EVERY Physics Student!!!

[@parellax]

bro gave the most easy ass question ive seen in my life and talking like its hard

[@alexanderbrucegill8091]

Maybe it’s for younger audience

[@parellax]

@@alexanderbrucegill8091 anyone below the age of 14 will not need to or even have kinematics in their curriculum including these formulas, unless theyre preparing for some olympiad, in which case theyre smart enough to understand basic concepts like this. more over even if there was somehow a 6 year old learning this for non olympiad preperation purposes then they wouldnt be called a "physics student" as at that age there will only be a science subject including all parts of science. so there was basically, 0 use of this video

[@alexanderbrucegill8091]

@@parellax bro I’m only 10

[@andrewwhite9302]

@@parellaxholy nerd chill tf out. Sorry not everybody is a god like you apparently

[@Em240Braho]

I 13 in physics and my head bald from all the scratching since it's beginning of the year

[@LethalBS]

Yes guys we can also solve this through energy conservation. If we're to take the whole motion without directing any axis the equation would be: *1/2mV₀²+mgh = 1/2m(V₀cosθ)²+mg(hmax)* ~(V₀cosθ because at the maximum point there would be only x-velocity vector directing)~ For a specific direction like the y-axis, the equation would be: *1/2m(V₀sinθ)²+mgh = mg(hmax)* ~(No factor of kinetic energy in RHS because there is no velocity in the y-axis direction at max point)~ Hope y'all understood it!

[@jamesrocket5616]

At maximum height, h max: vf = 0 (standstill on mid-air) a = -9.81 m/s² vf² = (vi(sinx))²- 2gh 0² = (16sin70°)² - 2(9.81)(h) h = 11.522m (from top of building) h max = 10m + 11.522m h max = 21.522m

[@RohitKumar-ql2oo]

How to make easy questions complicated ahh video

[@chanda7352]

v²-u² = 2as

[@reloadedditto]

I find your lack of significant digits disturbing

[@Life123love1]

Show us how to derive the equation

[@its_puggy_pugster8469]

Kachow, what an insightful video I just watched from the mastermind Nicholas GKK , my mind grew at the sight of an upload 😜

[@agriya7930]

Can be solved using u²sin²70°/2g +10m which is approx 21.9m

[@oglothenerd]

I love this channel!

[@God_d_ussop]

haha your this short made me do a physics problem while i was chilling really love the occasional test ❤

[@SaktLonda-f2t]

There wasn't the angle and initial velocity given. I thought it was about them😂😂

[@painf4l]

I just draw v/t graph

[@user-wssuuu]

What about on a slope

[@Wagonwheezer]

What the formula to solve for the highest point in a parabola in ax^2 + bx + c = 0?

[@brownfamily1892]

This would be formula for the vertex of a parabola tbh I forgot the formula 😭 but it's on the internet

[@Wagonwheezer]

@@brownfamily1892 I was thinking b^2/2a or smth along the line of that - my search engines are having a problem at the moment that’s why I asked but thanks anyways king 👑

[@tilekt4248]

Why don't you use the timeless distance formula?

[@SpiffyLionzz-sr2vx]

So can't you just indovidually change the equation to include the initial height?

[@Cyrusislikeawsome]

You want to teach your pupils a formula for every situation?

[@somerandomboi8239]

How should it be done then? I'm 13 just started please help

[@kikilolo6771]

where does the first equation come from ?

[@kikilolo6771]

Ah I get it we calculate the initial velocity on the vertical axes and the use conservation of energy

[@Mustafa_Shahzad]

Yeah, no disrespect intended, but he always just says that it's some high level physics and then just does a video of plugging in numbers into a formula. Id much prefer a derivation, because that's actually physics, not just simple maths.

[@its_puggy_pugster8469]

@@Mustafa_Shahzadyou have a face even a mother can’t love, I can tell by your name you’ve never been within 4 feet of a women, next time I have a question about being a lonely middle aged failure I’ll come straight to you! 🥰

[@repulse_wkey4432]

If u a=10 you’ll get 22.8

[@linkmastr]

Or we use the algebra 1 formula and find the vertex

[@Elsonlianneihguk]

Quadratic?

[@wilurbean]

Not really, find the time to apogee, then go from there. No assumption

[@macsnafu]

Is this a physics problem, or a puzzle?

[@behjani1]

Age?

[@alithemathguy]

You don’t even need the angle, mv^2/2 + mgh = mgH

[@shash321]

No. It will still have kinetic energy on the peak. U still need angle to calculate the x component of velocity

[@Terminator90782]

No mass given and there will kinetic energy

[@davidsaomi6493]

@@Terminator90782Both sides can be divided by mass so it goes away, but yeah it wont work anyway unless its adjusted to be v in y-direction and such

[@behjani1]

Marriages

[@teainnit27]

My guy, you didn't teach / explain a single thing in this video beyond "uhhhh use formula".

[@themodestai9603]

just use work energy theorem

[@ChadBeetle]

pretty sure they’re still on kinematics

[@krisharma69]

there's no need for work energy theorem here

[@ehudkotegaro]

Where exactly is this angle supposed to be..

[@SirBeYou]

"70⁰ Angle. Find Max Height."

[@ehudkotegaro]

Yes I know how big the angle is supposed to be. Where is it in the drawing?​@@SirBeYou

[@Termlz]

@@ehudkotegaro There is no angle it's made up

[@MuffinTheMicrobiologist]

@@Termlzth?

[@daanskiel1236]

@@ehudkotegaro The angle between ground level and the direction of the starting velocity.

[@atomgutan8064]

What the fuck is that formula for maximum height?? Please, people do not memorize that formula, you can very very easily derive it from conservation of mechanical energy.

[@MeghdadRezaei-ge9hi]

You did best sir teacher can I send easier way to solution than your way of it’s possible ? Do not think I’m rood