3D Mohr Circle.MP4

[@KickUpOfficial]

purdueMET not sure if you check this channel anymore but I just wanted to say thanks for all the tutorials! They really help with my mechanics courses and are the best tutorials out there. Thanks Mark :)

[@samaldacamel8003]

This is video I've been looking for the entire time. Such a great explanation.

[@syafiqridzuanable]

if you want the element's rotation to be the same as the the Mohr's circle rotation direction, the positive shear axis should be pointing downward.

[@J03lCola]

You are 100 times better than my prof I am paying. Thanks boss!

[@refayat7777]

Missed only 10 minute of lectures. Came home and looked at notes and book for 1 hour. Had no clue what's going on. Searched online and this video surely helped understand this section.

[@TATGemini]

Greatly appreciate the Instructional videos. I'm enjoying Mechanics of Materials more now thanks to this!

[@kakbar10]

your mohr's circle videos are great our lecturer explained it in a far more complicated way than you did thank you so much i appreciate all the great effort you put in these videos and like your shirts :P thanks again !

[@LineMUp321]

0.0 if only you were a woman my age who could have told me all of this you would be perfect. This mini tutorial just saved me hard on this assignment I have!

[@IBx27]

So THIS is what it's like not having an illegible chinese teacher for one of your fundamental engineering courses. Thank you for posting this.

[@purdueMET]

@gcass02 I am indeed a little busy these days, but am always planning more videos. Stay tuned for new ones. I'm glad they are helping you in statics. That's the first of the classes that teach you how to think like an engineer. Booyah!

[@aaaxfbhc]

Fantastic video. Really really useful. You make things seem so simple and understandable. You have my thanks.

[@jrnevesbr]

Thank you so much Professor! An old student from Brazil!

[@2007063]

you are a life saver. i love your videos. thank you so much

[@jesusbustos7128]

I like how he throws those damn magnets on the white board!

[@19hashan93]

That video made this concept so much more clearer. Thank you very Much :-)

[@sam59874]

Hi Mark, All your videos have been extremely helpful to me. I really appreciate your time and effort. Please do another video which explains how to calculate the angles for 3D Mohr's circle examples. That would be really great! Thanks again Sam

[@baudeagle1]

Is a 3d Mohr's circle equivalent to a VonMises stress calculation? Couldn't you draw this this "3D stress" graphically as a sphere? To draw this as a sphere the Sigma XY normal stresses would be represenated by the X axis of the graph as shown in this video, the Shear stress would be still bre represented by the Y-axis also shown in this video but the Sigma XZ normal stress would be represented on the Z axis of the same corordinate system. The sphere's outside surface is extreme condition

[@purdueMET]

@Zenjoksss No problem. Glad to help.

[@swayym]

Thank you so much! I have a final tomorrow and this was the last concept that I wasn't too confident about....

[@jinwoojung5880]

OMG!!! awesome. I understand your teaching. thank you.

[@adityamorey9251]

thumbs up if u think he's the coolest solid mech and statics prof ever ;)

[@bilalAhmed-vx8ut]

even though the video is 7-8 years old, it's still helping me. thank you. are you still making new content?

[@AnglBunny]

Thank you, you are our hero

[@pcliao5321]

how can i find a principle stress solution from any stress tensor in the 3D space? or, say, how to rotate arbitrary "box" to meet the principle stress "box" by using Mohr circles?

[@WorldOfWobble]

How about when sigma 3 does not equal zero? Can you still find the principal stress' graphically?

[@ermembro]

you do the same thing, and sigma3 is non zero, nothing change.

[@Clear7Flagrant]

@CallmePete89 The sum of the three stresses acting on the element MUST equal the sum of the three principal stresses. With enough information you can draw a 2D Mohr's circle, find the two principal stresses from that one circle and using the newly found principal stresses you can plug them into the equation where the sum of the experimental stresses equals the principal stresses.

[@harishli2020]

how to decide whether we need to rotate 22.5 degrees clockwise or counter clockwise

[@gohan100100]

How do you know when to use or draw the mohrs circle? Is it when you have shear stress & normal stress at a point?

[@mirrariswake]

this was really helpful. But how do you use a tension matrix into a mohr circle ?

[@Hatimoooo]

Thanks a lot sir ! Can you give us an example how to find directions of principal axes n1,n2,n3 with Sigma 1 , 2 and 3 different from zero ? Thanks again !

