Tips For Triples

[@Frie_Jemi]

with the regularity of videos, exposure to all the variants, the plan of a possible online puzzle webpage, you guys amaze me with the fact you do ANY viewer requests. you're WAAAY ahead of the game in my book

[@josephle5373]

online puzzle webpage is out, working and fun to side by side do sudokus :) awesome

[@ragnkja]

I love the name you gave this file.

[@sharonb7256]

You go so fast! I've watched five of your videos and wanted help specifically with triplets. You solve them without showing us how. I don't care if you go fast on obvious cells, but slow down on triplets. Thanks

[@israelaviles8909]

I want to learn about hidden triplets

[@crazypomp927]

Completed in 24 min. Nothing exceptionally tricky or difficult but a nice puzzle nonetheless. It's annoying though that despite spotting a lot of things before Simon, he still finished in about half the time.

[@maginpanic]

There's this thing that bothers me at 8:01 I'm trying to focus on triples like this one and apply one more rule to exclude something. There's 257 with 27, 57 and 257. I'm thinking of excluding 7 from the last cell. I don't have any bulletproof theory for that but in the last 10+ situations I had, it was correct way of thinking including this one here. I'm wondering if I can use that freely or if I was just lucky

[@MyReligionIs2DoGood]

Triples work just the same way as doubles, only on 3 cells instead of two. This means if you have 3 possible numbers that share exactly 3 cells, none of these 3 candidates can go anywhere else. Same goes for quads on 4 cells as well, quintuples on 5 cells, and so on, as long as the number of candidates matches the number of cells they share. Edit: Also, no other number can go into the shared cells but the candidates.

[@mary-alicetully9843]

How did you put that 3 in the central box?

[@ManiacalKiwi]

One of the easier puzzles I have seen on this channel.

[@ronmasters751]

4:17 after import to Joy of Sudoku, which allows auto-pencil and selected number coloring.

[@Skylooo]

a really elite video.... (check the length)

[@e1211]

At 4:03 i used the singularity glitch at r1c2 because it can only be 6 or 8 and if it's a 6 then r1c3 is 8 and you have non singluarity due to the rows 9 7 5 1 and c 2 and 3. putting 8 there solves the glitch and all of the puzzle.

[@Wecoc1]

That would be a Type 1 UR , right? Nice shortcut.

[@e1211]

@@Wecoc1 yes, the square could be 6 or 8, but it can't be 6 so it's 8. The other cells in the unit aren't immediately affect by that logic, only by the consequences.

[@ajaxmajor]

that's what i was thinking too. uniqueness is my favorite trick bc it's not even like a strict logical deduction. it's just "oh i hope the setter didn't mess up"

[@mauette2000]

The problem with these explanations is that for some people a hidden triple or quad is embedded in a row, col or block AFTER the sudoku is almost filled. His technique is emergent and actually masks the sheer presence of the triple or quad. As the solution progresses no where do you actually see a marked in hidden triple much less quad. Frankly these videos are so advanced I can't imagine anyone learning from them unless they are already advanced users.

[@efraiimssoon]

I really like this channel, keep it up! :)

[@DAVIDWILLIAMS-fx2nr]

Mark, when doing fiendish sudoko I always get to the point where I am left with all the unknown squares being two possible variables. When you get to this point is the only option to guess 50/50 and see if you are right? I've heard you say in the past 'let's assume this is X’ and continue on from there. But isn't that another way of simply guessing.? Or, is there always a logical mathematical solution without guessing/assumption?

[@MyReligionIs2DoGood]

At this point, I'd look out for possible Y-Wings and XY-Chains. CtC got a number of nice videos on those. :) On your second point: No, this is not guessing. It's a logical chain of conclusions, not assumptions, comparable with a If>Then line in a computer program. When Simon says 'let's assume', it is just a figure of speech. In fact, this is pretty much how the scientific method works. A hypothesis is formulated (X is true) on the basis of observations (only X or Y _can_ be true), then predictions are made and tested (what must happen _if_ X is true?), and if the results contradict known facts (the numbers already in the puzzle) or rules (no doubles), the hypothesis is wrong (X is not true). The other way is to show conclusively that all alternatives to the hypothesis must be wrong (Y is not true, therefore X). The last method works in Sudoku because we _know_ there are maximally 9 possibilities and what they must be - unfortunately, we don't have that luxury in the real world (we do _not_ know all possibilities), so we can use it there only to a certain extent. ;)

[@mauette2000]

his approach literally disassembles the triple before it has a chance to fully present at a solution point most people arrive act.

