Concentration and Molarity: The Key to Chemical Solutions

Concentration and Molarity. Mr. Causey discusses solutions, dilutions, and concentration. Mr. Causey shows you how to perform molarity calculations and use molarity to create specific dilutions.
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Molarity - 2:38
Dilutions - 5:32
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Mr. Causey discusses solutions, dilutions, and concentration. Mr. Causey shows you how to perform molarity calculations and how to use molarity to create specific dilutions. Solutions are homogeneous mixtures of a solute in a solvent. Concentration is the amount of solute per solvent or solution. Molarity is moles of solute per liter of solution.
#mrcausey #yourchemcoach #molarity

[@idcemail123]

Great explanation. The Dilution explanation nailed it for me thanks a lot.

[@mrcausey]

You're welcome. Thank you so much for taking the time to comment. It is greatly appreciated.

[@laurancehagan3338]

This was pretty helpful. It probably would have been better to watch it sooner than the night before my chemistry test but...c'est la vie

[@mariahsearle5692]

Laurance Hagan me rn😭😂

[@alchemists4443]

M eee

[@ddeul6551]

The cycle continues

[@TaylorGabaldon]

Probably the most professional educational video I've every watched. 10/10 would recommend!

[@captainvhagar9953]

Amazing video For the first time someone explained the calculations so clearly. Thank you, Mr. Causey!

[@woojoonsong5448]

Thank you Mr. Causey Your video helps me a lot to take chemistry class in school!

[@wynstontacheny9639]

In the dilution example he kept saying V1 would be how much water you would need to add. That volume is actually the volume of the 18M solution that you would need to remove to add water to until you reached the 3.0 L At the end when he finished the calculations he did restate it that way, but it was a bit confusing because before he said it was how much water you needed to add. He got it right in the end, but the inconsistency made it harder to understand.

[@finziefiasco]

Amazing! Very straightforward! Thanks!

[@ramaniramanijamal0128]

I have be so confused on how to calculate but now that I watch this video everything have become simple I say God bless u for your hard work

[@helenraine594]

I'm really struggling in this area for my exam in less than 2 weeks. This helps thank you.

[@diennawillis7676]

This video did a great explanation from start to finish!

[@mrcausey]

Thank you so much for the kind comment.

[@tsvietochek]

Mr. Causey, thank you sooo much for the video, your explanation is so clear and practical! You can't imagine what i went through in my school trying to solve problems with dilution. Thank you

[@mrcausey]

You're welcome. Thank you for the great feedback!

[@soccerismylife514]

you help me understanddd so much better!

[@camblank6283]

You realy help me. And I understand from you much more than my Instructor.

[@mrcausey]

Thank you for watching and commenting.

[@juanitaarbelo5409]

Thanx so much, You have helped me a lot!

[@timothydanieljayson6925]

THANK YOU! THANK YOU SO MUCH! Thanks to you I could probably pass my midterm in chemistry!! May God bless you!! :)

[@xx2ol753]

Clyde Walker how old r u

[@schmoovin2915]

i are 12

[@moisesvargas635]

Very good, you help me a lot, thank you very much

[@ellesrevisionsession]

Nice break down. Thanks

[@marcusandersson2990]

thanks this really helped, please keep doing these

[@garikatabecco]

Wow! I'm nothing to do with chemistry and just got to know what is molarity and that it's not the same with molecular weight! But now I understand how to do that! Thank you so much! Syperb lesson!

[@mrcausey]

You're welcome. Thank you so much for taking the time to comment. It is greatly appreciated.

[@jfaparra5803]

It helped me review my Chemistry. Thank you Mr. Causey! :D

[@mrcausey]

JF Aparra You're welcome. Thank you for watching and commenting.

[@mohammedhafeez1493]

Amazing explanation!

[@nditoxin]

God Bless you Mr Causey !!!!

[@iraqiman1854]

Mr.Causy you are great, keep doing more videos, i like your way of explanation

[@ALittleBitOfHotchPotch]

Thankyou this was really helpful 👍

[@dineshrai2658]

very nice sir......... thank u soo soo much for making video for us.......

[@Gigibean7]

This video helped me so much!!!!!! Thank you very very much.

[@mrcausey]

+Gianna You're welcome!

