Yup, seriously. I hate not finding it before. This guy has so many "uncommon" things I love. megaAVR-0 uC, Linear Regulators and its internal implementation, etc. FesZ Electronics is very good too. They should make a few videos together.
@nerdgirl80293 ай бұрын
Best video thus far on this topic!
@SineLab3 ай бұрын
I'm glad that you were able to find it helpful! :)
@wbaldwin6662 ай бұрын
Im upgrading to a heat sink with a new SSR i had to replace in an infrared conveyor belt dryer. The new dryers come with heat sinks, mine failed after 19 years so i dont think i need the heat sink but after your video i realize a 50A 3-35vdc input and 24-280vac output probably needs it. Thank you
@ponemark Жыл бұрын
Picking the best mosfet when we get quotes for insurance we go to comparison sites, it would be handy to have one comparing specs of components save trolling through loads of data sheets.
@tonysansom Жыл бұрын
Excellent info. Very helpful, thank you!
@justovision Жыл бұрын
This issue has cost Sony and Microsoft millions. It's cool to see the calculations but the real world is messy.
@SineLab Жыл бұрын
Heat sinks are tricky to get exactly right. :)
@evanssteАй бұрын
This is truly a clear-cut video on this subject, and I love it. However, in my situation, I seem to have run into a bit of a snag with the equation. I'm using a high-power BJT that allows a maximum current of 30 amps. In my circuit, I've measured that it absorbs about 91 watts of power (I've rounded up to 100), and the datasheet shows a maximum operating temperature of 150C. Rjc is 0.5, and I follow your rule-of-thumb value of 1.6 for Rcs. When I plug these numbers into the equation, and attempt to solve for Rsa, the value is negative. Does this just mean that there is no heat sink, on the market, that could ever be used to cool this transistor at 100 watts? Or, perhaps, does this equation only pertain to a certain range of power components? The datasheet, for the transistor, claims that it has a total power dissipation of 250 watts. This is in the "maximum ratings" section. Because I'm only considering a usage of 100 watts, shouldn't I be able to keep it cool with a heat sink? I agree, with many others, that you, easily, have the best video on this topic. Keep up the great work!
@SineLabАй бұрын
If the equation yields a negative number for Rsa, then it's physically impossible to pick a heatsink that keeps the transistor within the temperature rating. At this point the only way to solve the problem would be to choose another transistor with a lower Rjc value, lower your ambient temperature, lower your power dissipation, or raise your maximum temperature. It might help to know what exactly the transistor will be doing. 91 watts is A LOT of power. This could potentially be OK if the load is pulsed and isn't continuous since there wouldn't be enough time to heat the transistor up. Depending on what you had in mind, some sort of switching solution may be more appropriate.
@kermitefrog642 ай бұрын
Nder if a form of a heat sink could be used for siding on a house to reduce heat.
@cnchow3235 ай бұрын
It is very nice explanation on all calculation and useful. do you have a template to do all calculations by inputs all necessary parameters? I like to get a copy if possible
@kgaugelomohlaloga9585 Жыл бұрын
Great stuff! Thanks so much
@SineLab Жыл бұрын
Glad it was helpful!
@ivolol Жыл бұрын
Where's the TO-3 example!?
@mayd3153 Жыл бұрын
Very good video! I subsribed to you
@SineLab Жыл бұрын
Thank you very much!
@Yorumcu633 ай бұрын
Tekrar seyret
@dryster123 Жыл бұрын
Where did you obtain the TO-3 heatsink?
@SineLab Жыл бұрын
From DigiKey
@davestech63572 жыл бұрын
Cute video but you screwed up the mounting of the To-3 transistor. Not too good. I have seen worse though.
@davestech63572 жыл бұрын
I wasn't going to tell you that your calculations need work, but.. At least what about the 5 Watts the regulator drives to the load? So your 7 Watts is actually 12 Watts plus.
@SineLab2 жыл бұрын
The entire system has 12 watts. The regulator drops the 12 volt input down to 5 volts, resulting in a 7 volt drop. In order to lose those 7 volts, the regulator dissipates it in the form of heat. In this case there is 1 amp so 7 watts. The load itself has to deal with those extra 5 watts, because it is the one with 5v on its input.
@davestech63572 жыл бұрын
@@SineLab Yes, so your power supply will see 12 Watts and the total dissipation on the 317 is also 12 Watts of heat on it. The transistor inside the 317 does get hot with the output load not just from collector to emitter voltage.
@SineLab2 жыл бұрын
P = I * V
@anonymouseniller6688 Жыл бұрын
@@davestech6357 so what you're saying is that the load dissipates no power at all?
@TheWeepingCorpse Жыл бұрын
@@anonymouseniller6688 yes *the load will* away from the lm713.
@erbenton07 Жыл бұрын
All the music does is distract from the information you are presenting. just because you can add music doesn't always mean it's a good idea
@The_Movie_Thieves3 ай бұрын
It's interesting how he doesn't give hearts to the negative comments. It's like he doesn't want to test and improve.