The Kinematics of Simple Harmonic Motion (part I)

[@sachin211190]

Well.. You are a pure genius.. I don't know what is motivating you to keep doing this, but whatever it is, please don't stop posting videos.. The world needs people like you who think about others.. Even people who get paid cant make videos like these.. Thanks again

[@oshainross5536]

I was having trouble with this. You explained it very well. Thank you.

[@thesladeeffect]

Just wanted to say that although our professor basically goes over the exact same things in the same format, I have a very hard time understanding it in class. Going to your channel, you make things much clearer every time. Also, I DO study my material on a daily basis, do not procrastinate. Thanks a lot, lasseviren1, you really are doing a great service with these videos.

[@arslna7731]

I love the way you teach, thank you so much.

[@anilsinha4968]

Thank you very much. Didn't know for what purpose was this chapter being taught, why were different quantities being introduced and why circular motion analogies were being taken,makes sense now.

[@freelance1889]

Awesome explanation sir🙏🙏👍👍👍👍

[@ull893]

I have to Thank you for this amazing video, this was a concept i was trying hard to understand but could not, but you explained it such an ease....you are an amazing teacher..especially the part that how we shm is an extension of simple circular motion and how A= cos (theta)..thank you again

[@velolalola]

thank you sir,,,now i am more understand how to get all the equation.you are a good teacher.thumbs up.

[@khoatran08]

simply amazing! thank you!!

[@jnaziri2]

really a wonderful teacher.

[@ermiasmerine5304]

Thank you so much. Now I actually have a chance to get into AP next month.

[@rosaiahmarapaka8966]

Good explanation

[@farhadnoori8546]

very helpful and good explanation. thx

[@HispanicMajority]

You are amazing! solid explanation!

[@ladalmehar7678]

Good job

[@mohamednoor2567]

you really helped me alot. Thank you very much.

[@8Aetos]

Very helpful! Thank you!

[@tahsinahmed7585]

what about the phase constant

[@Cowboys2SB]

great video

[@OMEGAPRIMe4287]

Would you mind making a video in this similar fashion showing how to get the phase angle I understand the x=Acos(wt) but where is the phi in x=cos(wt+Φ)

[@SailaMaham]

Thank you so much! I have an exam tomorrow and this definitely cleared out all my doubts ! :D

[@Mohamed_zyd]

I have an exam tomorrow, too Six years after you 😂

[@berkant987]

@@Mohamed_zyd 2 years later, now I have an exam tomorrow.

[@Li8en_Candle]

Thank you

[@AnujFalcon]

great u got a clear idea what my teacher doesn't thaq a lot

[@Supersaiyantobi]

Why does my textbook say. X = Asin(wt) Instead of cos?

[@lasseviren1]

It depends on the initial conditions. If the object is at x=A when t=0 then you would use x = A cos(wt). If the object is at x = 0 when t = 0 then you would use x = A sin (wt). In fact, if the object is at x = -A when t=0 then you would use x = -Acost(wt). Take a look at the shape of the following four graphs and it might make more sense: x= Acost(wt), x=-Acos(wt), x=Asin(wt), and x=-Asin(wt).

[@faridchardonneret661]

thnx , u saved a life

[@vinnienauta]

what is that app ?

[@i.d.s5703]

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[@whatisyournamestupid]

THANKSSSSSSSSS

[@SamsherSinghJoon]

chore kamal kar diya ------ meaning------- hey dude!!!! awesome fu*******k

[@chg_m]

nice proof

[@TrojansFrightOn]

damnit why did i have to find these videos with only 19 hours until my test :(