[@nakatokaren505]

8 years later and this is very much useful. Thanks

[@mrcausey]

You're welcome. Thank you for watching and commenting.

[@ChanhNguyen-ye1tf]

thank you so much!!

[@rchavez5184]

To the blackboard! Thank you for helping and taking the time to make this video easy and understandable for everyone!

[@mrcausey]

+R Chavez You're welcome. Thank you for taking the time to comment.

[@stephengevanni8315]

Thank you so so much!!! The only thing I don't seem to understand is why you have the same number of moles of solute in both solutions. Can you please explain the M1V1=M2V2 part? Thank you!

[@ONExANDxONLY]

Thanks a lot, saved about 4 hours time. made things so simple.

[@mrcausey]

You're welcome! Thank you so much for watching.

[@SeichoBlossom]

Omg, thank you! Lmao @ "plug and chug dat" :') Lmfao I was about to cry cause I didn't get molarity. And you were the only channel who didn't just GIVE the moles/gram, you actually gave every formula to get to the next step. Thanks alot.

[@mrcausey]

You're welcome. Thanks for the feedback.

[@lilnoot7335]

thank you so much this helped me a tremendous amount!

[@mrcausey]

+Emily Filaseta You're welcome. Thank you for watching and commenting.

[@akshintl5025]

god bless u.... gr8 explanation love n respect from India

[@mrcausey]

Thank you so much!

[@lihkin1000]

this video actually really helped...

[@ravindramalusare2383]

Sir , when you do dilution what exactly changes ? moles of solute remain same ,so concentration of what decreases ,and please clarify whats concentration

[@panico5872]

Than you for the great explanation!! You just saved me

[@mrcausey]

You're welcome! Thank you so much for watching.

[@baqirqadri6752]

thanx for this vid helped with my science test

[@GravesMRA]

This really happened me out. It also helped that you sound like Marty McFly a lil bit and I love Back To The Future.

[@mrcausey]

Thank you for the comment. BTW Marty sounds like me.

[@EstefaniaD1029]

Thank you, It really helped me a lot! =)

[@dineshrai2658]

thankss for reply sir....... u r soo good

[@gabriellobo3456]

Thank you Mr. Causey

[@mrcausey]

You're welcome!

[@0016mohit]

thank you VEry much :) !!

[@ComandaKronikk]

Thanks Mr Causey! You tha man!

[@mrcausey]

You're welcome. Thank you for watching and commenting.

[@dannicatherine324]

You are literally the best 😭😭😭

[@123lebornjames]

much love thank you!

[@mrcausey]

You're welcome! Thank you for watching!

[@FounderPilot]

Thank you Mr Causey! You are such a great teacher! ":)

[@mrcausey]

+Serene Amour Thank you for taking the time to comment. It is very much appreciated.

[@JihadAlAnsari]

Thank you this is awesome

[@mrcausey]

You're welcome. Thank you for watching.

[@mehdee3415]

Thanks a ton !

[@mrcausey]

+Mehedi Hasan You're Welcome.

[@nodyesmail2915]

if you please, can you explain how to detect acidic and basic radicals ?

[@jackleek3916]

Thanks

[@infiniworls8340]

thank u! :)

[@sugams2s]

Aaaaaaand Subscribed!

[@irfanmalik-cu3db]

Very nice sir thanks a lot!

[@mrcausey]

irfan malik You're welcome!

[@markkeith9055]

I used to have trouble finding the solution to solutions until I figured out the solutions to a solution. Solute!!

[@hajarqaid]

thank you so much

[@mrcausey]

+Hajar Qaid You're welcome!

[@syafiqhariz13]

I have a question Mr.Causy. A 15.00ml of potassium nitrate was diluted to 125.0 mol and 25.00ml of this solution were then diluted to 1.000 X 10^3 ml. The concentration of the final solution is 0.00383 M. Calculate the concentration of the original solution.

[@dineshrai2658]

again........ thánkss a lotttt

[@mrcausey]

You're welcome.

[@nicholasrowe771]

muy bien

[@RainbowEssence-c3w]

Thanks for this video, it's very helpful! I am a bit confused though, when you dilute something are you not increasing the volume by adding more solvent? So shouldn't M1 not equal M2, since their volumes would be different after you dilute M1 into M2?

