Yesterday, I soved this kind of integral, first method no doubr! Thank you. Any arbitrary function x can be uniquely represented as the sum of the form x(t) = xe(t) +xo(t), where xe and xo are even and odd, respectively e,g, : e^x = sinhx+coshx For those of you motivated by enthusiasm, you can get more information about it in The Single Most Overpowered Integration Technique in Existence. Flammable Math
@holyshit9222 ай бұрын
I would use odd and even decomposition of function f(x) = 1/2*(f(x) - f(-x)) + 1/2*(f(x) + f(-x)) 1/2*(f(x) - f(-x)) is odd 1/2*(f(x) + f(-x)) is even