Probability Lesson 5: Conditional Probability and Multiplication Law of Probability

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Күн бұрын

Пікірлер: 16
@brellington1999
@brellington1999 2 жыл бұрын
going through this entire playlist a week before my probability exam >>
@zonneP
@zonneP Жыл бұрын
literally me
@j83lin
@j83lin 11 жыл бұрын
Great explanation of conditional probability! Thank you!
@i_harib
@i_harib 5 жыл бұрын
Very helpful, keep up the good work mate!
@sunnysarkarwind
@sunnysarkarwind 9 жыл бұрын
Good explanation !
@tamaraharutyunyan3355
@tamaraharutyunyan3355 9 жыл бұрын
Your lessons are amazing!
@hachemouanes8751
@hachemouanes8751 4 жыл бұрын
thank you very much, you saved my worthless life. now I have one.
@hachemouanes8751
@hachemouanes8751 4 жыл бұрын
Yes I agreee
@uroztas
@uroztas 11 жыл бұрын
10/10
@samirelzein1978
@samirelzein1978 3 жыл бұрын
very good job Now redo with modern animations :p
@shilpawakharkar9179
@shilpawakharkar9179 7 жыл бұрын
thanks
@ginoy007
@ginoy007 7 жыл бұрын
Shouldn't P(AnB) be 3/6 instead of 3/36?
@teaadvice4996
@teaadvice4996 6 жыл бұрын
Have to point out that the dice table is wrong for permutation outcomes because you only counted the 1,1 2,2 ..... only once when they are needed to be counted twice
@StatCourses
@StatCourses 6 жыл бұрын
The diagonal elements have the same likelihood of occurrence as the off-diagonal elements. They are not twice as likely to happen as you suggested. P(LH=1, RH=1) and P(RH=1,LH=1) correspond to a single event in the sample space. We don’t need to count it twice. P(1,1) = P(LH =1) P(RH=1) =(1/6)(1/6)=1/36. Left hand toss and right hand toss are independent experiments.
@teaadvice4996
@teaadvice4996 6 жыл бұрын
Actuarial Path thank you very much for responding back and explaining, btw great videos
@mahmudnuraringim7950
@mahmudnuraringim7950 Жыл бұрын
@@StatCourses pls i didn't under the A intersection B
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