[@mrcausey]

You're right M1 doesn't equal M2. M1V1 = M2V2 Thanks for watching.

[@phoenixplayz5071]

tq for your help

[@mrcausey]

You're welcome! Thank you for watching!

[@bvenkat8660]

Which book refer to learn molarity and another solution conc

[@MrVcmafira]

Thank you

[@mrcausey]

You're welcome!

[@chuchi5020]

hi...can you please teach me how to solve molarity given the percent by mass of solute and density of solution?...thanks.

[@honestmujahid]

Can have a normality problems sir

[@yathatisgood]

Hi there. I want to dilute sodium hypochlorite 5%/1litre to 1.5%/1litre but I m struggling with the maths. Could you please write down your workings I think the answer is 4 parts water and 1part sodium hypochlorite Kind regards Steve

[@christinesoberano7134]

Do you have any videos on how to calculate molality? I really need it! Please help me!

[@superAmaster]

KZbin is great place.

[@blackhawkX02]

Yeah, practice people, if you don't do that, you'll be here like me, watching this shit over and over and over even if it's not that complicated because you will forget it over and over IF you don't practice...

[@cabdixakiimaxmed4546]

excellent

[@mrcausey]

Thank you!

[@gittapeggy9726]

OMG you are amazing

[@mrcausey]

Thank you so much for watching and the kind comment.

[@jeraldsalvana4245]

how to solve this? mr causey? what weight of limestone containing 23.0%(w/w) Ca must be taken in order to have 750mg of Ca present?

[@rabiusalihu3097]

Perfect

[@mrcausey]

Thank you.

[@lolhoney123]

Mr. Causey may i please get some help. i used your method and i understood it but in this question... 9 g of glucose (C6H12O6, RMM = 180 gmol-1) is dissolved in 50 ml of water. This solution is then added to 100 ml of water to give Solution A. 10 ml of Solution A is added to 90 ml of water to give Solution B. What is the final concentration of glucose in Solution B? ...i struggled and couldn't get the answer right. (by the way it the answer is 33mM) please help me.

[@bkpandey7191]

Hello sir, I want to ask you a question. Basically this question is not from this topic but I'm having problem in this question. The question says, The mole fraction of a soluble in a solution is 0.1. At 298K, molarity of this solution is the same as its molality. Density of this solution at 298K is 2.0g cm^-3 . The ratio of the molecular weights of the solute and solvent , {MW of solute}/{MW of solvent} is.

[@mototsumi]

have a question to answer calculate the concentrstion of caffine in the two samples however i only have grams for the known so am unsure as to what to do

[@mrcausey]

The amount of solute doesn't change usually in a dilution the amount of solvent does.

[@vandam7656]

What word were written on the display which viewed by viewers is obsecure what transprance under which calculation were done under

[@Alex-jk9pq]

Thanks fam

[@mrcausey]

You're welcome! Thank you so much for watching.

[@Mendorich1]

I have a chem question. How would you determine which solution has higher concentration for example. 200.mL of 1.50 M NaCl solution And 150. mL of solution containing 24.0 g of NaCl

[@mrcausey]

Change the 150 ml to liters, then change the 24.0 g to moles and divide the moles by the liters.

[@h00015788]

thanks

[@mrcausey]

+ibrahim ali You're welcome.

[@johncook9331]

scientist have quantitative terms quantitative means measurable but in what terms

[@zakmatew]

How would I dilute 6% of NaClO to 0.005% NaClO? Should I use the same formula you gave here?

[@mrcausey]

Zak Matew It is similar but deals with percent by mass not molarity.

[@CB-cx8ty]

Mr Causey, You are an awesome teacher! I will follow you from this day forward! C :)

[@mxddy_goofy]

thx u

[@mrcausey]

You're welcome.

[@lepetite7332]

I want to ask something. supposed I want to make a phosphate solution form KH2PO4 anhydrous. to a phosphate solution of 300mg/L should I just ad 0.3 gram of KH2PO4 into a liter of DI water or I have to do some calculation?

[@mrcausey]

If you are considering the phosphate only, remember the phosphate is only about 70% of the mass. Thus, you must calculate how much KH2PO4 would contain .300 g of PO4.