[@M4ke4l]

At 7:30 i spotted you can break the puzzle with a uniqueness:once you place the 8 pair in the bottom left block you can deduce none of those 2 squares are a 6 : if you look at the 2nd & 3rd column you have 1-8 , 1,2, & 2-6 pairs there, once you placed the 8 pair in bottom left block you can't place 6 there because then you would have no way of knowing wich one is a 6 or a 8 anymore because of the previous 3 pairs. then you can place the 6 in the remaining place of the bottom left block and it destroys the puzzle.Pretty beautifull way of finishing imo so i'm sharing.

[@FunnyMan3595]

You can use that much earlier. At 3:40, as soon as you see a bunch of doubles going down column 2+3, you can chain them together and see we have 8+1, 1+2, and 2+6, forming an almost-complete cycle that's just missing a 6+8 pair. If you look at the bottom-left square with that in mind, we can't put 6+8 in row 9, or else we'd complete the cycle, and have two solutions. Therefore, either 8 or 6 must be in column 1. 8 is already present in column 1, and 6 is present in row 7, so you can immediately place a 6 in c1r8. That chains to the 5+6 pair in r4, and solves c1-3 completely.

[@fmakofmako]

I'm happy to do the puzzles presented, but if I recorded myself solving it my video would be 20 or so minutes long. It's nice to see how you clump numbers, reduce sample spaces, and hunt for certain patterns so quickly. I get there, but I'm working on my solving speed. Btw what software are you using?

[@ucthanhvu836]

It's Duncan's Sudoku Solver. You can find the download link in the description.

[@fmakofmako]

@@ucthanhvu836 thanks so much. I should have known.

[@eireannsg]

That was an easy one but it seems that the NY Times hard Sudoku, 20th of May, seems to be impossible to solve by pencil marking twins (Snyder) or triples.

[@andrewrogers9822]

eireannsg THANK YOU. I’m struggling so hard with today’s.

[@eireannsg]

@@andrewrogers9822 In the end I noticed I overlooked a hidden one in c4r7

[@adrianmcl]

Please someone: is there a link to this puzzle? Can't see it.

[@JohnSmith-rf1tx]

On Cracking the Cryptic videos made before they developed their software to play the puzzles, sort the YT video comments by new and someone named Julia seems to be going through the old videos and putting up a link to play them.

[@adrianmcl]

@@JohnSmith-rf1tx Thanks for the tip!

[@ajchat8701]

At 8:50...how can 7 be confidently placed?

[@Max_Alive]

Because 5 and 3 are in the same column

[@asknickfilms1]

Ajchat on row, the 1/8 pair makes it so only 3/5/7 can be placed. On the column, there’s a 3/5, so the only remaining number is 7. Hope that helps :)

[@ajchat8701]

AskNickFilms ahhh...now I see it. Thanks

[@CrackingTheCryptic]

Because of the 1/8 pair in row 1, the only numbers left to place are 3/5/7. But, if you look down column 6, there is already a 3 and a 5 in the column. Therefore the only possibility for row1col6 is a 7.

[@Darek97]

row 1 needs 3,5,7 to place. Column 6 has a 3, 5 in it so only 7 can be placed in the intersection of the two

[@stanvandervoort2240]

at 7:20 you can place the 5 in r9c3 only by looking at columns 2 and 3

[@kennethirving]

I disagree; the uniqueness pattern can be seen as early as 7:07, as soon as the bottom block is seen to have 568, since there are pairs 18, 26, 12 above the 68(plus 5) pair. This was also noted above by makeal and maybe others. I'm a big fan of CTC and Simon's methods and explanations, and can't wait for more (non-variant) Sudokus!

[@kennethirving]

​@@AnonimityAssured If r9c3 is not 5, then that leaves a 68 pair in r9c2 and r9c3, and the 4 paired cells can be resolved either way.

[@kennethirving]

​@@AnonimityAssured If r9c3 is not 5, then that leaves a 68 pair in r9c2 and r9c3, and the 4 paired cells can be resolved either way.

[@normanndaba8823]

C1/R5 how did he know that is an 8 ? 🤔

[@yashrocks31]

bcoz of the pencil-marked 2s in R7,R8-C1

[@mary-alicetully9843]

Never mind I just saw it

[@nicokuhne3255]

Leet

[@Oblivion776]

Glad to know I wasn't the only one who noticed that!