Normality & Volume Solution Stoichiometry Practice Problem

[@TheOrganicChemistryTutor]

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[@K379-b3j]

I can't thank you enough for this simple yet so useful video. I failed general chemistry last semester and am repeating the course now, but my new teacher says we have to learn everything ourselves because that's how the new educative system works. I've been struggling with a simple problem about titration and was feeling seriously dumb because it took me days to solve it. thank you, THANK YOU.

[@kirinkukumikajikanuku9470]

this 2 minute video literally saved me from failing my quiz, thanks a lot! Please make more videos, you're a great tutor!

[@catloafstudy]

at first i felt threatened by the question, then i thought about it and realized its really straightforward! thanks!

[@georgesadler7830]

Professor Organic Chemistry Tutor, thank you for a short video on Normality and Volume. in AP/General Chemistry. This is an error free video/lecture on KZbin TV with the Organic Chemistry Tutor.

[@TheOrganicChemistryTutor]

You're welcome

[@abdulazeez5423]

Thanks for making it simple❤

[@hao.1991]

thanks for this 2 min video!

[@ahmedokasha7462]

What about reaction ration ?

[@triple_gem_shining]

The fundamental idea behind gram equivalents and normality is that one gram equivalent of an acid reacts with one gram equivalent of a base. This idea eliminates the need of using molarity and thinking about mole ratios for any acid base titration.

[@johniman1689]

What about balancing the equation

[@triple_gem_shining]

The fundamental idea behind gram equivalents and normality is that one gram equivalent of an acid reacts with one gram equivalent of a base. This idea eliminates the need of using molarity and thinking about mole ratios for any acid base titration.

[@triple_gem_shining]

molarity and normality problems are so easy xD

[@janhvinarayan1633]

why did he write that N in numerator and denominator ?

[@triple_gem_shining]

its just convention, they cancel anyway.

[@anujkumar-xr8rn]

shouldn't it have been 76.4mL

[@politecnico_socratico]

I think so, yeah. The equation he uses assumes that the number of H+ is the same as the OH-. In this case H2SO4 has 2 H+ ions and NaOH has one OH- so this would def change the result to 76mL

[@aster3625]

@@politecnico_socratico nope there is a big difference between normality and molarity, and yes this might confuse you.. In our case, normality "already" takes into account the number of H+ ions in H2SO4 thus there is no need to multiply the left side of the equation by 2 . To not confuse you Normality = molarity x number of H+ions or OH- ions. If in this given problem we substitute all values of normality to molarity, then the answer would be 19.11. It should never be 76.4 mL. I think im right, feel free to comment.

[@aster3625]

kzbin.info/www/bejne/fnvZcn95mLCMd8U

[@triple_gem_shining]

The fundamental idea behind gram equivalents and normality is that one gram equivalent of an acid reacts with one gram equivalent of a base. This idea eliminates the need of using molarity and thinking about mole ratios for any acid base titration.@@politecnico_socratico

[@shramshafeq6432]

nice