Cars move around the “traffic circle” (solved)

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Question Solutions

Question Solutions

Күн бұрын

Cars move around the “traffic circle” which is in the shape of
an ellipse. If the speed limit is posted at 60 km/h, determine
the minimum acceleration experienced by the passengers.
Find more at www.questionsolutions.com
Book used: R. C. Hibbeler and K. B. Yap, Mechanics for engineers - dynamics. Singapore: Pearson Education, 2013.

Пікірлер: 28
@martin00114
@martin00114 Жыл бұрын
Well said!, This is way I enjoy your videos.
@QuestionSolutions
@QuestionSolutions Жыл бұрын
Thanks!
@jhfghrt1918
@jhfghrt1918 4 жыл бұрын
Thank you very much!
@QuestionSolutions
@QuestionSolutions 4 жыл бұрын
You are very welcome! :)
@engineerinie
@engineerinie Жыл бұрын
Thank you
@QuestionSolutions
@QuestionSolutions Жыл бұрын
You're very welcome!
@martin00114
@martin00114 Жыл бұрын
To find maximum acceleration could we also differentiate by y? and how did you know to differentiate by x to find minimum acceleration?
@QuestionSolutions
@QuestionSolutions Жыл бұрын
No, it depends on which curve you want to work with. To get maximum, we need to use the y-distance where as to get the minimum, we need to use the x-distance. It's based on the curve. So the 40m section gives you more acceleration because it's a shorter curve, and vice versa.
@raheemullah8060
@raheemullah8060 4 жыл бұрын
sir, when we were given the value of a and b then why you take a long method for finding the minimum acceleration...?
@QuestionSolutions
@QuestionSolutions 4 жыл бұрын
In case someone doesn't know how to do it the long way. At the end of the video, I also show the short method :)
@aimanjamil5454
@aimanjamil5454 3 жыл бұрын
how we suppose to get the rho=40^/60? as if we substitute the value of y to the dy/dx and d^2y/dx^2, the answer is undefined.
@QuestionSolutions
@QuestionSolutions 3 жыл бұрын
I am not too sure I understand your question but from what I understand, you're trying to use 60/40? If you want to use the opposite, you need to retake the derivative with respect to x instead of y.
@aimanjamil5454
@aimanjamil5454 3 жыл бұрын
@@QuestionSolutions thanks. I appreciate that
@rehanamjad2855
@rehanamjad2855 Жыл бұрын
Brother in question they askedfor minimum acceleration but u answer maximum. Am i right?
@QuestionSolutions
@QuestionSolutions Жыл бұрын
No, this is the minimum since we used the larger radius of curvature. Using the smaller one would give you the maximum.
@rehanamjad2855
@rehanamjad2855 Жыл бұрын
Sorry brother my mistake. You are right
@QuestionSolutions
@QuestionSolutions Жыл бұрын
@@rehanamjad2855 No need to apologize, it was a good question. Best wishes with your studies!
@dartrixs753
@dartrixs753 Жыл бұрын
Prhne lg gya ha rehan.
@rehanamjad2855
@rehanamjad2855 Жыл бұрын
@@dartrixs753 kha bat ha saif
@oximeter_x20a
@oximeter_x20a 4 жыл бұрын
why is there no tangential acc.?
@QuestionSolutions
@QuestionSolutions 4 жыл бұрын
It's assumed that the cars are moving at a constant speed of 60km/h since they are following the speed limit. Usually, the question will give a tangential acceleration or say something to hint at it.
@oximeter_x20a
@oximeter_x20a 4 жыл бұрын
@@QuestionSolutions Thank you sir. Your format is really helpful, would u consider teaching mechanical enginerring topics like heat transfer or thermodynamics in the future? When I looked at ur subcribed count i was shock this is a small chanell, its underated. Keep it up sir!
@QuestionSolutions
@QuestionSolutions 4 жыл бұрын
You're very welcome. I will definitely consider the topics you mentioned, I hope to do a lot of topics over time. Your kinds words mean a lot, many thanks :) Best of luck with your studies!
@Yuzze.official
@Yuzze.official 3 жыл бұрын
why is it sir my answer is -90 ?
@QuestionSolutions
@QuestionSolutions 3 жыл бұрын
I have no idea 😅 It's not possible to say, did you follow the steps I showed?
@koopakid3102
@koopakid3102 3 жыл бұрын
Where did the formulas for roh come from, with b^2/a or a^2/b?
@QuestionSolutions
@QuestionSolutions 3 жыл бұрын
The first half of the whole video is basically deriving it. I am unsure what you are asking here, sorry.
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