Strength of Materials | Module 3 | Shear Force Diagram | (Lecture 33)

[@tarun_sarkar_]

Terrific lecture! Most effective!

[@kozacknep2220]

@30:42 step has been jumped since (b-L)= -a....and the value of S.F at C=( - P*a/L)

[@mohdamin4611]

Thanks 🙏

[@naeemabbasbhatti1629]

Dear, I am from Pakistan and I love watching all your lectures especially of Fluid Mechanics and SOM of this channel. The way you teach is laudable and is not less than a blessing to have a teacher like you and others. Would you please mind initiating the series of Hydrology, Irrigation and Environmental Engineering? I am in need of these Lectures as I have my exams at end of this month. If you will do this, I will be grateful. Thanks

[@SunilKumar-gs6jr]

Thanks

[@naturelover5784]

Bhatti converted 🐷

[@travelfoodadventure775]

Jai hind

[@sandyp9926]

Frist speak jai shree ram 🚩🙏

[@aliabbas8029]

@@sandyp9926 tum jaise logo ki wjh se hi india ka naam khrab ho rha h..... Sir vi tere msg ko dekhe honge to unko vi tere pe sharam ayi hogi.....

[@ruhi2564]

Thank you so much Sir one of the best you tube gate lectures I found here keep uploading videos sir so that we can learn regularly. Thank you

[@sithuammasi9653]

You are made a subject very easy and understandable one. Hats off to you sir you deserve it. Thank you sir

[@ashutoshtiwari8187]

at 45:00 shear force is zero at x=0 (ie. at origin) the graph v=wx will be a straight line passing through origin inclined at some positive angle with respect to the x-axis (if w is positive) or it will have a negative angle (if w is negative) the graph will be similar to that of the y=x line please mention this point sir btw so much informative video............

[@shishirkoirala6945]

same doubt

[@engineeringstudents150]

Thank u Sir, One of the Best Teacher, and Way of Explaining the concepts is very Good, Thank u so much again, Sir.

[@harekrishna1590]

Thanks you sir for great teaching without any cost.

[@rameshpanwar8676]

Jitni tarif ki jaye utni km hai bhaut ache smjaya sir apne ap mere sare doubt Clear kr dete ho so thank you so much sir ❤️❤️

[@faheembaloch1605]

Iam from pakistan and iam ur fan sir plz upload more lectures and also lectures on truss anaylsis

[@yeonjin8]

You are my saviour. ..thanks a lot....😘❤️🙏

[@veeralingam74]

Terrific ..sooooo good lecture ..thank you sir

[@anirudhparvatikar7990]

Dear venugopal sir, all ur som lectures are excellent. I gained lot of understanding and many concepts became clear. Sir can u make lectures on rcc design especially working stress method and limit state design. It will be really wonderful. Thank u very much sir.

[@neerajkandpal5892]

Sir You are the great teacher of the universe

[@RahulKumar-ve5mn]

Thanks alot sir ji for uploading the som lecture.

[@manuverma7223]

Thank U Sir for teaches the topic bending force diagram this lecture is far better than my college teacher lecture

[@techeasy3667]

Thankyou Very Much For Your Dedication To Make videos. Thanks from my heart. U r really doing good work.

[@nehamd2392]

Doubt : sign convention taught in previous lecture ,when section is taken R to L, for point load upwards negative and downwards positive , moment clockwise is negative and anticlockwise is positive ......................but you didn't follow these

[@angshumannayak5337]

Mera GATE Ka pura Preparation aap ka video ke Upar ha

[@SunilKumar-gs6jr]

Thanks sir I have no words for you god bless you 🙏

[@venugopalsharma1945]

Thanks

[@shivanshdwivedi1572]

u are excellent teacher.ur way of teaching is excellent.😊😊😊😊😊

[@rahulpatel7861]

Bahut aachhe se aaya samajh me sirg

[@sugunakarrao7354]

Sir your teachungs are very useful

[@mdasifshaikh1623]

Wowsome lecturer

[@Education-js1sx]

thanks sir i am regular visitor of ur page

[@rathodkajal5005]

Always conceptual class sir 🙏

[@tollywoodhome1872]

Thank you so much sir ❤

[@nikhildeshpande9989]

Precisely and defined way. Thank you sir !!!

[@beginner828]

Great channel .. great teaching

[@vishalupadhyay5941]

33:05 sir at point c u written the shear force value is-pa/L so sir please show that how it will come?

[@poppurlanavaneethkumar2384]

Pa/l + Pb/l = P therefore pb/l - P = - Pa/l

[@sandeepkumarsahoo2629]

Thank u so much sir. I have no word to thanks you. God bless you sir.

