

I'm sorry Sharif the presentation cannot be shared. Please use the video and screenshot or replicate the content on a seperate slide. The problems are from the textbook Biostatistics Rosner.