AP Statistics Unit 4 Summary Review Video Part 1 - Intro to Probability

[@sleepingsnowleopard2453]

Seriously Mr. Porinchak is really getting me through my class, my teacher doesn't teach us well at all, but these videos give me confidence of understanding and passing my tests and exams

[@mporinchak]

I am so glad my videos are giving you confidence, keep it up!

[@barnabyinteractive]

super underrated. fantastic video, thanks

[@kalebmcgarry3595]

Love this content! Really helped me understand these concepts. Thanks Mr. Porinchak!

[@mporinchak]

Check out my ultimate review packet it may really help too if you need more practice! www.ultimatereviewpacket.com/courses/AP-statistics-ultimate-review-packet

[@lilyy-yg4eu]

this man is saving my life

[@zomgeek2236]

right i have a unit 4 test rn lmao

[@evingiamboy4337]

Looking at this the morning of the test. Wish me luck!

[@yuri_lvrrr]

same lol gl

[@abbyconcepcion8975]

did u gys passs 😭🙏🏻

[@Capesoda]

amazing content more attention is deserved this is the best AP stats content

[@mporinchak]

spread the word!

[@Capesoda]

@@mporinchak always will!

[@jeffreywong1260]

Hi! Why would we not subtract 0.1092 after adding 0.3108 and 0.1508? Isn't the probability that (A and B) = P(A) +P(B) - P(A n B) and P(A n B) equals 0.1092?

[@mporinchak]

because the question asked for the probability of purchasing EXACTLY one car. Which is very specific. Car 1 and NOT car 2 OR Car 2 and NOT car 1. It is not asking for probability of car 1 OR car 2. Does that make sense?

[@LukieReal]

i like thinking about it in the venn diagram. since we only want 1 car we are finding the probability of just A and just B, NO OVERLAPS! so instead of just subtracting one overlap we would subtract both overlaps. as you said the overlap is 0.1092, and two of those overlaps is 0.2184. 0.42 + 0.26 - 0.2184 = 0.4616! hope that helps

[@ToyotaGT8614]

this vid came in clutch

[@gunga834]

Question, for the two first car problems, could you have used a tree diagram for the first problem as you did for the second?

[@TheidiotAmongUs]

Thanks!

[@aaronmiranda630]

I have a question, arent the conditional probabilities and the multiplication rule recursive? if so, wouldnt you just end up with an identity statement unless you already know they're independent or not? because you can only prove they are mutually exclusive but you cant necessarily prove that they are one or the other (independent or dependent) without knowing the P(A&B) already? what is the minimum amount of information you need to be able to differentiate between the two?

[@lillrice27]

Im cooked

[@tmas9236]

why for the problem if she would buy on car or the other did you not just add them as if it was an "or" probability?😥(im cooked)

[@mporinchak]

@tmas9236 because when we use the word "or" we mean one, or the other or both. So when we say the probability of A or B, P(A or B), we are referencing only A, only B, and both A and B as well. So if we added them we get all three outcomes, but this question only asked for the probability she buys exactly one car, only A or only B. Hope that helps!

[@tmas9236]

@@mporinchak THANK YOU SOO

[@AKD-le2kb]

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