[@brittanyolson8532]

Hi, I need help with a question and am having a hard time finding a similar example online. I would really appreciate some help, or at least a bit of a direction. I have solved for the molarity of the NaCl solution, but not sure where to go from here. Thanks! A student dissolves 1.246 g of sodium chloride into 500.0 ml of water. That solution is then mixed with 300.0 ml of a 0.100 M sodium carbonate solution. What is the concentration of sodium ions in the final (mixed) solution.

[@mrcausey]

Try M1V1=M2V2

[@shonithraj5383]

can you please make videos on molality, normality and other concepts involved in concentration.

[@mrcausey]

Those topics are coming soon.

[@shonithraj5383]

thank you

[@mrcausey]

Molality is up.

[@shonithraj5383]

Mr. Causey thank you

[@anushkakumari8010]

Like from India 😍😍

[@sameermkaladagi9977]

Calculate the molarity solution of methanol in 1 litre of water in which of the mole fraction of methanol is 0.5

[@Vitality_Chiropractic]

How does Avagadro's number fit into all of this??

[@mrcausey]

Well, molarity is based on moles per liter and the mole is any Avogadro's number of something.

[@denisskenderovic3707]

I have an issue. How do I calculate the concentration of ions specifically ? The problem says "Calculate the molarity of all ions in a solution of barium-hydroxide, which has a molarity of 0.01mol/dm3. It's a full dissociation". Please help me :( .

[@mrcausey]

+Denis Skenderović The equation would be Ba(OH)2 ---> Ba 2+ + 2 OH - The ratio would be 1:1:2 Thus .01 M Ba(OH)2 will dissociate into .01 M Ba 2+ and .02 M OH-

[@denisskenderovic3707]

Oh, THANK you ! I must say I didn't really expect such a quick respond, but I'm positively surprised. This helped me deal with a lot of equations similar to this one. Thank you a thousand times Mr. Causey ! :)

[@mrlogicalism4799]

good though

[@tastytunaroll2784]

Do you sell Mr. Causey shirts

[@Punsmash]

How would i solve this? calculate the molarity of a solution prepared by dissolving 28.8 g of sodium hydroxide in water to make 500ml of solution

[@mrcausey]

+Sarah Nemetalla Well, remember that molarity is moles of solute per liters of solution. Thus, you must change the grams to moles using molar mass and then divide the moles by .500 L. The molar mass of NaOH is 40 g per mole.

[@Punsmash]

+Mr. Causey Oohhh i kept diving by 500ml and getting a weird answer. Thank you so much youre the best!

[@mrcausey]

+Sarah Nemetalla You're welcome.

[@abdallatalhamy8025]

How I can solve this? :how would you dilute the 6.0 M Nitric acid in order to get 400 mL 2.5 M nitric acid solution ??

[@mrcausey]

+abdalla Talhme M1V1 = M2V2 change the 400 mL to .400 L and get (6 M) V = (2.5 M) (.4 L) V = (2.5 x .4)/6 V = .167 L or 167 mL Start with 167 mL and add water to 400 mL

[@abdallatalhamy8025]

+Mr. Causey thank you

[@sergiocartagena6634]

How many grams of NaOH are needed to prepare 3.500L of a solution that is 0.250M? Plz help me!!!!

[@WhatchaTakinBout]

Sergio Cartagena 34.99grams of NaOH

[@sergiocartagena6634]

WhatchaTakinBout thanks"but i already failed this chapter.

[@HighPerformanceManagement]

you said concentration is solute/ solution or solvent? wouldn't it just be solute/solution? if not when would you use solution or solvent

[@mrcausey]

It can be either one. Molarity is moles of solute per liters of solution, but molality is moles of solution per kg of solvent.

[@HighPerformanceManagement]

ahh thankyou for that clarification :)

[@mrcausey]

You're welcome.

[@dineshrai2658]

sir....... where r u from???

[@mrcausey]

The United States. Texas.

[@shennonfernando8236]

do your calculations slowly plz

[@cookiezncreme9473]

You already know who this is

[@user-fs3wz8hw9k]

This is a good video but is not very followable due to the overuse of "M". It would be much clearer to use another letter or symbol to represent molarity.

[@mrcausey]

Sorry, but "M" is the official representation for molarity. Thanks for commenting.