Convolution Operation (Shortcut)

[@CenterOfAttention-l3c]

Nice... Thank you! I used this property for my homework.

[@glenthabang6411]

there's a special place reserved for you in the after life sir.

[@harshikhachandra801]

Thank you so much sir for such an interesting shortcut...it saves lot of time😇✨

[@BhavikRaghav14905]

Thanks a lot sir!!! You are really helping me with my studies and I am so grateful to you Jai Siya Ram

[@lakshyakhandelwal1091]

I love it

[@vandanakhairnar5151]

Great lectures...👍👍👍

[@sankarpanda1494]

Thank you

[@demetriusbosket]

Do these properties work for continuous and discrete cases?

[@yagzyalcntas553]

Thank you, people are doing videos with both T's are 1 and A's are 1 which i did a question wrong last year. Now i am taking a similar course and now i know how to do it. Thanks again.

[@estefaniac8260]

Wow! You are awesome, thank you so much for this video, it totally helped me understand this concept. Thank you!!!! :)

[@lovisharora7604]

At 5:55 the height depends on the value of both A1 and A2 whichever is smaller that should only get mutilplied by T1. If we assume A2>A1then height should be A1*T1

[@vijay-pv8sr]

Sir when I applied shortcut x1(t)*x2(t) is not equal to x2(t)*x1(t).. Property 1 isn't getting satisfied. I mean when x2(t)*x1(t) T2 becomes T1 right.,& also amplitude (height) =A1À2T1 is also differing from first case. Kindly explain

[@ayushagarwal69]

umm , I think we need to take the time period which is lesser , and not the time period of the one on the left

[@marydeepthijoseph9560]

If x1(t) interval is between -3 to 3 then T1= 0 ..is the amplitude is 0*amplitude

[@udayrajvashishtha6741]

MARY DEEPTHI JOSEPH duration is 6

[@kumarayushmittal2099]

best

[@pradeepbhambhoo8941]

if we have two triangles of same width what would be the convoluted wave,like these shortcuts.

[@amittak8135]

It is not shortcut we can get amplitude of trapazoidal by equal area property.

[@amitghosh3938]

sir why you multiplieng t1 to A1 and A2 why not only A1 multiply A2

[@dbss206]

We are integrating two signals. Formula is integration of x(k)*y(t-k) dt. Right?. Above problem can be further expanded into three parts. You solve them. You ll get these results

[@dbss206]

For example say t > T1 and t

[@amitghosh3938]

@@dbss206 , i am very thankful to you as you have cleared my doubt and helped me getting the point. thanks for your effort brother.

[@bosstriples9986]

Sir, I want to know the source from where you get this shortcut.

[@syedmuhammadghufran358]

Why isn't the height of the trapezoid equal to A1T1??

[@prabhakardas4261]

can you solve atleast one applications of this shortcut method where the starting point is not at origin,it is somehow at negative side,and the ending point is at positive side??

[@prabhakardas4261]

Neso Academy thank you sir, once again thank you, you helped me a great.....

[@estefaniac8260]

Thank you so much, I needed exactly this. :)

[@agaranvel]

Tq🙏🙏🙏🙏🙏🙏

[@Monugupta-qd9ud]

Sir in previous video ..u hav taken A1×A2×T1=1.....sir 2 hona chahiye n

[@jmounikareddy3558]

What is the reference link for the proof sir

[@adibmd.ridwan]

I see this video in 1.5 speed 😁😁😁

[@ahamethaathil2001]

I see this video in 2x speed 😂

[@ajithuddavolu2683]

Me in 4× 😂

[@renukanellaturu4610]

thank you

[@marydeepthijoseph9560]

If x1(t) interval is between -3 to 3 then T1= 0 ..is the amplitude is 0*amplitude

[@mdsamsadalam4089]

No !here you will have T1 = 3- (-3)=6