If memory serves, Hunt used projections onto Walsh distributions to finally pin down the convergence properties of Fourier transforms in the early 60s (or maybe 70s). Maybe you could make a special exception for them. (ps Hunt was a great hand ball player, but often Phelps was better; however, Hunt could understand the "corner walking" vibration functions for certain degenerate ball shots into the corners.)
@juanmolinas3 жыл бұрын
Greetings Doc!, you explain very well, and your english is very clear!
@mudkip_btw3 жыл бұрын
I prefer f "snek" for the tilde but "squiggle" works as well I guess
@rounaksinha53093 жыл бұрын
Very nice explanation,sir. Thank you very much!
@sabhrant55333 жыл бұрын
For those who are interested in this topic, you can refer to "Introduction to real analysis" by Bartle and Sherbet, 4th edition. The continuous extension thm is given on pages 144, 145. Sir, is it possible to extend this result to higher dimensions? (like the boundary of an open set.)
@arturcostasteiner97353 жыл бұрын
Yes. And also on the complex domain.
@rikthecuber3 жыл бұрын
I don't know much on calc 3(except the very basics) but can you suggest me a video on cross product of 2 vectors w/o converting into components?
@رشاداليامي3 жыл бұрын
Doctor , do you want to tell us new definition for cont ?
@رشاداليامي3 жыл бұрын
Or definition cont on set bigger than last set
@ZipplyZane3 жыл бұрын
I'm not sure I understand how an endpoint can be continuous. Can you have continuity on only one side? In other words, in the first example, can we say ~f is continuous at x=0 because lim_a->0+ (~f(a)) = ~f(0) ? Or is it only continuous because x sin(1/x) is continuous on all point of the interval (-1,0) as well?
@drpeyam3 жыл бұрын
Yes, it’s called one sided continuity, so here f is continuous at 0 from the right
@sparshsalodkar61773 жыл бұрын
Glad I subscribed! ✌️🤝
@HaCkeMatician3 жыл бұрын
Hello Dr.Peyam! I want to ask about the oscillating sequences: what is the mathematical importance of the central value of oscillation? Should we have to know its value? Thanks
@sieni2213 жыл бұрын
Wow I just had this last week in topology class
@رشاداليامي3 жыл бұрын
We redefine the function on the extended set to get the extended connection Is correct doctor?
@arturcostasteiner97353 жыл бұрын
Yes.
@66127703 жыл бұрын
I expected the proof to use reliance on a Limit existing AND all derivatives existing, as you approach the end of the domain segment.
@flowers96522 жыл бұрын
Hello sir, thank you very much for the videos they are very very helpful for clearing the concept, but I have a doubt in this last minutes of the video you showed that if x -> a then (f^~)(x) -> (f^~)(a), I completely understand the part where you showed that the limit exists and is unique irrespective of the sequence we choose, but I have doubt that how can we be sure that the limit say S obtained is same as (f^~)(a), I.e. S = (f^~)(a)......???? Waiting for you reply.. Thank you😇😇
@dr.rahulgupta75733 жыл бұрын
Very good lecture. Thanks Dr 3.14159....m .
@satishr82883 жыл бұрын
Here is an interesting question I came across ' how many Spheres of 1 cm radius will fit inside larger hollow sphere of 1meter'.
@chrisglosser73182 жыл бұрын
Tune in for the math, stay for the dad jokes :-)
@shahinjahanlu21993 жыл бұрын
Sometimes life is just sinx/x near zero
@drpeyam3 жыл бұрын
Hahaha
@shahinjahanlu21993 жыл бұрын
@@drpeyam باور کن
@pierreabbat61573 жыл бұрын
~f(0)=0 ~f(x)=sin(1/x), x∈(0,1) ~f(x)=sin(1)-(x-1)cos(1), x∈[1,∞) Also, what about analytic continuation?
@EmissaryOfSmeagol3 жыл бұрын
Wow the Doc does not accept extensions, that's harsh haha
@dgrandlapinblanc2 жыл бұрын
Not evident. Thank you very much.
@rialtho_the_magnificent3 жыл бұрын
I was wondering how Oreo is doing?
@drpeyam3 жыл бұрын
Oreo passed away in June 😞
@irinaignatova17993 жыл бұрын
Sorry for your loss :(
@iabervon3 жыл бұрын
It's not hard to show that sin 1/x is not UC, Let delta be 2. For any epsilon, let k be the ceiling of 1/epsilon. Then let x be 2/π(4k+1) and y be 2/π(4k+3). |x-y| < epsilon and yet |f(x)-f(y)|=delta.
@yoav6133 жыл бұрын
I think this video is just an excuse to say squiggle 😃😄