Diffraction at a single slit

[@CSFAKASHS]

small info see the video in 1.5x speed

[@xenderxender5233]

Really worth it

[@jashwanthsekar6635]

Thank u brother

[@Grind_and_grow]

2x

[@nawazkhokhar7726]

In single slit diffraction if the width of slit is equal to the wavelength of light then. A. Half screen become bright. B. First maximum fill the entire forward hemisphere. C. First minimum fill the entire forward hemisphere. D. Its not possible.

[@manaliratnoji6202]

D. It's not possible

[@abhisoni7111]

Why there is a pie phase difference when wavelets from A and C will arrive at P

[@dhruv-194]

Phi = (2π/lambda ) * ∆x Hence if you put ∆x (phase difference) = lambda/2 Then phi =π hence the phase difference=π and cancel eachother out

[@JeevanSamagar]

This is explained by Franhauffor

[@Divya268]

What are applications of diffraction at single slit experiments

[@hellonepp]

Won't the use of lens creates a phase different between the rays( say top ray and bottom) one at point 'O'? . I think so because the top ray has to travel more distance than bottom one(you can clearly see it, top ray is travelling along hypotenuse and bottom is along the base).

[@Rafi74571]

What will happen if strips 1& 2/3/4 interfere??why you consider only 1&11/2&12??

[@VidyaNidhiCareerCounseling97]

nice video sir

[@bcveeramani4258]

Then what will light from b point happen

[@prabhushankargite5873]

But diffraction is not at pt. C

[@arpitasingh5834]

How i know that the path difference between A and C is lambda/2

[@amisharajbanshi1662]

Yes..I was also wondering about it

[@ishabhadula2504]

Because AB has a path diff of lambda and since C is the midpoint of AB, the path diff will also be halved. Thus, giving lambda/2 as the path diff between A and C.

[@mustansirhussain4927]

@@amisharajbanshi1662 why ab have p. D lemda

[@jkss8]

​@@ishabhadula2504where should we find path difference is it any condition to find it sis

[@rashmidhalkari4449]

Nice video.. 👍

[@grose4058]

All wrong i am afraid. . The pattern is produced by interaction between the light passing thru the blades of the slit and the light being absorbed and reradiated through the blades, either in or out of phase.. . In an opaque solid blade the patterns cancel out. The slit interferes with the complete cancellation of the thru wave and the rerqdiated wave....the total opposite to how it is taught... Please check oyt the Feynman Lectures...

[@sateeshprathapani4608]

its a bit confusing, you dont need a lens in between the slit and the screen.

[@abhaadhikari809]

yes same i was confused by it too

[@labskhokhar8016]

This is because the rays are parallel and for them to finally meet, it will take a lot a distance. By using a convex lens we can make them meet at a near point.

[@hellonepp]

​@@labskhokhar8016 but won't the use of lens creates a phase different between the rays( say top ray and bottom) one at point 'O'. I think so because the top ray has to travel more distance than bottom one(you can clearly see it, top ray is travelling along hypotenuse and bottom is along the base).

[@chekkoslovakya5610]

Lots of error seen

[@munmunbasak8106]

Chalega

[@Sunrise5245]

😅😍😍😍amazing.m

[@surajmehra4442]

Ya really its Amazing

[@raeesalam5066]

Nice

[@alkkabenny2485]

So helpful

[@rajeevarghese7722]

worth 4 mins

[@PardeepKumar-my9hi]

thank you sir..it helped..

[@Rahulsingh-ib6ic]

Kaun kaun india se hai

[@DrSwati-wb3vd]

superb video . Any guy can understand it easily .

[@ajitmaurya8247]

thanks sir

[@sccm100]

Jesus Christ I fucking hate Physics 2

[@akmdgaming4740]

Abe Hindi main video banane main kuch jata hai kya😡

[@shinushaleela8896]

😊😊