[@CGRLW]

How about when you have to find the 3d stresses with eigenvalues? there are times when you cant use the typical equations but I dont know when any help would be appriciated

[@solobassoon]

I do not quite understand the rule of thumb regarding tau-xy and tau-yx. Here tau-xy is 50 MPa. Is this not in the direction of the vertical arrow with only half an arrowhead? As it is mentioned tau-xy is the shear stress on the x-face in the y-direction and tau-yx is the shear stress on the y-face in the x-direction. But the arrow for tau-xy points in the negative y-direction and the arrow for tau-yx is in the negative x-direction. It confuses me a bit. So tau-xy is positive in the negative y-direction? And if tau-yx is -50 MPa in the negative x-direction then tau-yx is 50 MPa in the positive x-direction?

[@gohan100100]

if you assume that the 4th dimensions is time... I have no idea.

[@Cyphlix]

12:59 did he mean "assuming that I have plane stress"? why would you need to assume you have plane strain? Fantastic video btw :)

[@rishijai]

Dont let your head be a Mohr's circle of stress

[@Obyak]

What if we have a 4-D ?

[@purdueMET]

@2007063 Wow. You are most welcome - RMF

[@emilybradley6814]

Thank you so much! You are so clear!

[@vuba1000]

@CallmePete89 ...i guess the problem becomes complicated and is difficult to solve.so,we use a computer or something like that to solve it...and also i have never seen problems in which sigms(3) not equal to 0...in some standard textbooks...so that might not be a very important case.

[@Obyak]

Yes, time is indeed the fourth dimension. Thanks for the reply.

[@mohammedalameri4763]

So Iam wondering if sigma 1 and sigma 2 have to be bigger than sigma 3 in all cases ?! Or this is only when both sigma 1&2 are positive ??

[@punkson]

For plane stress, which is what we are doing here, you can plot the first circle then you have two principal stresses. The third principal stress then has to be at (0,0) for the condition where sigma z = 0. Either this is between the two so you can draw two smaller circles or it is outside the two so you can draw another small circle, then one encompassing both.

[@CallmePete89]

What happends when sigma (3) does NOT equal zero? say sigma (3) = 24, or -24. Thanks!

[@AndrewEG]

I'm dumbfounded! An American using the world standard measurement system! :O Great video by the way!

[@HaowenLiu]

Thanks a lot !!!! Finally under stand what is going on!

[@537jaga7]

what if sigma z is non zero?

[@mohammedalameri4763]

Then sigma x or y should be zero, because we are talking here about plane stress. and in plane stresses we have to assume that one of the sigmas is zero

[@mechanicalengineer7329]

537jaga this is the question ^^ ....

[@goranstojanoski2]

What happens when I got negative sigma3? How do I drow them? I got : Sigma1= 14.4 Sigma2= -4 Sigma3= -6.4 Kind Regards

[@carlosdrums1]

you just draw a circle where the minimun value is 24 or -24 and the maximum value is sigma 2, then draw another circle from sigma 3 to sigma 1 and the half of that will the maximun shear.

[@pooya130]

Great video thanks! Would have been even better if you had a voice recording device.

[@Zenjoksss]

cool! I like it! Thanks you professor.

[@SteveAnthony21]

Excellent Teacher! THANKS!! :D

[@sabinzmathew]

It was all about 2D Mohr's circle, where is 3D ?

[@zhd911]

YOUR AMAZING! thank you very much.

[@djbenny1]

thanks very much - great video

[@autogordel]

It's time for KZbin University and I want you to be principal. It's quite funny that I can find better and more efficiënt explanations on KZbin than TUDelft can provide me with.

[@MrJudgeGTO]

FUCK YEAH! NOT GOING TO FAIL ANYMORE

[@BWCmike]

HAHAHAHAHAHA look at his shirt "Mathematical advisory, Graphic content" then a bunch of graphs lmao

[@NaveenKumar-vz4fo]

sir can explin strin at a point ples sir

[@presidentstories1498]

Thank you sir

[@wrath90210]

My prof uses powerpoints... this is teaching prof...take a note

[@tommansfield775]

brennan cant pass

[@ojmayazo]

adamsın insansın

[@abrzz94]

THis is not For a 3d !!!!!! its a 2D ..

[@JohnSmith-zh6yk]

no, It is 3D but the stress in z direction equals 0.