How To Calculate Normality & Equivalent Weight For Acid Base Reactions In Chemistry

[@TheOrganicChemistryTutor]

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replace oh with h...count how many replaced..and multiply the no. with given mass of compound...done. And for equaivalent mass , divide molar mass with the the no of replacebale oh with h, the same way u did with normality

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Professor Organic Chemistry Tutor, thank you for an awesome Introduction into Normality for Acid Base Reactions in AP/General Chemistry. The definition of Normality along with the practice problems/examples are off the learning charts. This is an error free video/lecture on KZbin TV with the Organic Chemistry Tutor.

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It helped me a lot and also now I understand normality concept a lot better. Thank you for your tutorial video!!

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can you tell me what the solution for this question 👇 A 3.0 solution of aluminum sulfate Al2(SO4)3 Normality what the molarity???? Can you answer please I need it too much I have an exam tomorrow 🙏🙏🙏🤕🥺

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@@OctobrTea I think its solution will be 0.5 but there is no option for that in the exam

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8:45 for finding ew first find the m.m then divide it by num of oxidation state,you will get the answer by this simple method

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10:07 we can directly do using N= M*n

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I'm confused rn is the atomic mass of Ca 40.08 or 40.078????

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[@xami8155]

At the first method of getting the Normality, Where did you get the 1when solving for the Molarity?

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In 12:34, what if CaCO3 (Calcium carbonate), I will times to three or one)

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[@sherlockholmes6803]

can you tell me what the solution for this question 👇 A 3.0 solution of aluminum sulfate Al2(SO4)3 Normality what the molarity???? Can you answer please I need it too much I have an exam tomorrow 🙏🙏🙏🤕🥺

[@aaaamxr]

@@sherlockholmes6803 normality is molarity multiplied with n factor. So molarity will be normality divided by nf. Normality is given 3.0 and nf of aluminium sulfate is 6 (charge on cations ot anions is the nf for ionic compounds.) Divididing normality 3 by nf 6 gives 0.5 which will be the molarity

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[@atomgaming1413]

You discuss acids and bases and great job 👍🏻, but in case if there was not an acid nor bases how can i find the Normality of that solution?

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there will be salt given