[@ratandeepsingh6369]

Very well explained,sir

[@harshittiwari9558]

I really enjoyed this lecture.. Thank u sir ji

[@VikrantYadav-ub2gj]

Sir mujhe apke sabhi lecture jaldi samaj ate ha

[@RahulKumar-ve5mn]

Sir please upload open channel flow lecture.

[@karantothsrikanth9662]

sir, i loved ur way of teaching but i have one doute for one end fixed and one end free the number of reactions =3, 1moment and 2 forces but u taken only 2reactions =1moment and 1upward force but i cant understood that please can u reply to my msg

[@amankumarchoudhary4181]

sir UDL or UVL can be solved without section cutting method ,can we solve directly ?

[@uddarajuvenkatapathiraju9292]

Excellent

[@Pawan-rn6nr]

Super teacher 👌👌🙏

[@indranilbhattacharjee5662]

Best teacher of SOM

[@shahidali-hy2hn]

good work sir......keep it up...we are all with uh( our support and warm regards).

[@mubeenabegum357]

Please add 'Ma sha Allah'.

[@payalsingh6911]

Could you please tell me sir that at point c -pa/l kaise aaya.??

[@mr.er.2981]

At 43:19 mistaken ly taken negative it should be positive v+wx=0

[@artitad9603]

Sir ur Lecture is best

[@aiswaryavijay8602]

Sir pls upload remaining lectures !! We r completly depending on u !!

[@praveensrivastava3132]

He says the Lectures were uploaded but they were deleted after hack.. Is is true or were the lectures never uploaded?

[@chetnadubey5985]

Warning:Very knowledgeable video 📸🙏

[@Rahulyadav-rj4hn]

Thank you so much sir for everything ❣️♥️🙏🙏

[@atithikumar1390]

When V=dM/dx =0 then it means graph has either maxima or minima but here we are considering only maxima why? Why are we not talking anything about minima here?

[@sreeharicr4099]

Sir please solve isro previous questions from som and fm

[@CiViLTechinformation]

The shear force at a certain section of a beam is stated to be zero the bending moment at the section will be?

[@deepaknayak4376]

Thanks a lot sir 🙏

[@prabhuvanprasad2644]

Thank u sir soo much.. 😊

[@imamit100]

Sir, baki k module upload kab honge, venugopal sir my only hope to understand SOM, life mein first tym koi Som acha pada raha hai. Please upload rest of the module. Thanks

[@ankitsamal1126]

Hello, Sir got a query actually. We need to consider various locations such as A, B, and C in the x-axis. Why you are randomly shuffling the directions/alignments

[@shreyashagrawal2264]

The fixed support must have 3 reaction force na? because of three restrictions in a 3-d plane then why sir has shown only 2 of them. Although the third one will be 0 but it has to be depicted in exam paper right?

[@nazrulnaz4744]

Sir ..which type of beam has Negative shear force and -ve Bending moment diagram always ?? 1) Cantilever 2) Overhanging 2)simply support 4)all of this

[@chandalam4437]

Sir in Fig you are not consider weight which is acting in downward direction

[@RAJKUMARYADAV-gw2uz]

Respected sir Syllabus SSC je ke exam tk complete ho gyega please.... suggeste sir........RRB JE , UPSSSC JE limited time hai sir 23 September ko SSC je ka exam hai Sir ..aap ka lecture very helpful ho rha hai sir .....plz sir something do sir

[@Education-js1sx]

Truly said.. very helpful

[@sonukumar-tz1ht]

Ssc je ka date aa gya kya?

[@sumitrana4875]

sir I think that shear force at point B is not zero according to graph 34:07

[@sameerbhakare3983]

Tnx sir for vdo

[@naushadworld000]

At 31:00 how SF AT C = pb/L -p = -pa/L ......

[@NirmalNikhil]

Ra+Rb=P.....eq 1 Ra=pb/l and Rb=pa/l Ra-p=-Rb( from eq1 and put the value of ra and rb in this we get) pb/l-p=-pa/l

[@haridwarsingh6220]

Ossam lecture

[@angshumannayak5337]

Sir Moment of inertia per kuch video banaiye na

[@abinashkarmakar360]

Sir civil ka concrete ka video kab se suru hoga

[@mikuftmina3736]

World class lecture sir! Why does the intro sound like metallica?😂😂

[@rakeshmal7970]

Sir pls upload som syllabus as soon as possible... Rrb je ke liye

[@SAURABHKUMAR-nx6wp]

sir i have a doubt in last question sir why not conisder centroid as a point load for shear force yani sir jis tarah se point a aur point b pe shear force nikale hain us tarah se centroid pe bhi nikal sakta hai before centroid and at centroid

[@shremiemotion]

Good morning sir................. From equation 1 ra ka value kaise nikale hai us me b ka koi term hi nhi hai sir......................... Please reply me......... I am waiting for your response sir................. Awesome teaching sir............

