Thermodynamics - 4-3 Conservation of Energy in constant pressure process

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[@emirbfitness]

minor typo, p2= p1 which is 175KPA not 125KPA i’m pretty sure all the answers are right tho

[@sunmichoi6888]

Thank you so so so so much!

[@kylecatman7738]

"Isolated" means no heat or work transfer, this only says "insulated", so yes there is work but no Q.

[@mangoharun]

hey man did you understand why we didnt add the Work boundary in the energy balance formula. We Have shaft work + electric work and word done by piston movement which is boundary work but he didnt calculate it

[@ishmail1472]

@@mangoharun I'd like to know this as well

[@wereleymereley7233]

amazing work 👍🏻thank you!

[@gamingclips1901]

Genius

[@simphiwesnobolo7695]

the pressure in state 2, is it not suppose to be 175 ?

[@engineeringdeciphered]

You’re right. Should be 175, I think I misread my handwriting there. I think everything else is probably correct though.

[@jktification]

I tried to do this only using P x delta V. My delta V came out to a smallish 2.372 m^3. Multiplied by the constant pressure of 175Kpa yielded just 415 KJ of work. Why can’t we get the answer this other way?

[@Azakadune]

If you are doing it that route make sure you use internal energy u, not enthalpy h. Enthalpy contains boundary work for constant pressure processes.

[@iadll3]

Thank you for this work, But I want to ask for the formula sheet cuz I have an exam on three chapters (4,5, and 6)

[@engineeringdeciphered]

I just let my students create their own formula sheet on an index card. Unless you’re talking about the unit conversion sheet or property tables?

[@iadll3]

@@engineeringdeciphered I meant if there was a sheet for all formula like a summary , and also the unit conversion sheet

[@engineeringdeciphered]

I don’t have a formula sheet, but here is the conversion factors: www.dropbox.com/s/gb23smh0c5glzyc/Conversion%20factors.pdf?dl=0

[@iadll3]

@@engineeringdeciphered Thanks

[@JonathanMartinez-ge4rg]

for h I got 44.36+0.5(2240.6)=1564.66 this should get me to the final answer got that from table

[@engineeringdeciphered]

Argghhhh... I accidentally wrote 125 kPa for state 2, but that should be 175 kPa. I think that should work!

[@syarizahnorhashimah833]

hiii, what do you mean by interpolate? thank you

[@engineeringdeciphered]

I have a video about interpolation kzbin.info/www/bejne/Z2qVpaWPo6d2idk

[@syarizahnorhashimah833]

@@engineeringdeciphered you have helped me a lot! Thanks!