Angles Formed by Secants and Tangents

[@lkkingamingz979]

Easy Yung pagturo Ni ma'am naintindihan ko😉 Kanina pa ako nood Ng nood eh

[@joysantos5974]

I'm glad you understood.

[@joysantos5974]

For the question: I got a little bit confused with this one||| (160-x)/2 =(50)2 160-×=100 160 -100=× 60=x Is the final answer wont be divided by 2 anymore? The answer is NO. You will not divide it by 2 anymore because when you multiply both sides by 2, the 2 in the denominator cancels out with the 2 that you have multiplied on it. Hope this makes sense.

[@joysantos5974]

For the question: Paano kung exterior arc and hinahanap? You have to do the inverse operations of all the steps. Multiply the angle by 2 and then add to the measure of the other arc. I hope this helps.

[@nur-aizaalamhali6501]

Hello paano kapag minor arc lang yung given, paano po makuha yung measurement ng angle and yung major arc? Thank uuu

[@joysantos5974]

@@nur-aizaalamhali6501 There are many possible illustrations to your question but you definitely need the major arc. I am thinking of a scenario where your segments are both tangents and so therefore, the minor are is a part of 360 degrees. So, you can subtract the minor arc from 360 in order to get the major arc. I hope this makes sense.

[@joysantos5974]

For the question, What if the given is the major arc, what is the measurement of the inscribed angle? Ans: The inscribed angle is half the measure of the arc that it is intercepting. It follows the last theorem that i discussed here. Hope this helps.

[@joysantos5974]

I also have a video of Inscribed Angles and Intercepted arcs

[@10pmcat60]

wait this kinda makes sense tysm for explaining it!! hopefully ill pass with ur methods

[@ihatelosing4740]

This vid helped out a lot, thank you!

[@joysantos5974]

Glad it helped!

[@joysantos5974]

@Rimi Irish Can you describe where the angle is? How I wish I could visualize the figure.

[@Eli-yu5dq]

intercepted po yung secant at tangent then may given po na number doon sa intercepted arc ang nawawala po is yung Inscribe angle, pero wala pong given doon sa mas maliit na intercepted arc

[@Eli-yu5dq]

kagaya po s’ya yung figure sa 2:00 yung pangalawa po sa ibaba,pero ang nawawala po is yung inscribed angle then ang given lang po ay yung intercepted arc na malaki

[@joysantos5974]

@@Eli-yu5dq Looking at the second example below, if the only given is the big intercepted arc and there is no description about that arc that is OUTSIDE of the angle, then you cannot get the measurement of the angle. Is there any other given information, like some parts being congruent?

[@Eli-yu5dq]

@@joysantos5974 there’s is no other given po Ma’am e, yung sa big intercepted arc lang po talaga

[@joysantos5974]

@@Eli-yu5dq You can answer this question with an algebraic expression like this: (160-x)/2. The 160 is the example for the measurement of the bigger arc, x is for the smaller arc, and when you divide by 2, then that will give you the measurement of the angle. This is all we could do. We cannot get any specific value for the angle. Sorry, I hope this makes sense.

[@Rayanisno.1okd]

Thanks you helped me a lot love you ❤❤❤❤❤❤❤❤❤❤❤😊❤❤❤❤

[@FariesLeo]

IT helped a lot thanks so much

[@PearlofGod_MLPPixel727]

This is great!

[@joysantos5974]

Thank you.

[@joysantos5974]

My channel has the complete lectures for Algebra 1, Algebra 2, and Geometry. I would encourage subcribing to get my currents updates. Good luck!!!

[@vincecoloma915]

From all of the vids i watched this is the only one that helped me. Thank you

[@joysantos5974]

Great to know! You're welcome!

[@tameremam5682]

Thank you

[@joysantos5974]

You're welcome

[@evelynn7853]

THJANK YU SO MUCH YU SAVE MY LIFE,, I WILL UPDATE YOU PO I WILL ACE THIS EXAM

[@Eli-yu5dq]

what if yung intercepted arc lang po ang given sa tangent-secant theorem then ang hahanapin po is yung main angle?

[@nathanfrick1962]

You saved me from an F. Thank you a million

[@jayallon5969]

Thank you so much😍

[@Illuminatedpk]

can you tell me what are the angles given ..is it the angle subtended by arc at the centre of the circle?

[@joysantos5974]

Yes. In this case, I identified the subtended angle by putting the "1" in it.

[@shinytears_]

this vid was helpful but like how do i make a real-life problem with this? 😭

[@joysantos5974]

Hi, Who Am I. There are a lot of actual applications of these theorems. For example, in architecture, engineering, gardening, baking, or any art project. One time, I was working on my yard and I wanted to have a perfect circular cemented area at the middle of my yard. I had to do some measurements and it may not be this exact theorem but angle relationships are all related to circles. Hope this helps.

[@notathing8206]

Pano po kung ang tanong po is to find the major arc pero yung given lang po is yung inscribe angle?

[@joysantos5974]

Double the measure of the inscribed angle to get the measurement of the major arc. You can watch my video on Inscribed angles and intercepted arcs, to see some examples

[@mialouise1982]

This was very helpful, THANK YOU!

[@rubiesantos287]

Hi, ma'am! I have a question po, paano po kung hindi po given ang value ng exterior major arc and yung minor arc and ang given lang po is yung angle mismo na 70°. Paano po yun? Bale ang ipinapahanap po yung value ng mga arcs katulad po sa 3:00

[@joysantos5974]

To find the bigger arc, multiply the angle by 2, then, add the measure of the smaller arc. The result is the measure of the bigger arc. I hope this helps.

[@helsavv]

This is helpful, thank youu

[@joysantos5974]

Glad it was helpful!

[@ken-fv9cz]

thank you

[@joysantos5974]

You’re welcome.

[@kimjarillo169]

Pano po ma'am kung sa secant angle, bigger arc lang po yung given?

[@PearlofGod_MLPPixel727]

This is a math topic is one I took forever to understand, but your video made it click almost immediately!

[@joysantos5974]

I’m glad it helps!

[@jacobkandchorov2694]

Thank you sm

[@rubiesantos287]

Ma'am, do you have fb or messenger account po ba? Para po sana i can message you privately and directly..

[@mikazukiaugus4596]

Tyyy po

[@joysantos5974]

You're welcome!

[@alexanderetrata8239]

Hi gab