[@AnkitMaurya-gs2po]

Sir , I have a question that the value of Ra =P.b/L How is the possible if Ra+Rb=P and Rb=P.a/L....... According to me Ra=P-Rb Therefore, Ra=P-[P a/L]=[PL-P a]/L Plz explain it....🙏🙏🙏

[@akashprajapati2141]

Love you sir.....,🙏🙏🙏

[@itsok85]

Thank u so much sir Please upload next video sir...please... Please....

[@CiViLTechinformation]

sir ans maximum hoga kia ?

[@Inazuma11cool]

Sir 53:20 me just after B hoga... Before nhi.. Before to kuch hai hi nhi

[@venugopalsharma1945]

No dear hum right to left move kar rahe hai

[@Inazuma11cool]

@@venugopalsharma1945 tq sir 🙏

[@anidhyagupta1523]

Sir, in case of UDL SF at A will be 0 and SF at just before A will be WL/2

[@knowledgehub4685]

No

[@ghousebabu9270]

Sir please continue lectures daily sir pls complete som lectures sir pls...

[@Prabhatkumar-nv4yk]

Compelet this topic plz sir all module 9

[@vandnasharma7227]

Sir if we are calculating from right to left graph is changing

[@bharatsharma5758]

Sir cantilever beam with UDL kaa jo aap n SFD draw kiya hai I think bo negative hoga "-wx" Maximum value hogi "-wl"

[@bharatsharma5758]

Time at 47:42

[@manishmahala7476]

Bro hum right se left gaye hai to jo down hoga vo +ve hoga and jo upper side hoga vo negative hoga to equation hogi -v+wx=0 V=wx

[@mridupawanbaishya210]

But sir, the direction of shear force would be opposite to load, so P i.e upward. So should not it be negative if coming from Right to Left?

[@calderanoadi5982]

Yes exactly same doubt

[@amitkr.kushwaha797]

Sir som thoda jald complete kijiye n..,... Please

[@bhanusingh2200]

Thnx sir.

[@mohdsamsul8194]

Sir simply supported beam me section kyu nhi liya

[@wblandinformation9832]

sir point C pe kaisa -pa/l aya hn?

[@rakeshmal7970]

Sir pls rrb je ki som ki syllabus complete kijiye....

[@rakeshmal7970]

Please please please sir.. 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏

[@prakhargupta6278]

THANKS SIR

[@SandeepSingh-dx5kl]

Sirr in case of cantilever beam isn't sfd be - ve

[@haribhajansingh7934]

Thank you sir

[@artistic-v8411]

Try to solve the assignment given in the lecture

[@RahulKumar-hn2ox]

For cantilever beam SF =(Wx²)/2L Here the equation is in 2nd order so the nature of sfb be parabolic Sf at support =WL/2 and at free end sf =0

[@RahulKumar-hn2ox]

FOR SIMPLIY SUPPORTED BEAM SFD IS PARABOLIC IN NATURE SF=Wx²/2L

[@anirudhdogra4300]

Can you solve one question? Related of shear force and bending moment dia?

[@mr.s9055]

Can you provide shear force equation Method at X distance?

[@aryatech1280]

Nice sir

[@manojnagsharma888]

I think this time u rushed a little bit sir. I didn't get some while explaining Sfd diagram

[@brijeshsinghadhikari6559]

Sir plz som ke khatam lar dijiye

[@vedprakashgupta6302]

Sir som ka next video kb tk aaiga

[@artistic-v8411]

Jaldhi

[@vedprakashgupta6302]

Sir jo pd \gd cource civil ka prepare ho rha usme aap v class ligia n atleast som aur hydraulics ka plz sir

[@rakeshmal7970]

Sir pls strength of materials ki video jaldi upload kijiye...

[@sarvendrasingh9771]

Sir starting me B pe x=0 liye But SFD me B pe x=L kaise le liye???

[@akashprajapati2141]

2rbl/3+wx^2/18

[@deepanshuvashisht1409]

Sir, Does Gate Academy plus has any paid course online or test series ??

[@bharatsharma3306]

Plzz upload next lectures