Thermodynamics - Pressure example 2 manometer

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Change in pressure due to depth.
Fluid manometer height.
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[@i3enjaminmejia66]

this video just proves how absurdly confusing the imperial system is

[@5thHeelToe2nd]

We really appreciate you, I am getting ready for a test and your videos have helped immensely. Thank you for you devotion to teaching / instructing. Subscribed and will follow closely.

[@azam8031]

Thank you very much 🙌

[@beshoymtsu2143]

Thank you!

[@rizzmechanics]

Thank you

[@mothug978]

Hello professor, awesome lessons, clear explanations. One question: since you add as you go down, but if you were to go up (from left to right), would you put a negative sign instead? Thank you!

[@engineeringdeciphered]

Yes, Anytime you go down - add. anytime you move up - subtract.

[@alvinlin8140]

@@engineeringdecipheredbut you went up when you went from the water to the Mercury so shouldn’t you be subtracting in that part? I can elaborate more if you want

[@engineeringdeciphered]

@@alvinlin8140 I think you’re talking about the part where I was going through the air. In that part, yes, going through the air you would technically subtract the rho g h of air, but we can neglect any gas because the rho of gas is much much smaller than the rho of the liquids. So I just skipped subtracting the rho g h of air. (you could do it, but it would be a very small number)

[@alvinlin8140]

@@engineeringdecipheredok gotcha thanks, my prof hasn’t gone over examples so this is helpful! One more thing, the pressure of a gas is negligible but in the question we are finding the pressure of the natural gas, can you explain that?

[@engineeringdeciphered]

@@alvinlin8140 well, it’s the change in pressure (due to height change of a gas) that is negligible.

[@PrincyGaming14]

how do you put in the calculator, mind was to far to your answer but I put the same input? thank you

[@tonyatilano7057]

let me know if you find out have my exam tomorrow

[@willowdesk]

just a thought, but the question is asking about pressure IN the pipeline right? not on the natural gas itself? so why wouldn't you also subtract the natural gas in the tube touching the mercury?

[@angrycyclone4353]

Because its a gas and gases have such a low density and are negligible

[@kennydalid9438]

can you post a downloadable soft copy of this convertion table

[@engineeringdeciphered]

www.dropbox.com/s/gb23smh0c5glzyc/Conversion%20factors.pdf?dl=0

[@kamranhafeez4269]

@@engineeringdeciphered Thank you so much

[@Miistik]

how do you solve it using ft instead of in?

[@alexisperry6010]

I’d convert it to inches

[@Jakeboi05]

Absolute pressure is gauge pressure + atmospheric pressure right??

[@engineeringdeciphered]

Yes!

[@nehemiascaban2461]

What app do u use on tis video? Btw, nice problem!!!

[@engineeringdeciphered]

NotesPlus

[@nrazzak8854]

at 4:40 why did you use 32.2 ft/s^2 instead of 9.81m/s^2

[@audufaisal728]

its not in S.I units

[@user-cl3rr6uq4l]

Can you send me conversion factors please 🙏 I need him

[@engineeringdeciphered]

www.dropbox.com/s/gb23smh0c5glzyc/Conversion%20factors.pdf?dl=0

[@user-cl3rr6uq4l]

@@engineeringdeciphered thanks 👍

[@carlosalzhrani4564]

What if we replace air with water what will be the height of it.

[@engineeringdeciphered]

You see in the problem that I neglected the part with air because it’s density is so small (compared to the others). If the air was water, then you would do the (rho)(g)(h) of that column as well, instead of neglecting it.

[@carlosalzhrani4564]

@@engineeringdeciphered I got the part but what I ment is that what will be the height if we replace air with oli for example.

[@engineeringdeciphered]

So for that type of problem you would have to be given the pressure of the natural gas. If you know that pressure and you don’t know the height of the right column - it’s still the same process and similar equation. Now h is the only unknown in the equation and you can solve for it.

[@carlosalzhrani4564]

@@engineeringdeciphered Thank you 👍

[@gump7237]

letsss go